So I am using this as a string:
Username entry \([a-z]{3,15}
To search this as an example:
[PA]apf_ms.c:7678 Username entry (host/computer.domain.com) is deleted for mobile a4:c4:94:63:1c:7a
[PA]apf_ms.c:7678 Username entry (username#domain.com) is deleted for mobile 94:e9:6a:ad:14:4d
Trying to wrap my head around regex and it's driving me nuts. My search only gets me so far, I am trying to make host/ optional and can't figure out where to insert it.
Username entry \((?:host/)?[a-z]{3,15}
(?: ... ) is a non-capture group
host/ is what you want to match
? after it means optional
You can use ? make anything optional in regex. The regex can be written as
Username entry \((?:host\/)?[a-z]{3,15}
(?:host\/)? Matches one or zero host/. The ?: within the brackets prevent it from capturing, as we don't want to save the host/ for future use.
Regex Demo
Related
I'm currently using this regex (?<=\/movie\/)[^\/]+, but it only matches the username from the second url, i know i could make a if (contains /movie/): use this regex, else: use another regex on my code, but i'm trying to do this directly on regex.
http://example.com:80/username/token/30000
http://example.com:80/movie/username/token/30000.mp4
To complete the Tensibai's answer, if you have not a port in url, you can use the last dot in url to start your regex :
\.[^\/\.]+\/(?:movie\/)?([^\/]+)
(demo)
You can use something like this to make the movie/ optional and have the username in a named capture group (Live exemple):
\d[/](?:movie\/)?(?<username>[^/]+)[/]
using \d/ to anchor the start of match at after the url.
Guys could you please help on creating a Regex for below Scenario.
I'm trying to create regex to match file name active users in wildcard.
Tried the basic one but doesn't work (?i)^active users$
example:
Regex should match the word(active users) with case insensitive
AcTiVE Users
active users
ACTIVE USERS
Regex should also match the word(active users) even though character present in prefix and suffix
Active users_test
Test_ACTIVE USERS
You can exclude matching word characters without the underscore at the left and at the right instead of using the anchors.
(?i)(?<![^\W_])active users(?![^\W_])
Regex demo
As the title presents above I am trying to reference a capture groups for a regex replace in a postgres query. I have read that the regex_replace does not support using regex capture groups. The regex I am using is
r"(?:[\s\(\)\=\)\,])(username)(?:[\s\(\)\=\)\,])?"gm
The above regex almost does what I need it to but I need to find out how to only allow a match if the capture groups also capture something. There is no situation where a "username" should be matched if it just so happens to be a substring of a word. By ensuring its surrounded by one of the above I can much more confidently ensure its a username.
An example application of the regex would be something like this in postgres (of course I would be doing an update vs a select):
select *, REGEXP_REPLACE(reqcontent,'(?:[\s\(\)\=\)\,])(username)(?:[\s\(\)\=\)\,])?' ,'NEW-VALUE', 'gm') from table where column like '%username%' limit 100;
If there is any more context that can be provided please let me know. I have also found similar posts (postgresql regexp_replace: how to replace captured group with evaluated expression (adding an integer value to capture group)) but that talks more about splicing in values back in and I don't think quite answers my question.
More context and example value(s) for regex work against. The below text may look familiar these are JQL filters in Jira. We are looking to update our usernames and all their occurrences in the table that contains the filter. Below is a few examples of filters. We originally were just doing a find a replace but that doesn't work because we have some usernames that are only two characters and it was matching on non usernames (e.g je (username) would place a new value in where the word project is found which completely malforms the JQL/String resulting in something like proNEW-VALUEct = balh blah)
type = bug AND status not in (Closed, Executed) AND assignee in (test, username)
assignee=username
assignee = username
Definition of Answered:
Regex that will only match on a 'username' if its surrounded by one of the specials
A way to regex/replace that username in a postgres query.
Capturing groups are used to keep the important bits of information matched with a regex.
Use either capturing groups around the string parts you want to stay in the result and use their placeholders in the replacement:
REGEXP_REPLACE(reqcontent,'([\s\(\)\=\)\,])username([\s\(\)\=\)\,])?' ,'\1NEW-VALUE\2', 'gm')
Or use lookarounds:
REGEXP_REPLACE(reqcontent,'(?<=[\s\(\)\=\)\,])(username)(?=[\s\(\)\=\)\,])?' ,'NEW-VALUE', 'gm')
Or, in this case, use word boundaries to ensure you only replace a word when inside special characters:
REGEXP_REPLACE(reqcontent,'\yusername\y' ,'NEW-VALUE', 'g')
This is our URL structure:
http://www.disabledgo.com/access-guide/the-university-of-manchester/176-waterloo-place-2
http://www.disabledgo.com/access-guide/kingston-university/coombehurst-court-2
http://www.disabledgo.com/access-guide/kings-college-london/franklin-wilkins-building-2
http://www.disabledgo.com/access-guide/redbridge-college/brook-centre-learning-resource-centre
I am trying to create a list of groups based on the client names
/access-guide/[this bit]/...
