Group Items together dictionary while loop - python-2.7

Question

I am having trouble storing the ID to keys, like a sub (parent-child) kind of thing. I spent hours on it and could not figure a way to accomplish this. What output I am expecting is at the end of this post. Any help would be great.
import sys
import collections
dict = collections.OrderedDict()
dict["A.1"] = {"parent_child":0}
dict["A.1.1"] = {"parent_child":1}
dict["A.1.1.1"] = {"parent_child":2}
dict["A.1.1.2"] = {"parent_child":2}
dict["A.1.1.3"] = {"parent_child":2}
dict["A.1.2"] = {"parent_child":1}
dict["A.1.2.1"] = {"parent_child":2}
dict["A.1.2.2"] = {"parent_child":2}
dict["A.1.2.2.1"] = {"parent_child":3}
dict["A.1.2.2.2"] = {"parent_child":3}
dict["A.1.2.3"] = {"parent_child":2}
dict["A.1.3"] = {"parent_child":1}
dict["A.1.4"] = {"parent_child":1}
print(dict)
new_dict = {}
p = 0 # previous index
i = 0 # current
n = 1 # next index
current_PC = 0 # current parent_child
next_PC = 0 # next parent_child
previous_id = ""
current_id = ""
next_id = ""
change_current = True
change = True
lst = []
while(True):
if change_current:
current_id = dict.keys()[i]
current_PC = dict.values()[i]["parent_child"]
change_current = False
try:
next_id = dict.keys()[n]
next_PC = dict.values()[n]["parent_child"]
except:
pass # it will go out of index
print("KEY {0}".format(current_id))
if next_PC > current_PC:
if next_PC - current_PC == 1:
lst.append(next_PC)
next_PC += 1
print("next_PC: {0}".format(next_PC))
if next_PC == current_PC:
new_dict[current_id] = lst
lst = []
break
print(new_dict)
Trying to make output looks like this (at in similar way), the new_dict should look like:
new_dict["A.1"] = ["A.1.1", "A.1.2", "A.1.3", "A.1.4"]
new_dict["A.1.1"] = ["A.1.1.1", "A.1.1.2", "A.1.1.3"]
new_dict["A.1.1.1"] = []
new_dict["A.1.1.2"] = []
new_dict["A.1.1.3"] = []
new_dict["A.1.2"] = ["A.1.2.1", "A.1.2.2", "A.1.2.3"]
new_dict["A.1.2.1"] = []
new_dict["A.1.2.2"] = ["A.1.2.2.1", "A.1.2.2.2"]
new_dict["A.1.2.2.1"] = []
new_dict["A.1.2.2.2"] = []
new_dict["A.1.2.3"] = []
new_dict["A.1.3"] = []
new_dict["A.1.4"] = []

Answer 1

This gives you the output you are asking for. Since i did not see a {"parent_child":...} in you desired output i did not proceed with anything else.
options = ["A.1","A.1.1","A.1.1.1","A.1.1.2","A.1.1.3","A.1.2","A.1.2.1","A.1.2.2","A.1.2.2.1","A.1.2.2.2","A.1.2.3","A.1.3","A.1.4"]
new_dict = {}
for i, key in enumerate(options):
new_dict[key] = []
ls = []
for j, opt in enumerate(options):
if (key in opt) and (len(opt)-len(key)==2):
new_dict[key].append(opt)
print(new_dict)
EDIT
Using the comment of #Ranbir Aulakh
options = ["A.1","A.1.1","A.1.1.1","A.1.1.2","A.1.1.3","A.1.2","A.1.2.1","A.1.2.2","A.1.2.2.1","A.1.2.2.2","A.1.2.3","A.1.3","A.1.4"]
new_dict = {}
for i, key in enumerate(options):
new_dict[key] = []
ls = []
for j, opt in enumerate(options):
if (key in opt) and (len(opt.split("."))-len(key.split("."))==1):#(len(opt)-len(key)==2):
new_dict[key].append(opt)
print(new_dict)