Powershell - Regex - Fixed width file - Escape Characters - regex

While reading a fixed width file like this:
ABC 7112123207/24/16Smith Timpson Head Coach 412-222-0000 00011848660 ELl CAAN HIGH SCHOOL 325 N Peal AVE. Smith Timpson Head Coach COLORADO CITY AZ 86021 01 FALL MALE 07/29/16EQ15031 1977904 BUDDY'S ALL STARS INC. BUDDY ALL STARS N V12V70R16 1.00V12V70R16
I wish to escape the single whitespace, / and the apostrophe.
I tried my regex in Powershell like this:
$Line | Select-String -Pattern "^(.*)[a-zA-Z0-9?\s?]" -AllMatches
I need the match values to read as:
ABC
12345607/24/16Joe (this split into three: 123456,07/24/16,Joe)
Smith
Head Trainer
Buddy's Box
I'm trying to add the slices to a csv assigning each one to a header. For instance:
$csh.USER_GROUP = $line.Substring(0,10).Trim()
$csh.ORDER_NUMBER = $line.Substring(10,8).Trim()
$csh.ORDER_ENTRY_DATE=$line.Substring(18,8).Trim()
$csh.CONTACT_FIRST=$line.Substring(26,35).Trim()
$csh.CONTACT_LAST=$line.Substring(61,35).Trim()
$csh.CONTACT_TITLE=$line.Substring(96,35).Trim()
$csh.CONTACT_EMAIL= $line.Substring(131,35).Trim()
$csh.CONTACT_PHONE=$line.Substring(166,20).Trim()
$csh.SCHOOL_ID=$line.Substring(186,15).Trim()
} | convertto-csv | select-object -skip 1 | out-file temp.csv
Now, given that there are empty spaces and repeating elements, it is erring that duplicate keys are not allowed. Is there an elegant alternative?

Match using two or more spaces as a delimiter:
if ($Line -match '(\S.*?) +(.{6})(.{8})(.*?) +(.*?) +(.*?) +(.*)') {
$whatsit = $matches[1]
$index = $matches[2]
$date = $matches[3]
$name1 = $matches[4]
$name2 = $matches[5]
$position = $matches[6]
$place = $matches[7]
} else {
echo "Bad line $Line"
}

Related

I want to split a string from : to \n in Powershell script

I am using a config file that contains some information as shown below.
User1:xyz#gmail.com
User1_Role:Admin
NAME:sdfdsfu4343-234324-ffsdf-34324d-dsfhdjhfd943
ID:xyz#abc-demo-test-abc-mssql
Password:rewrfsdv34354*fds*vdfg435434
I want to split each value from*: to newline* in my Powershell script.
I am using -split '[: \n]' it matches perfectly until there is no '' in the value. If there is an '*' it will fetch till that. For example, for Password, it matches only rewrfsdv34354. Here is my code:
$i = 0
foreach ($keyOrValue in $Contents -split '[: *\n]') {
if ($i++ % 2 -eq 0) {
$varName = $keyOrValue
}
else {
Set-Variable $varName $keyOrValue
}
}
I need to match all the chars after : to \n. Please share your ideas.
It's probably best to perform two separate splits here, it makes things easier to work out if the code is going wrong for some reason, although the $i % 2 -eq 0 part is a neat way to pick up key/value.
I would go for this:
# Split the Contents variable by newline first
foreach ($line in $Contents -split '[\n]') {
# Now split each line by colon
$keyOrValue = $line -split ':'
# Then set the variables based on the parts of the colon-split
Set-Variable $keyOrValue[0] $keyOrValue[1]
}
You could also convert to a hashmap and go from there, e.g.:
$h = #{}
gc config.txt | % { $key, $value = $_ -split ' *: *'; $h[$key] = $value }
Or with ConvertFrom-StringData:
$h = (gc -raw dims.txt) -replace ':','=' | ConvertFrom-StringData
Now you have convenient access to keys and values, e.g.:
$h
Output:
Name Value
---- -----
Password rewrfsdv34354*fds*vdfg435434
User1 xyz#gmail.com
ID xyz#abc-demo-test-abc-mssql
NAME sdfdsfu4343-234324-ffsdf-34324d-dsfhdjhfd943
User1_Role Admin
Or only keys:
$h.keys
Output:
Password
User1
ID
NAME
User1_Role
Or only values:
$h.values
Output:
rewrfsdv34354*fds*vdfg435434
xyz#gmail.com
xyz#abc-demo-test-abc-mssql
sdfdsfu4343-234324-ffsdf-34324d-dsfhdjhfd943
Admin
Or specific values:
$h['user1'] + ", " + $h['user1_role']
Output:
xyz#gmail.com, Admin
etc.

