values in class destroyed when getting back to main function c++ - c++

I've got a problem in my code in C++.
I have a class DataStructure that I'm using and and in particular, its method GetAllCreaturesByLevel defined as follow:
Class DataStructure;
StatusType DataStructure::GetAllCreaturesByLevel(int magiID, int **creatures, int *numOfCreatures);
This method receives pointers from the main function and gives back some statistics about the object it is working on.
To use this method from the main function, I call a function that will pass the pointers from the main function, cast the object from void* to DataStructure* and call its method GetAllCreaturesByLevel. This function is defined as follow :
StatusType GetAllCreaturesByLevel(void *DS, int magiID, int **creatures, int *numOfCreatures){
if((DS == NULL)||(creatures == NULL)||(magiID == 0)||(numOfCreatures == NULL)){
return INVALID_INPUT;
}
return ((DataStructure*)DS)->GetAllCreaturesByLevel(magiID, creatures, numOfCreatures);
}
The code works perfectly while in this function. The problem is when coming back to the main: the pointers gives back the right values but all the data in the object are changed and turned to garbage values.
What can be the cause of this bug ?

In the method I was using :
int *creaturesArray = new int[*numOfCreatures];
and to enter the values in the creatures array:
for(int i = 0; i < *numOfCreatures; i++) {
creatures[i] = &creaturesArray[i];
}
The problem is in Assembly. In the return to the main from GetAllCreaturesByLevel, the stack is bigger than when coming into the function and thus DS isn't at the same place in the stack it was before. As result, the value put into DS isn't it's real value but one of the addresses in the creatures array.
The solution is :
int *creatures = new int[*numOfCreatures];
and to return creatures as is, without using another array on the way.

Related

unable to change member value with method

I have an int member named size within my blob class whose value I am attempting to change within a method. Initially, I tried...
void blob::make_union(blob parent_blob){
parent=&parent_blob;
parent_blob.size = parent_size
}
Then I tried making a function whose sole purpose was to change the size value. Its worth noting that it changes the values within the function as verified by some cout statements.
int blob::change_size(int dat_size){
size=size+dat_size;
return this.size;
}
after making the new method change my other method
'void blob::make_union(blob parent_blob){
parent=&parent_blob;
int temp = size;
parent_blob.size = parent_blob.change_size(temp);
}'
still no dice. The following within main function does work.
if (charmatrix[m-1][n-1]==charmatrix[m][n]){
blobmatrix[m][n].make_union(blobmatrix[m-1][n-1]);
blobmatrix[m-1][n-1].size=blobmatrix[m-1][n-1].size + blobmatrix[m][n].size;
What am I doing wrong?
You are passing your blob class by value: you are making a copy of your blob object, and that is what the function change_size is working with.
void increment_number(int i) { ++i; }
void increment_number_ref(int& i) { ++i; }
int main()
{
int n = 6;
// This takes a copy of the number, and increments that number, not the one passed in!
increment_number(n);
// n == 6
// This passed our object by reference. No copy is made, so the function works with the correct object.
increment_number_ref(n);
// n == 7
return 0;
}
You need to pass your blob by reference (or as a pointer) if you wish to modify that object's value: see above.
In languages that have pass by reference and pass by value - if you have a situation where you make a change, and then suddenly the change is 'gone', you're almost certainly passing a copy vs a reference.
Try changing the prototype to pass in the blob by reference.

How can I access a class's member function via an array of pointers?

