String's character delete & Frequency without using library - c++

Question

I am trying to work on a assignment which need to input two string S & str and then deliver three results (Without using any string library):
1.Determine the number and positions of the given str in S
2.Return S with any possible occurrence of str removed
ex. if S=aababacd cdefgh ,
str=aba
The Frequency is 2, position is <0,2>
The Character Delete would be cd cdefgh
Attached code is what I have done so far, I can output the Frequency and the position, but now I have few unsolved questions and I have no idea how to implement it.
1.Once I input a string with space in there, ex. abcd efg, the code will implement it immediately, it will not consider abcd efg as one string but consider it as S=abcd and str=efg , with this problem I cant input a string with blank space to test.
2.How can I output the position like this form: <0,2> , because I am using a loop to output the result so it cant not be like that, I was thinking whether I can create an array to store i and then cout it, but I failed.
3.About the character Delete problem, I found one similar problem, it said if I know how to use strcpy without using library then I would know, but I learned it and I still dont know how to handle this question, I know I can compare these two strings but I dont know how to output S without the str part.I was thinking to change the S into '\0' after loop and output it, but that was totally wrong.
I would be really appreciated if anyone could give me some advice, thank you!
#include <iostream>
#include <algorithm>
using namespace std;
void CharacterDelete(){
char S[100], str[100];
bool match =true;
cout << "Enter string S :";
cin >> S;
cout << "Enter string str :";
cin>>str;
for(int i=0; S[i]!='\0'; i++)
{
for(int j=0; str[j]!='\0';j++){
if(S[i+j]!=str[j]){
match=false;
break;
}
if(match){
S[i+j]='\0';
}
}
}
cout<<S;//Apparently thats a wrong solution
}
void Frequency(){
string S,str;
cout<<"Please input string S"<<endl;
cin>>S;
cout<<"Please input string str"<<endl;
cin>>str;
int sum=0;
for (int i=0; i<S.size(); i++)
{
if (i + str.size() > S.size()) break;
bool match=true;
for (int j=0; j<str.size(); j++)
if (S[i+j] != str[j])
{
match=false;
break;
//Once we print blank space and it would implement it immediately?
}
if(match)
{
sum++;
cout<<"Start from"<<i<<endl;
//What if we use an array to store it and then output it?but how to write it?
}
}
cout<<"The Frequency is "<<sum<<endl;
if(sum==0){
cout<<"There is no starting point"<<endl;
}
}
int main() {
Frequency();
CharacterDelete();
return 0;
}

Answer 1

You are using local variables S and str. You need to use S and str in main function. Then transfer this variables from main in Frequency() and CharacterDelete.
Delete characters: create new variable then copy there characters without delete-characters.
Output:
cout << "<" << num_word << ", " << number << ">\n";