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I want to match the following with multiple capture groups:
Definition 1
: This is the definition text that described the term. Can have markdown formatting and
multiple lines.
Definition 2
: This is the definition text with **markdown**.`code`
I also want to replace it with the following text (HTML definition list):
<dl>
<dt>Definition 1</dt>
<dd>This is the definition text that described the term. Can have markdown formatting and
multiple lines.</dd>
<dt>Definition 1</dt>
<dd>This is the definition text with **markdown**.`code`</dd>
</dl>
You could do this in two steps:
1. Insert the dt and dd tags
Perform a search with:
(.*)\R: ((?:.+(?:\R|$))*?)(?=\R|.*\R:|$)/g
and substitute by:
<dt>$1</dt>\n<dd>$2</dd>\n
See regex tester.
2. Add the dl tags
Use the result of the previous substitution and perform the following search:
/(<dt>.*?<\/dd>(?!\s*<dt>))/gs
and substitute by:
<dl>\n$1\n</dl>
See regex tester.
Remarks
If the \R escape is not supported, use \n instead.
The back-references $1, $2 might need to be changed to \1, \2 depending on your regex engine.
Related
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I want to extract the words in given string which are start with '#' in notepad++. Can any one provide your suggestions/solutions?
Here is the string:
#Data is a convenient shortcut annotation that bundles the features of #ToString, #EqualsAndHashCode, #Getter / #Setter and #RequiredArgsConstructor together: In other words
Using Notepad++:
Refer to this answer: Regular expressions in notepad++ (Search and Replace). Open up "Find and Replace" menu. Set search mode to "Regular expression". Then search for your regular expression #\w+ in the "Find what" field.
Another option is to use Python:
Try the re Python module to extract the words from the variable using the same regular expression pattern. The regular expression pattern #\w+ matches any word starting with # followed by one or more word characters.
import re
string = "#Data is a convenient shortcut annotation that bundles the features of #ToString, #EqualsAndHashCode, #Getter / #Setter and #RequiredArgsConstructor together: In other words"
matches = re.findall(r'#\w+', string)
print(matches)
Outputs:
['#Data', '#ToString', '#EqualsAndHashCode', '#Getter', '#Setter', '#RequiredArgsConstructor']
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Please can somebody help me, I`m new to regex and have no idea how to do this!.
I`m trying to extract from a list which looks like this...
Joe-Age23-46737-251.aspx
Tim-Age18-46909-451.aspx
Roger-Age41-59768-251.aspx
What I want is this...
46737-251.aspx
46909-451.aspx
59768-251.aspx
so basically anything after the second to last hyphen.
Cheers
Let's translate "everything after the second-to-last hyphen" into regex:
(?<=-)[^-]*-[^-]*$
Explanation:
(?<=-) # Assert starting position right after a hyphen
[^-]* # Match zero or more characters except hyphens
- # Match a single hyphen
[^-]* # see above
$ # until end of string.
Test it live on regex101.com.
Step1 : Split the string on the basis of hyphen(-) . You will get array of strings.
Step2 : extract the second , fifth and eighth
and so on( incremented by 3 ).
Step3 : concatinate all the strings formed in step2.
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Writing a script to convert a Windows host file into a CSV. Used RegEx to get to this stage:
1.1.1.1,,server1,,,
2.2.2.2,,server2
3.3.3.3,,server3
4.5.6.7,,server4,,server5,,server6,,server7,,
8.8.8.8,,server8
9.9.9.9,server9
I need some RegEx that can remove the duplicate commas (in sequence) so it would look like this:
1.1.1.1,server1,
2.2.2.2,server2
3.3.3.3,server3
4.5.6.7,server4,server5,server6,server7,
8.8.8.8,server8
9.9.9.9,server9
Will also need to remove the comma at the end of each line (if there is one) but think this will be simpler to do.
The regex for your first task of removing duplicate commas was already provided in the comments above, but if you also want to remove trailing commas at the end of the line, you can use this to solve both problems at once:
(?m),(?=,|$)
Explanation:
(?m) # turn on multiline mode ($ matches end-of-line, not just end-of-string)
, # Match a comma
(?= # only if followed by
, # another comma
| # or
$ # the end of the string.
) # End of lookahead assertion
Test it live on regex101.com.
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I cannot figure out how to match only on groups that contain a certain word ('test' for example below). It is a big text file and the groups start with a line 'Group x' and include text with an empty line separation to the next group. I think I need to use lookaheads and lookbehinds but don't know how. I can use vb.net for this but trying to test out different expressions in the regex testers and can't get anywhere.
Group 1
adfdf
dd test ddfdf
dfdfadf
Group 2
ddfadfa
Group 3
add test
adfdff
Group 4
adfdf
Expected 2 matches:
Group 1
adfdf
dd test ddfdf
dfdfadf
Group 3
add test
adfdff
Start your pattern with ^Group \d+$ and end with (?:^$|\Z). In the middle match test but not preceeded by an empty line $(?:.(?!^$) (see Regular expression to match a line that doesn't contain a word? for details on how the latter works). Don't forget the m and s modifiers:
^Group \d+$(?:.(?!^$))*?test.*?(?:^$|\Z)
Demo: https://regex101.com/r/kM9qB3/2
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I want to be able to match all of the following strings to my regex below. It doesnt seem to be working. Any suggestions?
Strings to compare :
5878ce43aa3f1e1d713427d118115310 -1 Script Kiddie <perm>
f939f88b50fa5f0099b6751e7be27761 -1 Hacking <perm>
468f6634c5a9b00b5b3872dd6437143f 1356474103 Being Annoying <7day>
This is my perl code. It isnt working at the moment. Any suggestions?
my $bn_re = q{(.+?) (\d+) (.+?)};
If the first two fields are always without whitespace in them, you can use split to great effect, using the LIMIT option to only get three fields:
my ($str, $num, $other) = split ' ', $_, 3;
That is, assuming you read the file something like this:
while (<>) {
... # your code here
}
Also, this:
my $bn_re = q{(.+?) (\d+) (.+?)};
is not a regex. You may be confusing q() with qr(). You may also be confusing the functionality of
$str =~ $bn_re;
Which will automagically include the regex in a match operator m//. But you should use qr(). The q() operator does what the single quote does.
Also, you should be aware that .+? will match a single char if you allow it. As it does at the end of your "regex". At the end of your string, either do
... (.+)/ # matching greedily
... (.+?)$/ # using anchor to end of string
$bn_re =~ /[0-9a-z]+?\s[-0-9]+\s[\w\s]+?[<>a-z0-9]+?/i