How to retrieve data from one to many relations in django? - django

Question

I am making my personal website using django 1.10
Here is models of skill app:
from __future__ import unicode_literals
from django.db import models
# Create your models here.
class Skill(models.Model):
name = models.CharField(max_length=256)
created_at = models.DateTimeField(auto_now=False, auto_now_add=True)
updated_at = models.DateTimeField(auto_now=True, auto_now_add=False)
def __unicode__(self):
return self.name
def __str__(self):
return self.name
class Subskill(models.Model):
skill = models.ForeignKey(Skill, on_delete=models.CASCADE)
name = models.CharField(max_length=256)
link = models.CharField(max_length=256)
created_at = models.DateTimeField(auto_now=False, auto_now_add=True)
updated_at = models.DateTimeField(auto_now=True, auto_now_add=False)
def __unicode__(self):
return self.name
def __str__(self):
return self.name
And view:
from django.shortcuts import render
from skill.models import Skill,Subskill
# Create your views here.
def home(request):
skill = Skill.objects.all()
subskill =Subskill.objects.all()
context = {'skills':skill,
'subskills':subskill}
return render(request, 'skill.html', context)
This is my template page:
skill.html
{% block skill %}
{% for subskill in subskills %}
{{subskill.skill.name}}
{{subskill.name}}
{% endfor %}
{% endblock skill %}
Let assume, there is a skill named web design which has two subskill named html and css.
I want to render in view page as like as skill name and it's two child name:
Web design
Html
CSS
But it renders as like Web design Html Web design CSS
Please help me about this issue.

Answer 1

You can do realted query on skill itself
https://docs.djangoproject.com/en/1.10/topics/db/queries/#backwards-related-objects
# example
skill_obj = Skill.objects.all()[0]
subskills = skill_obj.subskill_set.all()
Or in your case
def home(request):
skills = Skill.objects.all().prefetch_related('subskill_set') # optimizing
context = {'skills':skills}
return render(request, 'skill.html', context)
In template
{% for skill in skills %}
{{skill.name}}
{% for subskill in skill.subskill_set.all %}
{{subskill.name}}
{% endfor %}
{% endfor %}