I have a data which is being fed in the below format -
2016-006-011 04:58:22.058
This is an incorrect date/timestamp format and in order to convert this to a right one as below -
2016-06-11 04:58:22.058
I'm trying to achieve this using regex in redshift. Is there a way to remove the additional Zero(0) in the date and month portion using regex. I need something more generic and not tailed for this example alone as date will vary.
The function regexp_replace() (see documentation) should do the trick:
select
regexp_replace(
'2016-006-011 04:58:22.058' -- use your date column here instead
, '\-0([0-9]{2}\-)0([0-9]{2})' -- matches "-006-011", captures "06-" in $1, "11" in $2
, '-$1$2' -- inserts $1 and $2 to give "-06-11"
)
;
And so the result is, as required:
regexp_replace
-------------------------
2016-06-11 04:58:22.058
(1 row)
Related
I'm trying to use the BigQuery function regexp_replace for the following scenario:
Given a string field with comma as a delimiter, I need to only remove the commas within double quotes.
I found the following regex to work in the website but it seems that the BigQuery function doesn't support Lookahead groups. Could you please help me find an equivalent expression that is supported by the Big Query function regexp_replace?
https://regex101.com/r/nxkqtb/3
Big Query example code not supported:
WITH tbl AS (
SELECT 'LINE_NR="1",TXT_FIELD="Some text",CID="0"' as text
UNION ALL
SELECT 'LINE_NR="2",TXT_FIELD=",,Some text",CID="0"' as text
UNION ALL
SELECT 'LINE_NR="3",TXT_FIELD="Some text ,",CID="0"' as text
UNION ALL
SELECT 'LINE_NR="4",TXT_FIELD=",Some ,text,",CID="0"' as text
)
SELECT
REGEXP_REPLACE(text, r'(?m),(?=[^"]*"(?:[^"\r\n]*"[^"]*")*[^"\r\n]*$)', "")
FROM tbl;
Thank you
Consider below approach (assuming you know in advance keys within the text field)
select text,
( select string_agg(replace(kv, ',', ''), ',' order by offset)
from unnest(regexp_extract_all(text, r'((?:LINE_NR|TXT_FIELD|CID)=".*?")')) kv with offset
) corrected_text
from tbl;
if applied to sample data in your question - output is
I've some URL's in my cas_fnd_dwd_det table,
casi_imp_urls cas_code
----------------------------------- -----------
www.casiac.net/fnds/CASI/qnxp.pdf
www.casiac.net/fnds/casi/as.pdf
www.casiac.net/fnds/casi/vindq.pdf
www.casiac.net/fnds/CASI/mnip.pdf
how do i copy the letters between last '/' and '.pdf' to another column
expected outcome
casi_imp_urls cas_code
----------------------------------- -----------
www.casiac.net/fnds/CASI/qnxp.pdf qnxp
www.casiac.net/fnds/casi/as.pdf as
www.casiac.net/fnds/casi/vindq.pdf vindq
www.casiac.net/fnds/CASI/mnip.pdf mnip
the below URL's are static
www.casiac.net/fnds/CASI/
www.casiac.net/fnds/casi/
Advise, how do i select the codes between last '/' and '.pdf' ?
I would recommend to take a look at REGEXP_SUBSTR. It allows to apply a regular expression. Db2 has string processing functions, but the regex function may be the easiest solution. See SO question on regex and URI parts for different ways of writing the expression. The following would return the last slash, filename and the extension:
SELECT REGEXP_SUBSTR('http://fobar.com/one/two/abc.pdf','\/(\w)*.pdf' ,1,1)
FROM sysibm.sysdummy1
/abc.pdf
The following uses REPLACE and the pattern is from this SO question with the pdf file extension added. It splits the string in three groups: everything up to the last slash, then the file name, then the ".pdf". The '$1' returns the group 1 (groups start with 0). Group 2 would be the ".pdf".
SELECT REGEXP_REPLACE('http://fobar.com/one/two/abc.pdf','(?:.+\/)(.+)(.pdf)','$1' ,1,1)
FROM sysibm.sysdummy1
abc
You could apply LENGTH and SUBSTR to extract the relevant part or try to build that into the regex.
For older Db2 versions than 11.1. Not sure if it works for 9.5, but definitely should work since 9.7.
