Uses of destructor = delete; - c++

Question

Consider the following class:
struct S { ~S() = delete; };
Shortly and for the purpose of the question: I cannot create instances of S like S s{}; for I could not destroy them.
As mentioned in the comments, I can still create an instance by doing S *s = new S;, but I cannot delete it as well.
Therefore, the only use I can see for a deleted destructor is something like this:
struct S {
~S() = delete;
static void f() { }
};
int main() {
S::f();
}
That is, define a class that exposes only a bunch of static functions and forbid any attempt to create an instance of that class.
What are the other uses (if any) of a deleted destructor?

Answer 1

If you have an object which should never, ever be deleted or stored on the stack (automatic storage), or stored as part of another object, =delete will prevent all of these.
struct Handle {
~Handle()=delete;
};
struct Data {
std::array<char,1024> buffer;
};
struct Bundle: Handle {
Data data;
};
using bundle_storage = std::aligned_storage_t<sizeof(Bundle), alignof(Bundle)>;
std::size_t bundle_count = 0;
std::array< bundle_storage, 1000 > global_bundles;
Handle* get_bundle() {
return new ((void*)global_bundles[bundle_count++]) Bundle();
}
void return_bundle( Handle* h ) {
Assert( h == (void*)global_bundles[bundle_count-1] );
--bundle_count;
}
char get_char( Handle const* h, std::size_t i ) {
return static_cast<Bundle*>(h).data[i];
}
void set_char( Handle const* h, std::size_t i, char c ) {
static_cast<Bundle*>(h).data[i] = c;
}
Here we have opaque Handles which may not be declared on the stack nor dynamically allocated. We have a system to get them from a known array.
I believe nothing above is undefined behavior; failing to destroy a Bundle is acceptable, as is creating a new one in its place.
And the interface doesn't have to expose how Bundle works. Just an opaque Handle.
Now this technique can be useful if other parts of the code need to know that all Handles are in that specific buffer, or their lifetime is tracked in specific ways. Possibly this could also be handled with private constructors and friend factory functions.

Answer 2

one scenario could be the prevention of wrong deallocation:
#include <stdlib.h>
struct S {
~S() = delete;
};
int main() {
S* obj= (S*) malloc(sizeof(S));
// correct
free(obj);
// error
delete obj;
return 0;
}
this is very rudimentary, but applies to any special allocation/deallocation-process (e.g. a factory)
a more 'c++'-style example
struct data {
//...
};
struct data_protected {
~data_protected() = delete;
data d;
};
struct data_factory {
~data_factory() {
for (data* d : data_container) {
// this is safe, because no one can call 'delete' on d
delete d;
}
}
data_protected* createData() {
data* d = new data();
data_container.push_back(d);
return (data_protected*)d;
}
std::vector<data*> data_container;
};

Answer 3

Why mark a destructor as delete?
To prevent the destructor from being invoked, of course ;)
What are the use cases?
I can see at least 3 different uses:
The class should never be instantiated; in this case I would also expect a deleted default constructor.
An instance of this class should be leaked; for example, a logging singleton instance
An instance of this class can only be created and disposed off by a specific mechanism; this could notably occur when using FFI
To illustrate the latter point, imagine a C interface:
struct Handle { /**/ };
Handle* xyz_create();
void xyz_dispose(Handle*);
In C++, you would want to wrap it in a unique_ptr to automate the release, but what if you accidentally write: unique_ptr<Handle>? It's a run-time disaster!
So instead, you can tweak the class definition:
struct Handle { /**/ ~Handle() = delete; };
and then the compiler will choke on unique_ptr<Handle> forcing you to correctly use unique_ptr<Handle, xyz_dispose> instead.

Answer 4

There are two plausible use cases. First (as some comments note) it could be acceptable to dynamically allocate objects, fail to delete them and allow the operating system to clean up at the end of the program.
Alternatively (and even more bizarre) you could allocate a buffer and create an object in it and then delete the buffer to recover the place but never prompt an attempt to call the destructor.
#include <iostream>
struct S {
const char* mx;
const char* getx(){return mx;}
S(const char* px) : mx(px) {}
~S() = delete;
};
int main() {
char *buffer=new char[sizeof(S)];
S *s=new(buffer) S("not deleting this...");//Constructs an object of type S in the buffer.
//Code that uses s...
std::cout<<s->getx()<<std::endl;
delete[] buffer;//release memory without requiring destructor call...
return 0;
}
None of these seems like a good idea except in specialist circumstances. If the automatically created destructor would do nothing (because the destructor of all members is trivial) then the compiler will create a no-effect destructor.
If the automatically created destructor would do something non-trivial you very likely compromise the validity of your program by failing to execute its semantics.
Letting a program leave main() and allowing the environment to 'clean-up' is a valid technique but best avoided unless constraints make it strictly necessary. At best it's a great way to mask genuine memory leaks!
I suspect the feature is present for completeness with the ability to delete other automatically generated members.
I would love to see a real practical use of this capability.
There is the notion of a static class (with no constructors) and so logically requiring no destructor. But such classes are more appropriately implemented as a namespace have no (good) place in modern C++ unless templated.

Answer 5

Creating an instance of an object with new and never deleting it is the safest way to implement a C++ Singleton, because it avoids any and all order-of-destruction issues. A typical example of this problem would be a "Logging" Singleton which is being accessed in the destructor of another Singleton class. Alexandrescu once devoted an entire section in his classical "Modern C++ Design" book on ways to cope with order-of-destruction issues in Singleton implementations.
A deleted destructor is nice to have so that even the Singleton class itself cannot accidentally delete the instance. It also prevents crazy usage like delete &SingletonClass::Instance() (if Instance() returns a reference, as it should; there is no reason for it to return a pointer).
At the end of the day, nothing of this is really noteworthy, though. And of course, you shouldn't use Singletons in the first place anyway.