copying an array of int* - c++

Question

I have to create a copy constructor for my object, which look like this;
class DTable {
private:
std::string s_name;
int* *array;
int size;
public:
DTable();
DTable(std::string sName);
DTable(DTable &pcOther);
~DTable();
void vSetName(std::string sName);
std::string info();
int getValue(int index, bool &ok);
bool setValue(int index, int val);
const int defaultArrSize = 10;
const std::string defaultArrName = "Default Name";
};
Where array variable points at array of int*. Copy constructor i came up with looks like this;
DTable::DTable(DTable & pcOther) {
s_name = pcOther.s_name + "_copy";
size = pcOther.size;
array = new int*[size];
for (int i = 0; i < size; i++) {
array[i] = new int;
*array[i] = pcOther.*array[i];
}
}
The problem is that, i just cannot copy values of pointed int array to another array. Solution like this leaves me with error
expression must have pointer to member type
Also,
array[i] = pcOther.array[i];
is wrong, because that just copies references, so after altering one object, copy of it will be altered too. I want to avoid that.
I'd love to use different structure for this, but it has to be dynamically allocated array of int*

Answer 1

You can use the memcpy(),
void * memcpy ( void * destination, const void * source, size_t num );
or
*array[i] = *(pcOther.array[i])
for e.g.
DTable::DTable(DTable & pcOther) {
s_name = pcOther.s_name + "_copy";
size = pcOther.size;
array = new int*[size];
for (int i = 0; i < size; i++) {
array[i] = new int;
*array[i] = *(pcOther.array[i]);
// or
memcpy ( array[i], pcOther.array[i] , sizeof(int)*1 );
}
}