Try this as is.
with cas_fnd_dwd_det (casi_imp_urls) as (values
'www.casiac.net/fnds/CASI/qnxp.pdf'
, 'www.casiac.net/fnds/casi/as.pdf'
, 'www.casiac.net/fnds/casi/vindq.pdf'
, 'www.casiac.net/fnds/CASI/mnip.PDF'
)
select
casi_imp_urls
, xmlcast(xmlquery('fn:replace($s, ".*/(.*)\.pdf", "$1", "i")' passing casi_imp_urls as "s") as varchar(50)) cas_code
from cas_fnd_dwd_det
I am using BigQuery on Google Cloud Platform to extract data from GDELT. This uses an SQL syntax and regular expressions.
I have a column of data (called V2Tone), in which each cell looks like this:
1.55763239875389,2.80373831775701,1.24610591900312,4.04984423676012,26.4797507788162,2.49221183800623,299
To select only the first number (i.e., the number before the first comma) using regular expressions, we use this:
regexp_replace(V2Tone, r',.*', '')
How can we select only the second number (i.e., the number between the first and second commas)?
How about the third number (i.e., the number between the second and third commas)?
I understand that re2 syntax (https://github.com/google/re2/wiki/Syntax) is used here, but my understanding of how to put that all together is limited.
If anything is unclear, please let me know. Thank you for your help as I learn to use regular expressions.
Below example is for BigQuery Standard SQL using super simple SPLIT approach
#standardSQL
SELECT
SPLIT(V2Tone)[SAFE_OFFSET(0)] first_number,
SPLIT(V2Tone)[SAFE_OFFSET(1)] second_number,
SPLIT(V2Tone)[SAFE_OFFSET(2)] third_number
FROM `project.dataset.table`
If for some reason you need/want to use regexp here - use below
#standardSQL
SELECT
REGEXP_EXTRACT(V2Tone, r'^(.*?),') first_number,
REGEXP_EXTRACT(V2Tone, r'^(?:(?:.*?),)(.*?),') second_number,
REGEXP_EXTRACT(V2Tone, r'^(?:(?:.*?),){2}(.*?),') third_number,
REGEXP_EXTRACT(V2Tone, r'^(?:(?:.*?),){4}(.*?),') fifth_number
FROM `project.dataset.table`
Note use of REGEXP_EXTRACT instead of REGEXP_REPLACE
You can play, test above options with dummy string from your question as below
#standardSQL
WITH `project.dataset.table` AS (
SELECT '1.55763239875389,2.80373831775701,1.24610591900312,4.04984423676012,26.4797507788162,2.49221183800623,299' V2Tone
)
SELECT
SPLIT(V2Tone)[SAFE_OFFSET(0)] first_number,
SPLIT(V2Tone)[SAFE_OFFSET(1)] second_number,
SPLIT(V2Tone)[SAFE_OFFSET(2)] third_number,
REGEXP_EXTRACT(V2Tone, r'^(.*?),') first_number_re,
REGEXP_EXTRACT(V2Tone, r'^(?:(?:.*?),)(.*?),') second_number_re,
REGEXP_EXTRACT(V2Tone, r'^(?:(?:.*?),){2}(.*?),') third_number_re,
REGEXP_EXTRACT(V2Tone, r'^(?:(?:.*?),){4}(.*?),') fifth_number_re
FROM `project.dataset.table`
with output :
first_number second_number third_number first_number_re second_number_re third_number_re fifth_number_re
1.55763239875389 2.80373831775701 1.24610591900312 1.55763239875389 2.80373831775701 1.24610591900312 26.4797507788162
I don't know of a single regex replace which could be used to isolate a single number in your CSV string, because we need to remove things on both sides of the match, in general. But, we can chain together two calls to regex_replace. For example, if you wanted to target the third number in the CSV string, we could try this:
regexp_replace(regexp_replace(V2Tone, r'^(?:(?:\d+(?:\.\d+)?),){2}', ''),
r',.*', ''))
The pattern I am using to strip of the first n numbers is this:
^(?:(?:\d+(?:\.\d+)?),){n}
This just removes a number, followed by a comma, n times, from the beginning of the string.
Demo
Here is a solution with a single regex replace:
^([^,]+(?:,|$)){2}([^,]+(?:,|$))*|^.*$
Demo
\n is added to the negated character class in the demo to avoid matching accross lines in m|multiline mode.
Usage:
regexp_replace(V2Tone, r'^([^,]+(?:,|$)){2}([^,]+(?:,|$))*|^.*$', '$1')
Explanation:
([^,]+(?:,|$){n} captures everything to the next comma or the end of the string n times
([^,]+(?:,|$))* captures the rest 0 or more times
^.*$ capture everything if we cannot match n times
And then, finally, we can reinsert the nth match using $1.
