I have values like this one in my db
ale
I would like to get the result ale when I query for alexander
I tried to do it like this, new MongoRegex("/^alexander/i") but no luck, how can i overcome this issue and get the result ale when I query for alexander
I am trying to do url matching system, when a user sets matching for asd.com/cat I have to match asd.com/cat/car and asd.com/cat/home, etc. I am trying to accomplish this, thank you
If I understood correctly, you need to match any url wit same form up to last slash. Im afraid you will have to do it in two steps. Fisrt isolate the first part of url with
.*\/
this will match asd.com/cat/ . And then you can search for this string with anything after it.
^asd.com/cat/.*
Related
I am at the beginning of learning Regex, and I use every opportunity to understand how it's working. Currently I am trying to extract dates from a text file (which is in fact a vnt-file type from my mobile phone). It looks like following:
BEGIN:VNOTE
VERSION:1.1
BODY;ENCODING=QUOTED-PRINTABLE;CHARSET=UTF-8:18.07.=0A14.08.=0A15.09.=0A15.10.=
=0A13.11.=0A13.12.=0A12.01.=0A03.02. Grippe=0A06.03.=0A04.04.2015=0A0=
5.05.2015=0A03.06.2015=0A03.07.2015=0A02.08.2015=0A30.08.2015=0A28.09=
17.11.2017=0A
DCREATED:20171118T095601
X-IRMC-LUID:150
END:VNOTE
I want to extract all dates, so that the final list is like that:
18.07.
14.08.
15.09.
15.10.
and so on. If the date has also a year, it should also be displayed.
I almost found out how to detect the dates by the following regex:
.+(\d\d\.\d\d\.(2015|2016|2017)?).+
But it only detect very few of the dates. The result is this:
BEGIN:VNOTE
VERSION:1.1
15.10.
04.04.2015
30.08.2015
24.01.2016
DCREATED:20171118T075601
X-IRMC-LUID:150
END:VNOTE
Then I tried to add a question mark which makes the .+ not greedy, as far as I read in tutorials. Then the regex looks like:
.+?(\d\d\.\d\d\.(2015|2016|2017)?).+?
But the result is still not what I am looking for:
BEGIN:VNOTE
VERSION:1.1
21.03.20.04.18.05.18.06.18.07.14.08.15.09.15.10.
13.11.13.12.12.01.03.02.06.03.04.04.20150A0=
03.06.201503.07.201502.08.201530.08.20150A28.09=
28.10.201525.11.201528.12.201524.01.20160A
DCREATED:20171118T075601
X-IRMC-LUID:150
END:VNOTE
For someone who is familiar with regex I am pretty sure this is very easy to solve, but I don't get it. It's very confusing when you are new to regex. I tried to find a hint in some tutorials or stackoverflow posts, but all I found is this: Notepad++ how to extract only the text field which is needed?
But it doesn't work for me. I assume it might have something to do with the fact that my text file is not one single line.
I have my example on regex101 too.
I would be very thankful if maybe someone can give me a hint what else I can try.
Edit: I would like to detect the dates with the regex and as a result have a list with only the dates (maybe it is called substitute?)
Edit 2: Sorry for not mentioning it earlier: I just want to use the regex in e.g. Notepad++ or an online regex test website. Just to get the result of the dates and save the result in a new txt-file. I don't want to use the regex in an programming language. My apologies for not being precisely before.
Edit 3: The result should be a list with the dates, and each date in a new line:
I want to extract all dates, so that the final list is like that:
18.07.
14.08.
15.09.
15.10.
I suggest this pattern:
(?:.*?|\G)(\d\d\.\d\d\.(?:\d{4})?)
This makes use of the \G flag that, in this case, allows for multiple matches from the very start of the match without letting any single unmatched character in the text, thus allowing the removal of all but what's wanted.
If you want to remove the extra matches as well, add |.* at the end:
(?:.*?|\G)(\d\d\.\d\d\.(?:\d{4})?)|.*
regex101 demo
In N++, make sure the options underlined are selected, and that the cursor is at the beginning. In the picture below, I replaced then undid the replacement, only to show that matches were identified (16 replacements).
You can try using the following pattern:
\d{2}\.\d{2}\.(?:\d{4})?
This will match day.month dates of the form 18.07., but it also allows such a date to be followed by a four digit year, e.g. 18.07.2017. While it would be nice to make the pattern more restrictive, to avoid false fire matches, I do not see anything obvious which can be added to the above pattern. Follow the demo link below to see the pattern in action.
