Check space in a string in two loops - c++

Question

In the proccess of creating a user register, I see a double do {} while loop with a same condition. The condition is if detected a space in the strings, the reading will not become available.
void createAccount()
{
unsigned short int i = 0;
bool space = false;
cin.ignore();
cout << "FIRST NAME: ";
getline(cin, fullName[0]);
do {
cout << "MIDDLE NAME: ";
getline(cin, fullName[1]);
for (i = 0; i < fullName[1].size(); i++)
{
if (fullName[i][1] == 32) {
space = true;
break;
}
else {
space = false;
break;
}
}
} while(space);
/*Reset values for the same loop again (I would not like to write 2 times all of this)
i is reseted at loop-for, which helps.*/
space = false;
do {
cout << "MIDDLE NAME: ";
getline(cin, fullName[1]);
for (i = 0; i < fullName[1].size(); i++)
{
if (fullName[i][1] == 32) {
space = true;
break;
}
else {
space = false;
break;
}
}
} while(space);
fullName[3] = fullName[0] + string(" ") + fullName[1] + string(" ") + fullName[2];
}
I really don't know how can I put this together in a same loop. I'm mind broken.
#edit: I'm roger that the right thing is to put fullName[1][i] and that the breaks conditions are wrong.
#edit²: The result:
class BankAccount
{
private:
string fullName[5];
char accountAddress[10];
unsigned short int cards;
float money;
bool visa, mastercard, americanExpress;
void checkName(string name, string typeName, bool exception)
{
unsigned short int errorVar, i;
errorVar = i = 0;
bool space = false;
do {
if (errorVar > 0)
cout << "Enter only the name purposed." << endl << endl;
if (exception)
cout << typeName << " NAME (type no if you haven't): ";
else
cout << typeName << " NAME: ";
getline(cin, name);
for (i = 0; i < name.size(); i++)
{
if (name[i] == ' ')
{
space = true;
break;
}
else
space = false;
}
errorVar++;
} while (space);
if (name.compare("no") == 0)
name = "NULL";
}
public:
void createAccount()
{
cout << endl << "FIRST NAME: "; /* First name has no checks (it can be a compound name) */
getline(cin, this->fullName[0]);
checkName(this->fullName[1], "SECOND", false);
checkName(this->fullName[2], "THIRD", true);
checkName(this->fullName[3], "LAST", false);
if (this->fullName[2].compare("NULL") == 0)
{
this->fullName[4] = this->fullName[0] + string(" ") + this->fullName[1] + string(" ") + this->fullName[3]; //NOT FULL NAME
cout << this->fullName[4];
}
else
{
this->fullName[4] = this->fullName[0] + string(" ") + this->fullName[1] + string(" ") + this->fullName[2] + string(" ") + this->fullName[3]; //NOT FULL NAME
cout << this->fullName[4];
}
}
BankAccount() {/* Constructor */}
~BankAccount() {/* Deconstructor */}
};
Logically it's a simple stuff. Thanks for helping and improve the code also in other areas.

Answer 1

The obvious and clean solution is to put the do-loop in a function (or method), and call it twice, once with fullname[1] and then again with fullname[2].