Powershell script using RegEx to look for a pattern in one .txt and find line in a second .txt

I have a real "headsmasher" on my plate.
I have this piece of script:
$lines = Select-String -List -Path $sourceFile -Pattern $pattern -Context 20
foreach ($id in $lines) {
if (Select-String -Quiet -LiteralPath export.txt -Pattern "$($Matches[1]).+$($id.Pattern)") {
}
else {
Select-String -Path $sourceFile -Pattern $pattern -Context 20 >> $duplicateTransactionsFile
}
}
but it is not working for me as I wanted it to.
I have two .txt files: "$sourcefile = source.txt" and "export.txt"
The source.txt looks like something like this:
Some text here ***********
------------------------------------------------
F I N A L C O U N T 1 9 , 9 9
**************
** [0000123456]
ID Number:0000123456
Complete!
****************!
***********
Some other text here*******
------------------------------------------------
F I N A L C O U N T 9 , 9 9
**********
** [0000789000]
ID Number:0000789000
Complete!
******************!
************
The export.txt is like this:
0000123456 19,99
0000555555 ,89
0000666666 3,05
0000777777 31,19
0000789000 9,99
What I am trying to do is look into source.txt and search for the number that I enter (spaced out in my case)
*e.g: "9,99" but only that. As you can see, the next number in the source.txt is "19,99" and it also contains "9,99" but I do not want it to be matched.
and once I find the number, look for the next line in the source.txt that contains the text "ID Number:" then get the numbers right after the ":" Once I get those numbers after the ":", I want to now look into the export.txt and see if the numbers after the ":" are there and whether it has the "9,99" on the same line next to it but exactly "9,99" and nothing else lie "19,99", "29,99", and so on.
Then the rest is easy:
if (*true*) {
do this
}
else {
do that
}
Could you guys give me some love here and help a brother out?
I very much appreciate any help or hint you could share.
Best of wishes!
You could approach this like below:
# read the export.txt file and convert to a Hashtable for fast lookup
$export = ((Get-Content -Path 'D:\Test\export.txt').Trim() -replace '\s+', '=') -join "`r`n" | ConvertFrom-StringData
# read the source file and split into multiline data blocks
$source = ((Get-Content -Path 'D:\Test\source.txt' -Raw) -split '-{2,}').Trim() | Where-Object { $_ -match '(?sm)^\s?F I N A L C O U N T' }
# make sure the number given is spaced-out
$search = (((Read-Host "Search for Final Count number") -replace '\s' -split '') -join ' ').Trim()
Write-Host "Looking for a matching item using Final Count '$search'"
# see if we can find a data block that matches the $search
$blocks = $source | Where-Object { $_ -match "(?sm)^F I N A L C O U N T\s+$search\s?$" }
if (!$blocks) {
Write-Host "No item in source.txt could be found with Final Count '$search'" -ForegroundColor Red
}
else {
# loop over the data block(s) and pick the one that matches the search count
$blocks | ForEach-Object {
# parse out the ID
$id = $_ -replace '(?sm).*ID Number:(\d+).*', '$1'
# check if the $export Hashtable contains a key with that ID number
if ($export.Contains($id)) {
# check if that item has a value of $search without the spaces
if ($export[$id] -eq ($search -replace '\s')) {
# found it; do something
Write-Host "Found a match in the export.txt" -ForegroundColor Green
}
else {
# found ID with different FinalCount
Write-Host "An item with ID '$id' was found, but with different Final Count ($($export[$id]))" -ForegroundColor Red
