I need to pass a node as a parameter to an XSL stylesheet. The issue is that the parameter gets sent as a string. I have seen the several SO questions regarding this topic, and I know that the solution (in XSLT 1.0) is to use an external node-set() function to transform the string to a node set.
My issue is that I am using eXist DB I cannot seem to be able to get its XSLT processor to locate any such function. I have tried the EXSLT node-set() from the namespace http://exslt.org/common as well as both the Saxon and Xalan version (I think eXist used to use Xalan but now it might be Saxon).
Are these extensions even allowed in the XSLT processor used by eXist? If not, is there something else I can do?
To reference or transform documents from the database, you should pass the path as a parameter to the transformation, and then refer to it using a parameter and variable
(: xquery :)
let $path-to-document := "/db/test/testa.xml"
let $stylesheet :=
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:param name="source" required="no"/>
<xsl:variable name="error"><error>doc not available</error></xsl:variable>
<xsl:variable name="theDoc" select="if (doc-available($source)) then doc($source) else $error"/>
<xsl:template match="/">
<result><xsl:value-of select="$source"/> - <xsl:value-of select="node-name($theDoc/*)"/></result>
</xsl:template>
</xsl:stylesheet>
return transform:transform(<dummy/>,$stylesheet, <parameters><param name="source" value="xmldb:exist://{$path-to-document}"/></parameters>)
As per Martin Honnen's comments I don't think it is possible to pass an XML node via the <parameters> structure of the transform:transform() function in eXist. The function seems to strip away any XML tags passed to it as a value.
As a workaround I will wrap both my input XML and my parameter XML into a root element and pass that as input to the transform function.
Related
I have an XSLT key defined. I need to access the key from within a for-each loop, where that loop is processing a node-set that is outside the scope of where the key was defined.
Snippet, where I've marked two lines, one which works and one which does not:
<xsl:value-of select="key('name', 'use')"/> <!-- works -->
<xsl:for-each select="$outOfScopeNodeSet">
<xsl:value-of select="key('name', 'use')"/> <!-- does not work -->
</xsl:for-each>
Is there a way to access the key from within the for-each loop?
XSLT 1.0, msxsl engine.
(I could not think of a reasonable way to provide a full working example for this. I'm also not sure of the correct terminology, such as "scope" - perhaps if I knew the correct terminology I'd be able to find my answer already. If the question is not clear enough please let me know and I'll try to edit it into better shape.)
In XSLT 1.0, keys do not work across documents. It seems that your $outOfScopeNodeSet contains a node-set whose root node is different from the root node of the XML document being processed (probably created by the exsl:node-set() function?) - while the key is supposed to fetch a value from the processed XML document.
To resolve this problem, you need to return the context back to the processed XML document before calling the key() function, for example:
<xsl:variable name="root" select="/" />
<xsl:for-each select="$outOfScopeNodeSet">
<xsl:variable name="use" select="some-value" />
<xsl:for-each select="$root">
<xsl:value-of select="key('name', $use)"/>
</xsl:for-each>
</xsl:for-each>
I am using Saxon to perform a transformation of an XML document in my .NET application. I am passing in a parameter to my xslt document but I have no idea how to use it in my template.
Here is what I have done so far:
var zipcode = _db.AXCustomers.FirstOrDefault(x => x.ACCOUNTNUM == accNo).ZIPCODE;
transformer.SetParameter(new QName("CustomerZipCode"), new XdmAtomicValue(zipcode));
Then in my xslt document I am specifying the parameter like so:
<xsl:template match="/">
<xsl:param name="CustomerZipCode" />
But when I try to use the parameter, nothing appears. I am using it like so:
<xsl:value-of select="substring-before($CustomerZipCode, ' ')"/>
But nothing is output even though my zipcode does contain a value
You are using xsl:param inside a xsl:template element, it means that the param is for the template. The parameter you are passing from the .net code is a transformer parameter and related xsl:param must be placed at the top level of the stylesheet, into the xsl:stylesheet element.
I try to concstruct link with
<xsl:element name="a">
<xsl:attribute name="href">
<xsl:value-of select="concat('file:///', substring-before('%RolesPath%', 'roles'),'Flores.chm')"/>
</xsl:attribute>
Help
</xsl:element>
but I get error:
File file:///Flores.chm not found
I'm pretty sure, that variable %RolesPath% works fine. I'm using it in code normally. And if I use in code only
<xsl:value-of select="concat('file:///', substring-before('%RolesPath%', 'roles'),'Flores.chm')"/>
I get
file:///C:\Flores\Flores.chm
which is right path. Where I'm doing mistake please?
edit. %RolesPath% stores path to specify folder of program, which works with this code. In my case %RolesPath% stores "C:\Flores\roles\".
To specify my problem. I need open file(Flores.chm) in root folder of program. Program can be install everywhere in PC and prapably only way, how I can get the path is via %RolesPath%.