I have a pretty standard class with some public member functions and private variables.
My problem originally stems from not being able to dynamically name object instances of my class so I created an array of pointers of the class type:
static CShape* shapeDB[dbSize];
I have some prompts to get info for the fields to be passed to the constructor (this seems to work):
shapeDB[CShape::openSlot] = new CShape(iParam1,sParam1,sParam2);
openSlot increments properly so if I were to create another CShape object, it would have the next pointer pointing to it. This next bit of code doesn't work and crashes consistently:
cout << shapeDB[2]->getName() << " has a surface area of: " << shapeDB[2]->getSA() << shapeDB[2]->getUnits() << endl;
The array of pointers is declared globally outside of main and the get() functions are public within the class returning strings or integers. I'm not sure what I'm doing wrong but something relating to the pointer set up I'm sure. I'm writing this code to try and learn more about classes/pointers and have gotten seriously stumped as I can't find anyone else trying to do this.
I'm also curious as to what the CShape new instances get named..? if there is any other way to dynamically create object instances and track the names so as to be able to access them for member functions, I'm all ears.
I've tried all sorts of permutations of pointer referencing/de-referencing but most are unable to compile. I can post larger chunks or all of the code if anyone thinks that will help.
class CShape {
int dim[maxFaces];
int faces;
string units;
string type;
string name;
bool initialized;
int slot;
public:
static int openSlot;
CShape();
CShape(int, string, string); // faces, units, name
~CShape();
void initialize(void);
// external assist functions
int getA(void) {
return 0;
}
int getSA(void) {
int tempSA = 0;
// initialize if not
if(initialized == false) {
initialize();
}
// if initialized, calculate SA
if(initialized == true) {
for(int i = 0; i < faces; i++)
{
tempSA += dim[i];
}
return(tempSA);
}
return 0;
}
string getUnits(void) {
return(units);
}
string getName(void) {
return(name);
}
// friend functions
friend int printDetails(string);
};
// constructor with values
CShape::CShape(int f, string u, string n) {
initialized = false;
faces = f;
units = u;
name = n;
slot = openSlot;
openSlot++;
}
My guess is you use the CShape constructor to increment CShape::openSlot?
You're probably changing the value before it's read, thus the pointer is stored in a different location.
Try replacing openSlot with a fixed value to rule out this CShape::option.
-- code was added --
I'm pretty sure this is the problem, the constructor is executed before the asignment, which means the lhs. will be evaluated after CShape::openSlot is incremented.

