Django, viewing models from different app - django

Question

I am super new to python programming and django and i got the basics out of the way. I created a project with two apps, home and video. In my video models.py i have the following data:
class Video(models.Model):
name = models.CharField(max_length=200)
description = models.TextField(blank=True, null=True)
I want to do something with this in my home app in the views.py, such as display the data in an html page and currently it is set up as followed:
from video.models import Video
def display_video(request):
video_list = Video.objects.all()
context = {'video_list': video_list}
return render(request, 'home/home.html', context)
in my home.html
{% if video_list %}
{% for video in video_list %}
<p>{{ video.name }}</p>
<p>{{ video.description }}</p>
{% endfor %}
{% else %}
<p>no videos to display</p>
{% endif %}
my home.html always returns "no videos to display"
But when i query Video.objects.all() in my video app it finds 2 objects. any help is appreciated.

Answer 1

I decided to delete the project and started over brand new but this time I used class views instead of function views. I'm not exactly sure why it didn't run but using class views it worked like a charm. So the equivalent in class views as simple as possible is.
from video.models import Video
class IndexView(generic.ListView):
template_name = 'home/index.html'
context_object_name = 'top_three'
def get_queryset(self):
return Video.objects.all()[:3]

Answer 2

In settings, check the following is there.
TEMPLATES = [
{
'BACKEND': 'django.template.backends.django.DjangoTemplates',
'DIRS': [],
'APP_DIRS': True,
'OPTIONS': {
'context_processors': [
'django.template.context_processors.debug',
'django.template.context_processors.request',
'django.contrib.auth.context_processors.auth',
'django.contrib.messages.context_processors.messages',
],
},
},
]

Answer 3

It worked for me without using class. I just did what we normally do.
from django.shortcuts import render
from AllBlogs.models import Post # getting this post form AllBlogs app
# Create your views here.
def home (request):
# sort posts according to date in descending order
# only a single query is generated and then hit the database that's how this will not affect the performance of database
latest_blogs = Post.objects.all().order_by("-date")[:3]
return render(request,'Home/home.html',{'blog':latest_blogs})
And this is my template
<!--separated it from the home.html because we can use it in AllBlogs.html
and it save our work and time by just including without copying the same data several times-->
{% load static %}
<li>
<!--add field name which we used in models-->
<article class="blog">
<a href="{% url 'blogDetails_page' blog.slug %}"> <!--Different slug for different blog as slug will create a different url-->
<!--dtl filter to add back or url dynamic url creation-->
<image src="{% static 'images/'|add:blog.image_name %}" alt="{{blog.title}}">
<div class="blog__content">
<h3>{{blog.title}}</h3>
<p>{{blog.excerpt}}</P>
</div>
</a>
</article>
</li>
And this is the Post model
# having post data
class Post(models.Model):
title = models.CharField(max_length=150)
date = models.DateField(auto_now=True) # put the date in the field at which time we are saving the data
image_name = models.CharField(max_length=50) # later on we upload files right now we get images from static folder
excerpt = models.CharField(max_length=200)
content = models.TextField(validators=[MinLengthValidator(10)]) # TextFields same like CharField
slug = models.SlugField(unique=True, db_index=True) # set it as unique because we are going to use it as a primary key
author = models.ForeignKey(Author,on_delete=models.SET_NULL,related_name='posts',null=True) # one to many relation
tags = models.ManyToManyField(Tag) # ManyToManyRelation with tag
# represent post entry by it post title
def __str__(self):
return self.title