Transforming xml with namespaces using XSLT - xslt

Question

I have the following xml
<?xml version="1.0" encoding="UTF-8"?>
<typeNames xmlns="http://www.dsttechnologies.com/awd/rest/v1" xmlns:xs="http://www.w3.org/2001/XMLSchema">
<typeName recordType="case" href="awdServer/awd/services/v1/businessareas/SAMPLEBA/types/SAMPLECASE">SAMPLECASE</typeName>
<typeName recordType="folder" href="awdServer/awd/services/v1/businessareas/SAMPLEBA/types/SAMPLEFLD">SAMPLEFLD</typeName>
<typeName recordType="source" href="awdServer/awd/services/v1/businessareas/SAMPLEBA/types/SAMPLEST">SAMPLEST</typeName>
<typeName recordType="transaction" href="awdServer/awd/services/v1/businessareas/SAMPLEBA/types/SAMPLEWT">SAMPLEWT</typeName>
</typeNames>
I want to transform above xml as below by using XSLT:
<response>
<results>
<source>
SAMPLEST
</source>
</results>
</response>
</xsl:template>
I just want to get the source from the input xml to the output xml.
I am trying with the following xml, but couldn't get the required output xml:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:v="http://www.dsttechnologies.com/awd/rest/v1" version="2.0" exclude-result-prefixes="v">
<xsl:output method="xml" version="1.0" omit-xml-declaration="yes" encoding="UTF-8" indent="yes" />
<xsl:strip-space elements="*" />
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()" />
</xsl:copy>
</xsl:template>
<xsl:template match="typeNames">
<response>
<results>
<source>
<xsl:value-of select="source" />
</source>
</results>
</response>
</xsl:template>
</xsl:stylesheet>

Answer 1

I. Namespace in input xml
<typeNames xmlns="http://www.dsttechnologies.com/awd/rest/v1"...
xmlns puts self + all child nodes into a namespace. This namespace does not need any prefix.
II. Namespace in XSLT
... xmlns:v="http://www.dsttechnologies.com/awd/rest/v1"...
You prefixed the namespace (same uri as source) with v, so you have to write this prefix in your xpath as well.
<xsl:template match="v:typeNames">
[XSLT 2.0: you also can add xpath-default-namespace="uri" in the stylesheet section, to define a default namespace for all xpath-expressions. Therefore you dont have to prefix the namespace.]
III. Guessing on given input xml
<xsl:value-of select="source" /> -> <typeName recordType="source"..>SAMPLEST</typeName>
If you want to select the shown xml-node, you have to write one of the following:
absolute, without any context node:
/v:typeNames/v:typeName[#recordType = 'source']
on context-node typeNames:
v:typeName[#recordType = 'source']
[<xsl:value-of select="..."/> will return the text-node(s), e.g. "SAMPLEST"]
EDIT:
What if there are two tags.
First things first: <xsl:value-of in XSLT 1 can only work with 1 node! If the xpath expression matches more than one node, it will just process the first one!
Solve it like this way:
...
<results>
<xsl:apply-templates select="v:typeName[#recordType = 'source']"/>
</results>
...
<xsl:template match="v:typeName[#recordType = 'source']">
<source>
<xsl:value-of select="."/>
</source>
</xsl:template>
The apply-templates within results searches for all typeName..source. The matching template listens to that node and creates the xml <source>....