Demo
I have some data that I need help cleaning up. For some reason, tracking params are being stored within the database so what is the best way to extract the search query minus the tracking params using regex? I need to extract the following search queries:
things to do
las vegas
airport parking
from the following data:
{"query":"things to do","prefilteredchannel":"gpse
{"query":"las vegas","prefilteredchannel":"gpsea
{"query":"airport parking
I've tried a few things but I can only match the things I don't care about and I don't know how to just extract the search query. I'm new to this so any help would be appreciated.
Any ideas on how to make this work with the Platfora regex_replace:
http://documentation.platfora.com/webdocs/index.html#reference/expression_language/function_regex_replace.html
use this regex . its quite simple
{"query":"([^"]*)(?:"|$)
See demo here regex101
You can use following:
\{"query":"([^"]*|$)
It will match the query value until " is encountered or end of string (whichever comes first).
Demo
We have an implementation of Liferay portal and I'm just getting started with using Google Analytics with it. I'm noticing a lot of duplicate entries in GA, mainly because of the query strings in the URI, for example:
/web/home-community/search-and-help?p_p_id=mytcdirectory_WAR_mytcdirectory&p_p_lifecycle=1&p_p_state=normal&p_p_mode=view&p_p_col_id=column-3&p_p_col_count=4&_mytcdirectory_WAR_mytcdirectory_action=getResults
I'm playing around with the Search and Replace filters in GA (using regex) and my goal is to try to pull out the ?p_p_id and &*_action parameters from the URI, and disregard the rest. I'm getting close with the following regex:
^([^\?]+)([\?\&]p_p_id=[^\&]+)?.*(\&[^\&]+_action=[^\&]+)?.*$
But that last grouping isn't working correctly. If I remove the ? from the end of the last grouping it matches, but the problem with that approach is that not all URIs contain that query string so it needs to be optional. But if I keep it in, it won't grab that last parameter. My regex fiddle is located here:
http://regex101.com/r/qQ2dE4/13
Thank you all in advance for any help.
I'm relatively new to regex and in order to set up a goal in Google Analytics, I'd like to use a regular expression to match a URL containing both "thank-you" and "purchaseisFree=False" but exclude two specific rate plans that are represented in the URL as "productRatePlanID=5197e" and "productRatePlanID=c1760".
Here is a full URL example:
https://www.examplepage.com/thank-you?productRatePlanId=5197e&purchaseIsFree=False&grossTotal=99.95&netTotal=99.95&couponCode=&invoiceNumber=INV00000589
I tried using this post as a model and created this regex:
\bthank-you\b.+\purchaseIsFree=False\b(?:$|=[^c1760]|[^5197e])
However, I'm not getting the desired results. Thanks in advance for any suggestions.
I think the below mentioned regex should solve your problem. It uses the positive|negative look ahead facility. We can sit at the beginning of http[s] and check all the three condition and then engulp the whole tree
(https?:\/\/)(?=.*?productRatePlanId=(?!5197e&)(?!c1760&))(?=.*?thank-you)(?=.*?purchaseisFree=False).*
Note:- I have used & after the productRatePlanId values just to ensure it doesnt ignore other values as 5197f, 5198d and all other sorts of values.
I spend a couple of hour with no good result (maybe my mood is not helping about it).
I am trying to build a regex to help me match both urls:
/reservables/imagenes/4/editar/6
/reservables/imagenes/4/subir
As you note above, the last segment in the first url 6 is not present at the end of the second url, because this segments is optional here. So I need to match both urls in one regex, for that, I have tried this:
reservables/(editar|imagenes)/([0-9]+)/(imagen|editar|actualizar|subir)/([0-9]+)
That works fine only for the first url. So, reading a few notes about regex it suggest me that I need the ? symbol, right? So, I tried this one, but it did not work:
reservables/(editar|imagenes)/([0-9]+)/(imagen|editar|actualizar|subir)/([0-9]+)?
Well, I do not what I am doing wrong.
You want to put the ? around the / as well, like so:
reservables/(editar|imagenes)/([0-9]+)/(imagen|editar|actualizar|subir)(?:/([0-9]+))?
You can see that it matches correctly on debuggex.
This one will work:
reservables/(editar|imagenes)/([0-9]+)/(imagen|editar|actualizar|subir)/([0-9]*)