So I can have a performance list of all our clients.
This is my regex:
/access-guide/(.*universit(y|ies)|.*colleg(e|es))/
I want it to group anything that has university/ies or college/es in it, at any point within that client name section of the URL.
At the moment, my current regex will only return groups that are X-University:
Durham-University
Plymouth-University
Cardiff-University
etc.
What does the regex need to be to have the list I'm looking for?
Do I need to have something at the end to stop it matching things after the client name? E.g. ([^/]+$)?
Thanks for your help in advance!
Depending upon your needs you may want to do:
/access-guide/([^/]*(?:university|universities|college|colleges)[^/]*)/
This will match names even if "university" or "college" is not at the end of the string. For example "college-of-the-ozarks" Note the non-capturing internal parenthesis, that should probably be used no matter what solution you go with, as you don't want to just match the word "university" or "college"
Live Example
Additionally, I don't know what may be in your but if you may have compound words you want to eliminate using a \b may be advisable. For instance if you don't want to match "miskatonic-postcollege" you may want to do something like this:
/access-guide/([^/]*\b(?:university|universities|college|colleges)\b[^/]*)/
If the client name section of the URL is after the access-guid/ and before the next /:
http://www.disabledgo.com/access-guide/the-university-of-manchester/176-waterloo-place-2
|----------------------------|
you need to use a negated character class to only match university before the regex reaches that rightmost / boundary.
As per the Reference:
You can extract pages by Page URL, Page Title, or Screen Name. Identify each one with a regex capture group (Analytics uses the first capture group for each expression)
Thus, you can use
/access-guide/([^/]*(universit(y|ies)|colleges?))
^^^^^
See demo.
The regex matches
/access-guide/ - leftmost boundary, matches /access-guide/ literally
[^/]* - any character other than / (so we still remain in that customer section)
(universit(y|ies)|colleges?) - university, or universities, orcollegeorcolleges` literally. Add more if needed.
I'm basically not in the clue about regex but I need a regex statement that will recognise anything after the / in a URL.
Basically, i'm developing a site for someone and a page's URL (Local URL of Course) is say (http://)localhost/sweettemptations/available-sweets. This page is filled with custom post types (It's a WordPress site) which have the URL of (http://)localhost/sweettemptations/sweets/sweet-name.
What I want to do is redirect the URL (http://)localhost/sweettemptations/sweets back to (http://)localhost/sweettemptations/available-sweets which is easy to do, but I also need to redirect any type of sweet back to (http://)localhost/sweettemptations/available-sweets. So say I need to redirect (http://)localhost/sweettemptations/sweets/* back to (http://)localhost/sweettemptations/available-sweets.
If anyone could help by telling me how to write a proper regex statement to match everything after sweets/ in the URL, it would be hugely appreciated.
To do what you ask you need to use groups. In regular expression groups allow you to isolate parts of the whole match.
for example:
input string of: aaaaaaaabbbbcccc
regex: a*(b*)
The parenthesis mark a group in this case it will be group 1 since it is the first in the pattern.
Note: group 0 is implicit and is the complete match.
So the matches in my above case will be:
group 0: aaaaaaaabbbb
group 1: bbbb
In order to achieve what you want with the sweets pattern above, you just need to put a group around the end.
possible solution: /sweets/(.*)
the more precise you are with the pattern before the group the less likely you will have a possible false positive.
If what you really want is to match anything after the last / you can take another approach:
possible other solution: /([^/]*)
The pattern above will find a / with a string of characters that are NOT another / and keep it in group 1. Issue here is that you could match things that do not have sweets in the URL.
Note if you do not mind the / at the beginning then just remove the ( and ) and you do not have to worry about groups.
I like to use http://regexpal.com/ to test my regex.. It will mark in different colors the different matches.
Hope this helps.
I may have misunderstood you requirement in my original post.
if you just want to change any string that matches
(http://)localhost/sweettemptations/sweets/*
into the other one you provided (without adding the part match by your * at the end) I would use a regular expression to match the pattern in the URL but them just blind replace the whole string with the desired one:
(http://)localhost/sweettemptations/available-sweets
So if you want the URL:
http://localhost/sweettemptations/sweets/somethingmore.html
to turn into:
http://localhost/sweettemptations/available-sweets
and not into:
localhost/sweettemptations/available-sweets/somethingmore.html
Then the solution is simpler, no groups required :).
when doing this I would make sure you do not match the "localhost" part. Also I am assuming the (http://) really means an optional http:// in front as (http://) is not a valid protocol prefix.
so if that is what you want then this should match the pattern:
(http://)?[^/]+/sweettemptations/sweets/.*
This regular expression will match the http:// part optionally with a host (be it localhost, an IP or the host name). You could omit the .* at the end if you want.
If that pattern matches just replace the whole URL with the one you want to redirect to.
use this regular expression (?<=://).+