}
}
else {
# ID not found
Write-Host "No item with ID '$id' could be found in the export.txt" -ForegroundColor Red
}
}
}
If as per your comment, you would like the code to loop over the Final Count numbers found in the source.txt file instead of a user typing in a number to search for, you can shorten the above code to:
# read the export.txt file and convert to a Hashtable for fast lookup
$export = ((Get-Content -Path 'D:\Test\export.txt').Trim() -replace '\s+', '=') -join "`r`n" | ConvertFrom-StringData
# read the source file and split into multiline data blocks
$blocks = ((Get-Content -Path 'D:\Test\source.txt' -Raw) -split '-{2,}').Trim() |
Where-Object { $_ -match '(?sm)^\s?F I N A L C O U N T' }
if (!$blocks) {
Write-Host "No item in source.txt could be found with Final Count '$search'" -ForegroundColor Red
}
else {
# loop over the data block(s)
$blocks | ForEach-Object {
# parse out the FINAL COUNT number to look for in the export.txt
$search = ([regex]'(?sm)^F I N A L C O U N T\s+([\d,\s]+)$').Match($_).Groups[1].Value
# remove the spaces, surrounding '0' and trailing comma (if any)
$search = ($search -replace '\s').Trim('0').TrimEnd(',')
Write-Host "Looking for a matching item using Final Count '$search'"
# parse out the ID
$id = $_ -replace '(?sm).*ID Number:(\d+).*', '$1'
# check if the $export Hashtable contains a key with that ID number
if ($export.Contains($id)) {
# check if that item has a value of $search without the spaces
if ($export[$id] -eq $search) {
# found it; do something
Write-Host "Found a match in the export.txt with ID: $($export[$id])" -ForegroundColor Green
}
else {
# found ID with different FinalCount
Write-Host "An item with ID '$id' was found, but with different Final Count ($($export[$id]))" -ForegroundColor Red
}
}
else {
# ID not found
Write-Host "No item with ID '$id' could be found in the export.txt" -ForegroundColor Red
}
}
}
There are surely multiple valid ways to accomplish this. Here is my approach:
(See comments for explanations. Let me know if you have any questions)
param (
# You can provide this when calling the script using "-Search 9,99"
# If not privided, powershell will prompt to enter the value
[Parameter(Mandatory)]
$Search,
$Source = "source.txt",
$Export = "export.txt"
)
# insert spaces
$pattern = $Search.ToCharArray() -join " "
# Search for the value in the source file.
$found = $false
switch -Regex -File $Source {
# This regex looks for something that is not a number,
# followed by only whitespace, and then your (spaced) search value.
# This makes sure "19,99" is not matched with "9,99".
# You could use a more elaborate regex here, but for your example,
# this one should work fine.
"\D\s+$pattern" {
$found = $true
}
"ID Number:(\d+)" {
# Get the ID number from the match.
$id = $Matches[1]
# If the search value was found
# (that means, this ID number is immediately followed by the search value)
# we can stop looking.
if ($found) {
break
}
}
}
# quick check if the value was actually found
if (-not $found) {
throw "Value $Search not found in $Source."
}
# Search for the id in the export file.
switch -Regex -File $Export {
"$id\s+(\S+)" {
# Get the amount value from the match
$value = $Matches[1]
# If the value matches your search...
if ($value -eq $search) {
# do this
}
else {
# otherwise do that
}
break
}
}
Note: You could additionally convert the values to decimal to account for different text representations when searching and comparing.