What you are passing to substring-before() is just a string ('%RolesPath%'). It appears that you are trying to use a Windows environment variable. This isn't going to work the way you're using it.
I think you have 2 options:
Option 1
Pass the value of the environment variable as an xsl:param when you call the stylesheet. This would work in either XSLT 1.0 or 2.0.
You would need the xsl:param:
<xsl:param name="RolesPath"/>
and this is how you would reference it:
<a href="{concat('file:///', substring-before($RolesPath, 'roles'),'Flores.chm')}"/>
Option 2
Use the environment-variable() function. This would only work with an XSLT 3.0 processor, such as Saxon-PE or EE.
Example:
<a href="{concat('file:///', substring-before(environment-variable('RolesPath'), 'roles'),'Flores.chm')}"/>
Here's another example of environment-variable() to show the function actually working:
XSLT 3.0
<xsl:stylesheet version="3.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<environment-variable name="TEMP" value="{environment-variable('TEMP')}"/>
</xsl:template>
</xsl:stylesheet>
Output (when applied to any well-formed XML)
<environment-variable name="TEMP" value="C:\Users\dhaley\AppData\Local\Temp"/>
Use this shorter expression:
<a href="file:///{substring-before($RolesPath, 'roles')}Flores.chm"/>
where $RolesPath is passed as an external, global parameter to the transformation.
How exactly to pass an external parameter to the transformation varies from one XSLT processor to another -- read your XSLT processor documentation. Some XSLT processors also allow string-typed parameters to be passed to the transformation from a command-line execution utility.
For some reason, YQL's XSLT table can't parse my stylesheet. I have used the stylesheet successfully with the W3C's XSLT service. Here's an example of the problem in YQL Console. Why does this not work in YQL?
Also, I have yet to figure out how to pass the results of a YQL query to the XSLT table as the XML to be transformed while also specifying a stylesheet url. Current workaround is to abuse the W3C's service.
Your stylesheet is defined as 1.0 but you're using replace() and tokenize() which is part of the 2.0 standard. However it is a fully valid XSLT/XPath 2.0 stylesheet.
As an addition to Per T answer, change this:
<xsl:variable name="r">
<xsl:value-of select="replace(tr/td/p/a/following-sibling::text(),
'\s*-\s*(\d+)\.(\d+)\.(\d+)\s*',
'$1,$2,$3')" />
</xsl:variable>
With this:
<xsl:variable name="r"
select="translate(tr/td/p/a/following-sibling::text(),'. -',',')">
These:
tokenize($r,',')[1]
tokenize($r,',')[2]
tokenize($r,',')[3]
With these:
substring-before($r,',')
substring-before(substring-after($r,','),',')
substring-after(substring-after($r,','),',')
Note: This is just in case you don't know the amount of digit in advance, otherwise you could do:
substring($r,1,2)
substring($r,4,2)
substring($r,7)
Also, this
replace(tr/td/p[#class='t11bold']/a,'\s+',' ')
It should be just this:
normalize-space(tr/td/p[#class='t11bold']/a)
And finaly this:
replace($d,'^[^\[]*\[\s*(\d+:\d{2})?\s*-?\s*([^\]]*)\]\s*$','$2')
Could be:
normalize-space(substring-after(substring-before(substring-after($d,'['),']'),'-'))
I have an XML document that needs to pass text inside an element with an '&' in it.
This is called from .NET to a Web Service and comes over the wire with the correct encoding &
e.g.
T&O
I then need to use XSLT to create a transform but need to query SQL server through a SP without the encoding on the Ampersand e.g T&O would go to the DB.
(Note this all has to be done through XSLT, I do have the choice to use .NET encoding at this point)
Anyone have any idea how to do this from XSLT?
Note my XSLT knowledge isn’t the best to say the least!
Cheers
<xsl:text disable-output-escaping="yes">&<!--&--></xsl:text>
More info at: http://www.w3schools.com/xsl/el_text.asp
If you have the choice to use .NET you can convert between an HTML-encoded and regular string using (this code requires a reference to System.Web):
string htmlEncodedText = System.Web.HttpUtility.HtmlEncode("T&O");
string text = System.Web.HttpUtility.HtmlDecode(htmlEncodedText);
Update
Since you need to do this in plain XSLT you can use xsl:value-of to decode the HTML encoding:
<xsl:variable name="test">
<xsl:value-of select="'T&O'"/>
</xsl:variable>
The variable string($test) will have the value T&O. You can pass this variable as an argument to your extension function then.
Supposing your XML looks like this:
<root>T&O</root>
you can use this XSLT snippet to get the text out of it:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" />
<xsl:template match="root"> <!-- Select the root element... -->
<xsl:value-of select="." /> <!-- ...and extract all text from it -->
</xsl:template>
</xsl:stylesheet>
Output (from Saxon 9, that is):
T&O
The point is the <xsl:output/> element. The defauklt would be to output XML, where the ampersand would still be encoded.