Django : Update ImageField from OneToOne relation - django

Question

After several hours to try to update a ImageField in the views.py, I need your helps :
MODEL :
class ImageTeam(models.Model):
image = models.ImageField(upload_to="imageTeam/", null=False)
team = models.OneToOneField(Team,on_delete=models.CASCADE,related_name="theImage", null=False)
VIEW :
def update_team(request, idTeam):
try :
team = Team.objects.get(id = idTeam)
except Team.DoesNotExist :
return redirect(teams)
...
if request.method == "POST" :
form = updateTeamForm(request.POST, request.FILES)
if form.is_valid() and form.has_changed() :
team.name = form.cleaned_data["name"]
...
imageForm = form.cleaned_data["image"]
if imageForm :
if hasattr(team, 'theImage') :
team.theImage.image = imageForm
print(team.theImage.image) #Good it prints "<ImageFieldFile: imageName.jpg>"
team.theImage.save() #save doesn't works!
print(team.theImage.image) #Bad it prints "<ImageFieldFile: None>"
else :
#works!
ImageTeam.objects.create(image = imageForm, team=team)
...
TEMPLATE :
<form method="POST" enctype="multipart/form-data" action="{% url 'update_team' team.id %}" class="form-signin">
{% csrf_token %}
...
<div class="row">
{{ form.image }}
</div>
...
FORM :
class updateTeamForm(forms.ModelForm):
image = forms.ImageField(widget=forms.ClearableFileInput(attrs={'id':'image_team'}))
...
class Meta :
model = Team
exclude = ['image',...]
I have tried many solutions (get the instance and save it, use request.FILES['image'], write directly in path...)
So why the imageField is not updated ?
I will very happy if I can fix this problem today

Answer 1

I think problem here is that imageForm = form.cleaned_data["name"]. ImageForm is not 'image'. If you want to store file, you need to get the file.
form.cleaned_data['image'] is what you need here. Also, I don't see any form field name so for sure the save is not going to work.
Also, good technique to debug these kinds of scenarios is do you a debugger like ipdb. Just put import ipdb; ipdb.set_trace() in the top of your function and step through the code during execution time.
Hope this helps!