how can I create a file in python if the filename contains '/'
url='https://www.udacity.com/cs101x/index.html'
f=open(url,'w')
f.write('123')
f.close()
above code produces an error as
Traceback (most recent call last):
File "9.py", line 2, in <module>
f=open(url,'w')
IOError: [Errno 22] invalid mode ('w') or filename:https://www.udacity.com/cs101x/index.html'
Use os.path.basename() to isolate the filename.
import os
url='https://www.udacity.com/cs101x/index.html'
filename = os.path.basename(url)
f=open(filename,'w')
f.write('123')
f.close()
This will create a file called index.html
Related
I am trying to read data from an xml file from an url using request module in python
import requests
from requests.auth import HTTPBasicAuth
import xml.etree.ElementTree as et
url ="https://sample.com/simple.xml"
response = requests.get(url,auth=HTTPBasicAuth(username,password))
xml_data = et.fromstring(response.text)
The error I am getting is:
Traceback (most recent call last):
File "C:\Python27\myfolder\Artifactory.py", line 156, in <module>
xml_data = et.fromstring(xml_response.text)
File "C:\Python27\lib\xml\etree\ElementTree.py", line 1311, in XML
parser.feed(text)
File "C:\Python27\lib\xml\etree\ElementTree.py", line 1657, in feed
self._parser.Parse(data, 0)
UnicodeEncodeError: 'ascii' codec can't encode character u'\xae' in position 8419: ordinal not in range(128)
So i changed the code to xml_data = et.parse(response.text)
then the error is :
Traceback (most recent call last):
File "C:\Python27\myfolder\Artifactory.py", line 156, in <module>
xml_data = et.parse(xml_response.text)
File "C:\Python27\lib\xml\etree\ElementTree.py", line 1182, in parse
tree.parse(source, parser)
File "C:\Python27\lib\xml\etree\ElementTree.py", line 647, in parse
source = open(source, "rb")
IOError: [Errno 2] No such file or directory: u'<?xml version="1.0" encoding="utf-8"?>
After this error the xml data is getting printed
please help me in this issue
et.parse requires file path (not contents).
You need to encode response to utf-8
xml_data = et.fromstring(response.text.encode('utf-8'))
The first attempt seems like an encoding issue with python.
try adding this to your code between your last import and your url variable.
import sys
reload(sys)
sys.setdefaultencoding("utf8")
I am trying to create an empty csv file in python (2.7) but see the following error. Can anyone tell me why this is happening?
>>> tutorial_out = open('tutorial.csv', 'wb')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
IOError: [Errno 1] Operation not permitted: 'tutorial.csv'
This is a permission issue, you probably don't have permission to write in that directory.
Solution: Modify permission of that directory or run as root.
I am struggling with file access - I have my python 2.7 here:
C:\Python27
I created a txt file data.txt
and I am trying to get the shell to read and print values from it. Location of data.txt is in the same folder (C:\Python27\data.txt)
Every time I got the same error msg:
Traceback (most recent call last):
File "C:/Python27/FileReader.py", line 1, in <module>
infile = open('data.txt', 'r') # Open the file for reading.
IOError: [Errno 2] No such file or directory: 'data'
You need to enter the full filename data.txt instead of data only:
infile = open('data.txt', 'r')
I wrote a script to rename a txt file in pythonwin as below.
import os
os.rename("northrdge.txt","northrdgechg.txt")
the above text file is in the path:C:\Users\gmayil\Desktop\northrdge.txt.
after this when i run the script i met below error:
Can anyone please help me on this ?
Traceback (most recent call last):
File "C:\Python27\Lib\site-packages\pythonwin\pywin\framework\scriptutils.py", line 433, in ImportFile
exec codeObj in __main__.__dict__
File "<auto import>", line 1, in <module>
File "C:\Python27\Tools\gopi\renamefile.py", line 2, in <module>
os.rename("northrdge.txt","northrdgechg.txt")
WindowsError: [Error 2] The system cannot find the file specified
Your python-file lies in "C:\Python27\Tools\gopi\renamefile.py", but you say your txt-file is in "C:\Users\gmayil\Desktop\". If you pass a relative path, python searches in its own directory, which is "C:\Python27\Tools\gopi\".
So all you have to do is giving the complete path:
os.rename("C:\Users\gmayil\Desktop\northrdge.txt", "C:\Users\gmayil\Desktop\northrdgechg.txt")
I want to loop through the files present in Audio_files folder and check if it is raw file or wave file and put it in the respective directories.
Here is my code:
import shutil
import os
source = os.listdir("/home/GM/codec_implement/Audio_files/")
destination = "/home/GM/codec_implement/raw_files/"
destination2 = "/home/GM/codec_implement/raw_files/wave_files/"
for files in source:
if files.endswith(".wav"):
shutil.copy(files,destination)
elif files.endswith(".raw"):
shutil.copy(files,destination)
else:
print "Invalid format"
Please let me know where I am making mistake. Error i get is:
Traceback (most recent call last): File "./checkaudiofiles.py", line
12, in shutil.copy(files,destination) File
"/usr/lib/python2.7/shutil.py", line 119, in copy copyfile(src, dst)
File "/usr/lib/python2.7/shutil.py", line 82, in copyfile with
open(src, 'rb') as fsrc: IOError: [Errno 2] No such file or directory:
'test_sound.wav'
The error means that the test_sound.wav file is not on that directory. These file might be removed between the two proces or the os.listdir() and the shutil.copy() don't list the files the same way.