PowerShell Regex with csv file

I'm currently trying to match a pattern of IDs and replace with 0 or 1.
example pc0045601234 replace with 1234 the last 4 and add the 3rd digit in front "01234"
I tried the code below but the out only filled the userid column with No matching employee
$reportPath = '.\report.csv'`$reportPath = '.\report.csv'`
$csvPath = '.\output.csv'
$data = Import-Csv -Path $reportPath
$output = #()
foreach ($row in $data) {
$table = "" | Select ID,FirstName,LastName,userid
$table.ID = $row.ID
$table.FirstName = $row.FirstName
$table.LastName = $row.LastName
switch -Wildcard ($row.ID)
{
{$row.ID -match 'P\d\d\d\d\d\D\D\D'} {$table.userid = "Contractor"; continue}
{$row.ID -match 'SEC\d\d\d\D\D\D\D'} {$table.userid = "Contractor"; continue}
{$row.ID.StartsWith("P005700477")} {$table.userid = $row.ID -replace "P005700477","0477"; continue}
{$row.ID.StartsWith("P00570")} {$table.userid = $row.ID -replace "P00570","0"; continue}
default {$table.userid = "No Matching Employee"}
}
$output += $table
}
$output | Export-csv -NoTypeInformation -Path $csvPath
Here are three different ways to achieve the desired result. The first two use the same technique, just written in a different way.
First we put the sample data in a variable as a multiline string array. This is the equivalent as $text = Get-Content $somefile
$text = #'
PC05601234
PC15601234
'# -split [environment]::NewLine
Option 1 # convert to character array, select the 3rd and last 4 digits.
$text | foreach {-join ($_.ToChararray()| select -Skip 2 -First 1 -Last 4)}
Option 2 # same as above, requiring an extra -join to avoid spaces.
$text | foreach {(-join $_.ToChararray()| foreach{$_[2]+(-join $_[-4..-1])})}
Option 3 # my preference, regex. Capture the desired digits and replace the entire string with those two captured values.
$text -replace '^\D+(?!=\d)(\d)\w+([\d]{4}$)','$1$2'
All of these output
01234
11234
Further testing with different char/digit combinations and lengths.
$text = #'
PC05601234
PC15601234
PC0ABC124321
PC1DE4321
PC0A5678
PC1ABCD215678
'# -split [environment]::NewLine
Running the new sample data through each option all produce this output
01234
11234
04321
14321
05678
15678

Capturing Regex in Powershell

I'm having a block solving this. I want to get all the URL's in the text that match my pattern. Should include the first parm of the URL, but not the second one.
Two issues:
It's not getting the first URL
I'm missing how the capture works.
In Method 1, I see the matches, but I don't see the capture text of what I put in parentheses. In Method 2, I see my captures on some outputs, but getting extra outputs that contain more than my capture. I like Method 2 style, but did Method 1 to try to understand what's happening, but just dug my self a deeper hole.
$fileContents = 'Misc Text < a href="http://example.com/Test.aspx?u=a1">blah blah</a> More Stuff blah blah Closing Text'
#Sample URL http://example.com/Test.aspx?u=a1&parm=123
$pattern = '<a href="(http://example.com/Test.aspx\?u=.*?)[&"]'
Write-Host "RegEx Pattern=$pattern"
Write-Host "----------- Method 1 --------------"
$groups = [regex]::Matches($fileContents, $pattern)
$groupnum = 0
foreach ($group in $groups)
{
Write-Host "Group=$groupnum URL=$group "
$capturenum = 0
foreach ($capture in $group.Captures)
{
Write-Host "Group=$groupnum Capture=$capturenum URL=$capture.value index=$($capture.index)"
$capturenum = $capturenum + 1
}
$groupnum = $groupnum + 1
}
Write-Host "----------- Method 2 --------------"
$urls = [regex]::Matches($fileContents, $pattern).Groups.Captures.Value
#$urls = $urls | select -Unique
Write-Host "Number of Matches = $($urls.Count)"
foreach ($url in $urls)
{
Write-Host "URL: $url "
}
Write-Host " "
Output:
----------- Method 1 --------------
Group=0 URL=<a href="http://example.com/Test.aspx?u=b2&
Group=0 Capture=0 URL=<a href="http://example.com/Test.aspx?u=b2&.value index=81
----------- Method 2 --------------
Number of Matches = 2
URL: <a href="http://example.com/Test.aspx?u=b2&
URL: http://example.com/Test.aspx?u=b2
Powershell Version 5.1.17763.592
I'm missing how the capture works.
Capture group 0 is always the entire match - unnamed capture groups will be numbered 1 through 9, so you'll want group 1.
I've renamed the variables to make their meaning a little more clear:
$MatchList = [regex]::Matches($fileContents, $pattern)
foreach($Match in $MatchList){
for($i = 0; $i -lt $Match.Groups.Count; $i++){
"Group $i is: $($Match.Groups[$i].Value)"
}
}
If you want to collect all the captured url's, just do:
$urls = foreach($Match in $MatchList){
$Match.Groups[$i].Value
}
If you only need the first match you don't need to invoke [regex]::Matches() manually though - PowerShell will automatically inject the string value of any captured groups into the automatic $Matches variable when you use the -match operator, so if you do:
if($fileContents -match $pattern){
"Group 1 is $($Matches[1])"
}
# or
if($fileContents -match $pattern){
$url = $Matches[1]
}
... you'll get the expected result:
Group 1 is http://example.com/Test.aspx?u=b2
Use Select-String with the parameter -AllMatches to get all matches from your input string. Your regular expression should look like this: (?<=a href=")[^"]*. That will match any character that is not a double quote after the string a href=" (with that last string not being included in the match). Now you just need to expand the value of the matches and you're done.
$re = '(?<=a href=")[^"]*'
$fileContents |
Select-String -Pattern $re -AllMatches |
Select-Object -Expand Matches |
Select-Object -Expand Value