Passing integer by reference to a class in c++

I have a thread-class Buffer (own made class), and many derived classes such as BufferTypeA, BufferTypeB...
Since I have to synchronize them in a certain order, I'm giving any of them an integer which represents the order to run certain task. I also have to know inside each thread Buffer which one is next to run the task, so I'm passing every BufferType a reference to an integer which all of them must share and I didn't want to make it Global.
I got lost at any point and I don't see where.
First I create all the BufferTypes from a class where I also define that shared integer as:
int currentThreadOrder;
And when creating the BufferTypes:
int position = 0;
if (NULL == bufferA) {
bufferA = new BufferTypeA(&currentThreadOrder, ++position,
waitCondition);
}
if (NULL == bufferB) {
bufferB = new BufferPos(&currentThreadOrder, ++position,
waitCondition);
}
if (NULL == bufferC) {
bufferC = new BufferRtk(&currentThreadOrder, ++position,
waitCondition);
}
Then, in BufferTypeA header:
class BufferTypeA: public Buffer {
public:
BufferTypeA(int currentThreadOrder,
int threadConnectionOrder = 0,
QWaitCondition *waitCondition = NULL);
//..
}
And in cpp file:
BufferTypeA::BufferTypeA(int currentThreadOrder, int threadConnectionOrder, QWaitCondition *waitCondition):
Buffer(currentThreadOrder, threadConnectionOrder, waitCondition) { }
Now I'll show Buffer header:
class Buffer: public QThread {
public:
Buffer(int &currentThreadOrder,
int threadConnectionOrder = 0,
QWaitCondition *waitCondition = NULL);
//...
protected:
QWaitCondition *waitCondition;
int threadConnectionOrder;
int &currentThreadOrder; // Shared address
}
And finally the cpp:
Buffer::Buffer(int &currentThreadOrder, int threadConnectionOrder, QWaitCondition *waitCondition) {
this->threadConnectionOrder = threadConnectionOrder;
this->waitCondition = waitCondition;
this->currentThreadOrder = currentThreadOrder;
}
And the error I'm getting is error: uninitialized reference member Buffer::currentThreadOrder.
I'm embarrased to ask, because it's going to be a simple problem with pointers and addresses, but I can't see where the problem is, so please help.
When you create a class with a data-member that is a reference, the reference needs to be assigned a value in the constructor initializer list.
References have to be given a value when they are created, they are not pointers. They have to start with a value and that value cannot be changed (while the contents that is pointed to by that value can be changed).
Essentially you can think of a reference as an alias for an existing variable. You can't give a friend a nickname if you don't have a friend :)
RESPONSE TO COMMENT:
You don't "share a reference" between objects. Each object will have its own reference to the same variable. When you "pass by reference" you are telling the compiler that you want the variable in your function to actually be the variable in your outer scope, rather than creating a new variable by value. This means that you only have one variable at one memory location. The reference is just memory in some other place that forwards you to that same memory location.
Think of this as call forwarding... I can have 15 phone numbers in 15 different countries. I can set them all up to forward calls to my cell in the US. So, people are calling me no matter which number they call.
Each of your classes just has another reference to forward the "phone calls" or variable reads/writes to that same memory location. So, you're not sharing a reference between classes, you're making sure that each class HAS a reference to the same underlying memory location.
Back to the metaphore, each class won't have the same phone, but each class' phone will forward to the same number (variable) none-the-less which lets them all set/get the same value in the end.
RESPONSE II:
Here's a simple example to get your head going, it's pretty easy to apply to your classes. I didn't compile it but it should work minus a typo or two possibly.
class A
{
public:
A(int& shared) : m_shared(shared)
{
//No actions needed, initializer list initializes
//reference above. We'll just increment the variable
//so you can see it's shared in main.
m_shared += 7;
}
void DoSomethingWithIt()
{
//Will always reflect value in main no matter which object
//we are talking about.
std::cout << m_shared << std::endl;
}
private:
//Reference variable, must be initialized in
//initializer list of constructor or you'll get the same
//compiler error again.
int& m_shared;
};
int main()
{
int my_shared_integer = 0;
//Create two A instances that share my_shared_integer.
//Both A's will initialize their internal reference to
//my_shared_integer as they will take it into their
//constructors "by reference" (see & in constructor
//signature) and save it in their initializer list.
A myFirstA(my_shared_integer);
A mySecondA(my_shared_integer);
//Prints 14 as both A's incremented it by 7 in constructors.
std::cout << my_shared_integer << std::endl;
}
you pass a pointer int* as 1st argument to BufferTypeA, which expects and int, while you said in your question you meant to use a int&. To do this, the ctor of BufferTypeA should take a int& and initialise it in an initialisation list (i.e. not within the { } part of the ctor) like
class BufferType {
int &Ref;
public:
BufferTypeA(int& ref) : Ref(ref) { /* ... */ }
};
and in your construction of BufferA you must not pass an address, but the reference, i.e.
int counter;
Buffer = new BufferType(counter);
You want code like this:
Buffer::Buffer(
int &currentThreadOrder0,
const int threadConnectionOrder0,
QWaitCondition *const waitCondition0
) :
threadConnectionOrder(threadConnectionOrder0),
waitCondition(waitCondition0),
currentThreadOrder(currentThreadOrder0)
{}
The reason is related to the reason you cannot write
const double pi;
pi = 3.14;
but can write
const double pi = 3.14;
A reference is typically implemented as a constant pointer, to which one cannot assign an address after one has initialized the pointer. Your version of the code assigns, as in the first pi example. My version of the code initializes, as in the second pi example.

Passing a specific array element using pointer reference

I am having problem with passing a pointer by reference.
This is the method
void set_range(double **measu)
{
if ((*measu)[0] < 0) //or i is used for a loop
return ;
}
int main()
{
double *mes;
set_range(&mes[1]);
}
I have allocated memory and required values are set. But this program gives me "Unhandled exception Access violation reading location" error.
So my question is,how to pass the pointer of mes[1] instead of mes[0] (which normally passed when (&mes) is given) to the set_range method?
One problem is that &mes[1] is of type double *, not the double ** required of your function.
Another problem is that mes doesn't point to anything - it's uninitialized. So dereferencing it will access junk (which is why you get an access violation).
I'm trying to come up with some code to help clarify, but honestly I have no idea what you're trying to do. Some more code would help us figure out what your goal is, but just given the above I have no idea why you need a double ** or whether you need dynamic memory or just a single double variable.
Change your function to take a double* instead of a double**, eg:
void set_range(double *measu)
{
if (*measu < 0) //or i is used for a loop
return;
}
int main()
{
double *mes;
...
set_range(&mes[1]);
}
Alternatively, use a real reference instead:
void set_range(double &measu)
{
if (measu < 0) //or i is used for a loop
return;
}
int main()
{
double *mes;
...
set_range(mes[1]);
}