I am trying to extract all occurrences of a word before '=' in a string, i tried to use this regex '/\w+(?=\=)/g' but it returns null, when i remove the first '/' and the last '/g' it returns only one occurrence that's why i need the global flag, any suggestions?
As Wiktor pointed out, by default, you only get the first string in a REGEXP_SUBSTR() call. But you can get the second, third, fourth, etc.
Embedded into SQL, you need to treat regular expressions differently from the way you would treat them in perl, for example. The pattern is just the pattern, modifiers go elsewhere, you can't use $n to get the n-th captured sub-expression, and you need to proceed in a specific way to get the n-th match of a pattern, etc.
The trick is to CROSS JOIN your queried table with an in-line created index table, consisting of as many consecutive integers as you expect occurrences of your pattern - and a few more for safety. And Vertica's REGEXP_SUBSTR() call allows for additional parameters to do that. See this example:
WITH
-- one exemplary input row; concatenating substrings for
-- readability
input(s) AS (
SELECT 'DRIVER={Vertica};COLUMNSASCHAR=1;CONNECTIONLOADBALANCE=True;'
||'CONNSETTINGS=set+search_path+to+public;DATABASE=sbx;'
||'LABEL=dbman;PORT=5433;PWD=;SERVERNAME=127.0.0.1;UID=dbadmin;'
)
,
-- an index table to CROSS JOIN with ... maybe you need more integers ...
loop_idx(i) AS (
SELECT 1
UNION SELECT 2
UNION SELECT 3
UNION SELECT 4
UNION SELECT 5
UNION SELECT 6
UNION SELECT 7
UNION SELECT 8
UNION SELECT 9
UNION SELECT 10
)
,
-- the query containing the REGEXP_SUBSTR() call
find_token AS (
SELECT
i -- the index from the in-line index table, needed
-- for ordering the outermost SELECT
, REGEXP_SUBSTR (
s -- the input string
, '(\w+)=' -- the pattern - a word followed by an equal sign; capture the word
, 1 -- start from pos 1
, i -- the i-th occurrence of the match
, '' -- no modifiers to regexp
, 1 -- the first and only sub-pattern captured
) AS token
FROM input CROSS JOIN loop_idx -- the CROSS JOIN with the in-line index table
)
-- the outermost query filtering the non-matches - the empty strings - away...
SELECT
token
FROM find_token
WHERE token <> ''
ORDER BY i
;
The result will be one row per found pattern:
token
DRIVER
COLUMNSASCHAR
CONNECTIONLOADBALANCE
CONNSETTINGS
DATABASE
LABEL
PORT
PWD
SERVERNAME
UID
You can do all sorts of things in modern SQL - but you need to stick to the SQL and to the relational paradigm - that's all ...
Happy playing ...
Marco
please, I have in Oracle table this texts (as 2 records)
"Sample text with replace parameter %1%"
"You reached 90% of your limit"
I need replace %1% with specific text from input parameter in Oracle Function. In fact, I can have more than just one replace parameters. I have also record with "Replace this %12% with real value"
This functionality I have programmed:
IF poc > 0 THEN
FOR i in 1 .. poc LOOP
p := get_param(mString => mbody);
mbody := replace(mbody,
'%' || p || '%', parameters(to_number(p, '99')));
END LOOP;
END IF;
But in this case I have problem with text number 2. This functionality trying replace "90%" also and I then I get this error:
ORA-06502: PL/SQL: numeric or value error: NULL index table key value
It's a possible to avoid try replace "90%"? Many thanks for advice.
Best regards
PS: Oracle version: 10g (OCI Version: 10.2)
Regular expressions can work here. Try the following and build them into your script.
SELECT REGEXP_REPLACE( 'Sample text with replace parameter %1%',
'\%[0-9]+\%',
'db_size' )
FROM DUAL
and
SELECT REGEXP_REPLACE( 'Sample text with replace parameter 1%',
'\%[0-9]+\%',
'db_size' )
FROM DUAL
The pattern is pretty simple; look for patterns where a '%' is followed by 1 or more numbers followed by a '%'.
The only issue here will be if you have more than one replacement to make in each string and each replacement is different. In that case you will need to loop round the string each time replacing the next parameter. To do this add the position and occurrence parameters to REGEXP_REPLACE after the replacement string, e.g.
REGEXP_REPLACE( 'Sample text with replace parameter %88888888888%','\%[0-9]+\%','db_size',0,1 )
You are getting the error because at parameters(to_number(p, '99')). Can you please check the value of p?
Also, if the p=90 then then REPLACE will not try to replace "90%". It will replace "%90%". How have you been sure that it's trying to replace "90%"?