Regex replace using a substring of the regex result value

I've been reading a ton of material and thought I had found my solution but no luck. I need to find apostrophes contained in a name and then replace them with a double. I am loading a file to an array and then looping through that, looking for the apostrophes. The catch is that each row can have several apostrophes so that's why it's not a simple find and replace.
Here is a sample of the file:
create(xxxxxxx)using(xxxxxxx)name('O'Doe, John')
replace(xxxxxxx)instdata('ab 1234 ')
create(xxxxxxx)using(xxxxxxx)name('Doe, O'Jane')
replace(xxxxxxx)instdata('ab 5678 ')
There are other lines inbetween but they don't contain apostrophes.
Here is what I have so far:
$Pattern = "[A-Z]'[A-Z]"
$user = gc C:\Temp\mfnewuser.ins
for ($i = 0; $i -lt $user.count; $i++) {
if ($user[$i] -match $Pattern) {
$user[$i] = [regex]::replace($strText, $Pattern.substring(2,1), "''")
$user | out-file C:\Temp\mfnewuser.ins
}
}
I'm looking for a capital letter, followed by an apostrophe, followed by another capital. Because of the other commas, I can't just do a global replace. I know my pattern matching is working but I can't seem to manipulate it with the substring. The substring looks at $Pattern as a string instead of the result of a regex. If I can save the regex result to a variable, that would be great. I think then the replace would be easy.
Tried this as well but no luck either:
$Pattern = "[A-Z]'[A-Z]"
$NewPattern = "[A-Z]''[A-Z]"
$f = Get-Content C:\Temp\mfnewuser.ins
$f = $f -replace $Pattern, $NewPattern
$f | out-file C:\Temp\mfnewuser.ins
I may be approaching this all wrong and there is an easier way but I haven't seen anything yet.
EDIT:
Based on Bill_Stewarts example below, I've got this to work on the First Name but not yet the Last Name:
$Pattern = "[A-Z]'[A-Z]"
$user = gc C:\Temp\mfnewuser.ins
for ($i = 0; $i -lt $user.count; $i++) {
if ($user[$i] -match $Pattern) {
$user[$i] = $user[$i] -replace "(.*[A-Z])'([A-Z]+.*)", "`$1''`$2"
$user | out-file C:\Temp\mfnewuser.ins
}
}
Perhaps something like this?
get-content "test.txt" | foreach-object {
$_ -replace "([A-Z])'([A-Z])", "`$1''`$2"
}
Regular expressions can be grouped using ( ) and the -replace operator supports substring replacement ($1 and $2).
Replace your line, with the following.
$user[$i] = $user[$i] -replace "([A-Z])'([A-Z])", "`$1`''`$2"
Or try one of the following. This should suffice.
get-content "mfnewuser.ins" | foreach-object {
$_ -replace "([A-Z])'([A-Z])", "`$1`''`$2"
} | set-content "mfnewuser.ins"
...
get-content "mfnewuser.ins" | foreach-object {
$_ -replace "([a-zA-Z', ]+)'([a-zA-Z', ]+)", "`$1`''`$2"
} | set-content "mfnewuser.ins"