Creating function pointers to functions created at runtime

I would like to do something like:
for(int i=0;i<10;i++)
addresses[i] = & function(){ callSomeFunction(i) };
Basically, having an array of addresses of functions with behaviours related to a list of numbers.
If it's possible with external classes like Boost.Lambda is ok.
Edit: after some discussion I've come to conclusion that I wasn't explicit enough. Please read Creating function pointers to functions created at runtime
What I really really want to do in the end is:
class X
{
void action();
}
X* objects;
for(int i=0;i<0xFFFF;i++)
addresses[i] = & function(){ objects[i]->action() };
void someFunctionUnknownAtCompileTime()
{
}
void anotherFunctionUnknowAtCompileTime()
{
}
patch someFunctionUnknownAtCompileTime() with assembly to jump to function at addresses[0]
patch anotherFunctionUnknownAtCompileTime() with assembly to jump to function at addresses[1]
sth, I don't think your method will work because of them not being real functions but my bad in not explaining exactly what I want to do.
If I understand you correctly, you're trying to fill a buffer with machine code generated at runtime and get a function pointer to that code so that you can call it.
It is possible, but challenging. You can use reinterpret_cast<> to turn a data pointer into a function pointer, but you'll need to make sure that the memory you allocated for your buffer is flagged as executable by the operating system. That will involve a system call (LocalAlloc() on Windows iirc, can't remember on Unix) rather than a "plain vanilla" malloc/new call.
Assuming you've got an executable block of memory, you'll have to make sure that your machine code respects the calling convention indicated by the function pointer you create. That means pushing/popping the appropriate registers at the beginning of the function, etc.
But, once you've done that, you should be able to use your function pointer just like any other function.
It might be worth looking at an open source JVM (or Mono) to see how they do it. This is the essence of JIT compilation.
Here is an example I just hacked together:
int func1( int op )
{
printf( "func1 %d\n", op );
return 0;
}
int func2( int op )
{
printf( "func2 %d\n", op );
return 0;
}
typedef int (*fp)(int);
int main( int argc, char* argv[] )
{
fp funcs[2] = { func1, func2 };
int i;
for ( i = 0; i < 2; i++ )
{
(*funcs[i])(i);
}
}
The easiest way should be to create a bunch of boost::function objects:
#include <boost/bind.hpp>
#include <boost/function.hpp>
// ...
std::vector< boost::function<void ()> > functors;
for (int i=0; i<10; i++)
functors.push_back(boost::bind(callSomeFunction, i));
// call one of them:
functors[3]();
Note that the elements of the vector are not "real functions" but objects with an overloaded operator(). Usually this shouldn't be a disadvantage and actually be easier to handle than real function pointers.
You can do that simply by defining those functions by some arbitrary names in the global scope beforehand.
This is basically what is said above but modifying your code would look something like this:
std::vector<int (*) (int)> addresses;
for(int i=0;i<10;i++) {
addresses[i] = &myFunction;
}
I'm not horribly clear by what you mean when you say functions created at run time... I don't think you can create a function at run time, but you can assign what function pointers are put into your array/vector at run time. Keep in mind using this method all of your functions need to have the same signature (same return type and parameters).
You can't invoke a member function by itself without the this pointer. All instances of a class have the function stored in one location in memory. When you call p->Function() the value of p is stored somewhere (can't remember if its a register or stack) and that value is used as base offset to calculate locations of the member variables.
So this means you have to store the function pointer and the pointer to the object if you want to invoke a function on it. The general form for this would be something like this:
class MyClass {
void DoStuf();
};
//on the left hand side is a declaration of a member function in the class MyClass taking no parameters and returning void.
//on the right hand side we initialize the function pointer to DoStuff
void (MyClass::*pVoid)() = &MyClass::DoStuff;
MyClass* pMyClass = new MyClass();
//Here we have a pointer to MyClass and we call a function pointed to by pVoid.
pMyClass->pVoid();
As i understand the question, you are trying to create functions at runtime (just as we can do in Ruby). If that is the intention, i'm afraid that it is not possible in compiled languages like C++.
Note: If my understanding of question is not correct, please do not downvote :)