This question already has answers here:
Regular Expression to describe Credit Card expiry (valid thru) date
(3 answers)
Closed 6 years ago.
I'm trying to find a regex pattern to validate credit card expiration date. The format is MM/YYYY
00/0000 -> Not accepted
02/0000 -> Not accepted
00/2016 -> Not accepted
02/2016 -> accepted
12/2016 -> acceptedenter code here
13/2016 -> Not accepted
the two number of the year must be 20
the year doesn't be under 2016
Any ideas?
thanks
You want this -- not that it's the only solution:
(0[1-9]|10|11|12)/20[0-9]{2}$
PS: This requires the -E tag if being used with grep.
PPS: This answer assumes that the expiration date is at the end of a line.
PPPS: If you want an explanation, give me a ring. :)
Related
This question already has answers here:
Regex to match Date
(7 answers)
Closed 2 years ago.
I made a google forms which i asked a date of birth like dd/mm/yyyy.
I'm looking for a RegEx that allow every date from 01/01/1900 to 31/12/2015 but refuse every date who contains this 5 years 2016, 2017, 2018, 2019, 2020.
Does someone have an idea ?
Thanks for help.
If you really only want to check dates for years 1900-2015, it suffices to code
\b(\d{1,2}/\d{1,2}/(19\d{2}|200\d|201[0-5]))\b
The \b...\b bound is less restrictive than ^...$
Because the previous answer did not specify any year bounds, they need to be added, for example, 1900…2099 (excluding 2016-2020)
\b(?!2016|2017|2018|2019|2020)(\d{1,2}/\d{1,2}/(19|20)\d{2})\b
This question already has an answer here:
Reference - What does this regex mean?
(1 answer)
Closed 4 years ago.
I have a series of dates that I am trying to separate into years, months and days. These dates are in the yyyy-mm-dd format. I'm not very familiar with RegEx, but I have tried (\dddd)\-(\dd)\-(\dd).
Any help is appreciated.
Accepted answer would also match invalid dates like 1234-56-78, or if mm & dd were in the wrong positions.
([1-2][0-9]{3})\-([0-1][0-9])\-([0-3][0-9])
Does a little more validation.
i have a dataframe with entries looking like:
"Wittmann 2014 100 Hills Dry Riesling (Rheinhessen)" and
"Hazlitt 1852 Vineyards 2013 Riesling (Finger Lakes)"
I need to extract the years (vintage of the wine) out of the String, but only the years from 2012 till 2015...
Would be nice if someone can help me find the right code/regex in R.
Maybe this regex will work for you:
/(\b201[2-5]\b)/g
Try it online
This regular expression (posted on here as an answer) is supposed to handle dd/MM/yyyy with leap years included but it doesn't handle day 19 for some reason.
What is needs to be changed to fix this?
(^(((0[1-9]|[12][0-8])[\/](0[1-9]|1[012]))|((29|30|31)[\/](0[13578]|1[02]))|((29|30)[\/](0[4,6,9]|11)))[\/](19|[2-9][0-9])\d\d$)|(^29[\/]02[\/](19|[2-9][0-9])(00|04|08|12|16|20|24|28|32|36|40|44|48|52|56|60|64|68|72|76|80|84|88|92|96)$)
Fixed it for you
Changed "[12][0-8]" <-- doesn't include 19 to "1[0-9]|2[0-8]"
"(^(((0[1-9]|1[0-9]|2[0-8])[\/](0[1-9]|1[012]))|((29|30|31)[\/](0[13578]|1[02]))|((29|30)[\/](0[4,6,9]|11)))[\/](19|[2-9][0-9])\d\d$)|(^29[\/]02[\/](19|[2-9][0-9])(00|04|08|12|16|20|24|28|32|36|40|44|48|52|56|60|64|68|72|76|80|84|88|92|96)$)"
I found this one validates 2320 and 3000 as non leap years correctly.
^(((0[1-9]|[12]\d|3[01])\/(0[13578]|1[02])\/((19|[2-9]\d)\d{2}))|((0[1-9]|[12]\d|30)\/(0[13456789]|1[012])\/((19|[2-9]\d)\d{2}))|((0[1-9]|1\d|2[0-8])\/02\/((19|[2-9]\d)\d{2}))|(29\/02\/((1[6-9]|[2-9]\d)(0[48]|[2468][048]|[13579][26])|((16|[2468][048]|[3579][26])00))))$
I need serious help building two Regex statements for a project. The software we're using ONLY accepts Regex for validation.
