Host should be a string error in ansible - vmware

Question

This is the error I get when I run this code.
[my-host]
19.3.112.97 ansible_ssh_pass=mypass ansible_ssh_user=root
The play book is
---
- hosts: localhost
connection: local
tasks:
- vsphere_guest:
guest: newvm001
vmware_guest_facts: yes
Error:
An exception occurred during task execution. The full traceback is:
Traceback (most recent call last): File
"/var/folders/zt/s5ykx9_n4y9611h_k_gj_vx00000gn/T/ansible_vYePRK/ansible_module_vsphere_guest.py",
line 1879, in
main() File "/var/folders/zt/s5ykx9_n4y9611h_k_gj_vx00000gn/T/ansible_vYePRK/ansible_module_vsphere_guest.py",
line 1748, in main
viserver.connect(vcenter_hostname, username, password) File "/Library/Python/2.7/site-packages/pysphere/vi_server.py", line 71, in
connect
,FaultTypes.PARAMETER_ERROR) pysphere.resources.vi_exception.VIException: [Parameter Error]: 'host'
should be a string with the ESX/VC url.
fatal: [9.1.142.86]: FAILED! => {"changed": false, "failed": true,
"invocation": {"module_name": "vsphere_guest"}, "module_stderr":
"Traceback (most recent call last):\n File
\"/var/folders/zt/s5ykx9_n4y9611h_k_gj_vx00000gn/T/ansible_vYePRK/ansible_module_vsphere_guest.py\",
line 1879, in \n main()\n File
\"/var/folders/zt/s5ykx9_n4y9611h_k_gj_vx00000gn/T/ansible_vYePRK/ansible_module_vsphere_guest.py\",
line 1748, in main\n viserver.connect(vcenter_hostname, username,
password)\n File
\"/Library/Python/2.7/site-packages/pysphere/vi_server.py\", line 71,
in connect\n
,FaultTypes.PARAMETER_ERROR)\npysphere.resources.vi_exception.VIException:
[Parameter Error]: 'host' should be a string with the ESX/VC url.\n",
"module_stdout": "", "msg": "MODULE FAILURE", "parsed": false}
Why do i get this error?

Answer 1

You are currently supplying two parameters to vsphere_guest, guest and vmware_guest_facts. However, the documentation lists several more parameters as being required:
password
username
vcenter_hostname
If I had to guess, vcenter_hostname is defaulting to None (Python's null equivalent) and so the code that expects it to be a URI string throws the exception you see there.