django - different inlines for different users - django

Question

I have these models
class Office(models.Model):
name = models.CharField(max_length=255)
class User(models.Model):
name = models.CharField(max_length=255)
status = models.SmallIntegerField()
office = models.ForeignKey(Office, on_delete=models.SET_NULL, null=True)
class Inspection(models.Model):
place = models.CharField(max_length=255, null=True, blank=True)
class Jobs(models.Model):
inspection = models.ForeignKey(Inspection, on_delete=models.CASCADE)
inspector = models.ForeignKey(User, on_delete=models.SET_NULL)
cost = models.DecimalField(max_digits=20, decimal_places=2)
I have different users: common users(status=1) and admins(status=2).
Common users can make and see Jobs only with Inspectors from the same office.
Admins can put any user into Inspectors and see all Jobs.
I can filter job list for users in the same office:
class JobAdmin(admin.StackedInline):
model = Job
extra = 0
def get_queryset(self, request):
qs = super(JobAdmin, self).get_queryset(request)
if request.user.status in [1]:
qs = qs.filter(inspector__office=request.user.office)
return qs
class InspectionAdmin(ModelAdmin):
list_display = ['place']
inlines = [JobAdmin]
But how can I add additional filters for editing?
If it was not an inline form I would do it this way:
class JobAdminForm(ModelForm):
def __init__(self, *args, **kwargs):
super(JobAdminForm, self).__init__(*args, **kwargs)
if self.user.status == 1: #common user
self.fields['inspector'].queryset = Inspector.objects.filter(office=self.user.office)
class Meta:
model = Jobs
fields = '__all__'
class JobAdmin(ModelAdmin):
form = JobAdminForm
def get_form(self, request, obj=None, **kwargs):
form = super(JobAdmin, self).get_form(request, **kwargs)
form.user = request.user
return form

Answer 1

Maybe this code will be helpfull:
class JobAdmin(admin.StackedInline):
model = Job
extra = 0
def get_queryset(self, request):
qs = super(JobAdmin, self).get_queryset(request)
if request.user.status in [1]:
qs = qs.filter(inspector__office=request.user.office)
return qs
def formfield_for_foreignkey(self, db_field, request=None, **kwargs):
if db_field.name == "inspector" and request.user.status == 1:
kwargs['queryset'] = Inspector.objects.filter(office=request.user.office)
return super().formfield_for_foreignkey(db_field, request, **kwargs)
P.S. Link to Django documentation: formfield_for_foreignkey