I need one that fires for any date <4/1/2009
and a second that fires for any date <10/1/2009
My co-worker gave me the following code to check for <=10/01/2010, but it checks leap years and all that stuff. I need something a little more streamlined than this in the MM/DD/YYYY format. Thanks in advance!
^(?:(?:0?[1-9])|(?:1[0-2]))(\/|-|\.)(?:0?[1-9]|1\d|2[0-8])(\/|-|\.)(?:2[0-9][2-9][0-9])$|^(?:(?:0?[1-9])|(?:1[0-2]))(\/|-|\.)(?:0?[1-9]|1\d|2[0-8])(\/|-|\.)(?:201[1-9])$|^(?:(?:(?:0?[13578]|1[02])(\/|-|\.)31)|(?:(?:0?[1,3-9]|1[0-2])(\/|-|\.)(?:29|30)))(\/|-|\.)(?:201[1-9])$|^(?:(?:(?:11)(\/|-|\.))(?:0?[1-9]|1\d|2[0-9]|30)(\/|-|\.))(2010)$|^(?:(?:(?:10|12)(\/|-|\.))(?:0?[1-9]|1\d|2[0-9]|30|31)(\/|-|\.))(2010)$|^(?:(?:0?[1-9])|(?:1[0-2]))(\/|-|\.)(?:0?[1-9]|1\d|2[0-8])(\/|-|\.)(?:2[0-9][2-9][0-9])$|^(?:(?:(?:0?[13578]|1[02])(\/|-|\.)31)\1|(?:(?:0?[1,3-9]|1[0-2])(\/|-|\.)(?:29|30)))(\/|-|\.)(?:2[0-9][2-9][0-9])$|^(?:(?:0?[1-9])|(?:1[0-2]))(\/|-|\.)(?:0?[1-9]|1\d|2[0-8])(\/|-|\.)(?:2011)$|^(?:0?2(\/|-|\.)29\3(?:(?:(?:2[0-9][1-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))$
^(?:(?:0?2/(?:[12][0-9]|0?[1-9])|0?[13]/(?:3[01]|[12][0-9]|0?[1-9]))/2009|(?:0?2/(?:[12][0-9]|0?[1-9])|(?:0?[469]|11)/(?:30|[12][0-9]|0?[1-9])|(?:0?[13578]|1[02])/(?:3[01]|[12][0-9]|0?[1-9]))/(?:200[0-8]|19[0-9]{2}))$
will match any date between 1/1/1900 and 3/31/2009, ignoring leap years but otherwise matching only valid dates;
^(?:(?:0?2/(?:[12][0-9]|0?[1-9])|0?[469]/(?:30|[12][0-9]|0?[1-9])|0?[13578]/(?:3[01]|[12][0-9]|0?[1-9]))/2009|(?:0?2/(?:[12][0-9]|0?[1-9])|(?:0?[469]|11)/(?:30|[12][0-9]|0?[1-9])|(?:0?[13578]|1[02])/(?:3[01]|[12][0-9]|0?[1-9]))/(?:200[0-8]|19[0-9]{2}))$
does the same for 1/1/1900-9/30/2009.
EDIT: It looks like "firing" means "not matching" in your question. So
^(?:(?:(?:0?[469]|11)/(?:30|[12][0-9]|0?[1-9])|(?:0?[578]|1[02])/(?:3[01]|[12][0-9]|0?[1-9]))/2009|(?:0?2/(?:[12][0-9]|0?[1-9])|(?:0?[469]|11)/(?:30|[12][0-9]|0?[1-9])|(?:0?[13578]|1[02])/(?:3[01]|[12][0-9]|0?[1-9]))/(?:[3-9][0-9]{2}|2[1-9][0-9]|20[1-9])[0-9])$
will match any date from 4/1/2009 onwards, and
^(?:(?:11/(?:30|[12][0-9]|0?[1-9])|1[02]/(?:3[01]|[12][0-9]|0?[1-9]))/2009|(?:0?2/(?:[12][0-9]|0?[1-9])|(?:0?[469]|11)/(?:30|[12][0-9]|0?[1-9])|(?:0?[13578]|1[02])/(?:3[01]|[12][0-9]|0?[1-9]))/(?:[3-9][0-9]{2}|2[1-9][0-9]|20[1-9])[0-9])$
will match any date from 10/1/2009 onwards.
All regexes created using RegexMagic.