Understanding bind - c++

I have a bit of trouble understanding a std::bind call.
In the following example:
#include <functional>
#include <iostream>
#include <memory>
class Notifier
{
public:
Notifier(std::function<void(Notifier&)> on_notify)
:on_notify_(on_notify)
{ }
void notify()
{
if (on_notify_)
on_notify_(*this);
}
std::function<void(Notifier&)> on_notify_;
};
struct Manager
{
Manager()
{
n_ = std::make_unique<Notifier>(std::bind(&Manager::trigger, this));
}
void trigger()
{
std::cout << "notified" << std::endl;
}
std::unique_ptr<Notifier> n_;
};
int main()
{
Manager s;
s.n_->notify();
}
I don't understand how on_notify_(*this); calls back the functor with a Notifier& parameter, but the functor created by bind doesn't specify it.
The calls result correctly to the void notify() method, but I don't understand what exactly will be the functor created by bind to result in this.
If I were to write a lambda instead, I would need to specify the parameter, otherwise it would compile.
What kind of operation does bind here behind my back? :-)

std::bind basically ignores the invalid given argument according to this.
If some of the arguments that are supplied in the call to g() are not matched by any placeholders stored in g, the unused arguments are evaluated and discarded.
It might surprise you that when even more absurd arguments are provided, the binded functor can still successfully reach Manager::trigger() as follows:
#include <functional>
#include <iostream>
#include <memory>
// Some classes that have nothing to do with on_notify_
class AAA {};
class BBB {};
class Notifier
{
public:
Notifier(std::function<void(AAA&, BBB&)> on_notify)
:on_notify_(on_notify)
{ }
void notify()
{
if (on_notify_)
{
// Arguments not matching.
AAA a{};
BBB b{};
// Invoke with them.
on_notify_(a, b);
}
}
std::function<void(AAA&, BBB&)> on_notify_;
};
struct Manager
{
Manager()
{
n_ = std::make_unique<Notifier>(std::bind(&Manager::trigger, this));
}
void trigger()
{
std::cout << "it's also notified!" << std::endl;
}
std::unique_ptr<Notifier> n_;
};
int main()
{
Manager s;
s.n_->notify();
}
Live demo is here.

Related

Does std::future support polymorphism?

Does std::future in c++ support polymorphism?
So, if to store child_class in future<parent_class>, can I after get it after by dynamic_cast<child_class>?
Providing you use a reference or a pointer (probably obvious since it'll fail to compile otherwise)... Yes.
#include <iostream>
#include <future>
using namespace std;
struct Parent {
virtual void a() { cout << "I am parent"; }
};
struct Child : Parent {
virtual void a() { cout << "I am child"; }
};
Child g_c; //just some global for the purposes of the example
int main() {
std::future<Parent&> p = async(launch::async, []() -> Parent& { return g_c; });
auto c = dynamic_cast<Child&>(p.get());
c.a();
return 0;
}
code result here: http://ideone.com/4Qmjvc

Call member function when class type is not known

I want to have a class that can have a callback set to a pointer to member function. This means I need to store the address of the function, and the address of the object instance. The function should have the proper prototype and return value to what the callback expects.
I've played around with std::mem_fn and boost::bind (with the Boost Signals2 library), but it seems like I have to know the type of the class containing the callback function to store this information.
It seems like there should be a way to store a couple void* that would point to any object/function, but this obviously smells funny, loses type safety, etc.
Given a class SomeClass with a method some_method, I want to be able to do something like this:
SomeClass obj;
some_other_class.set_callback(&SomeClass::some_method, &obj);
Here is how I was able to accomplish this using Boost. Note that this uses Boost signals, and seems like overkill for a simple callback. Also, there is the issue of signals using "combiners" to determine the return value of the callback, since there are potentially multiple slots connected to a single signal. I only need support for a single callback. Also note that this is a complete compilable program:
#define _SCL_SECURE_NO_WARNINGS
#include <iostream>
#include <boost/bind.hpp>
#include <boost/signals2.hpp>
#include <string>
using namespace std;
struct MessageSource
{
boost::signals2::signal<void(const string &)> send_message;
typedef boost::signals2::signal<void(const string &)>::slot_type slot_type;
template<typename A, typename B>
boost::signals2::connection connect(A a, B b)
{
return send_message.connect(boost::bind(a, b, _1));
}
void send_msg(const string& msg)
{
send_message(msg);
}
};
struct Printer
{
void print(const string& msg) { std::cout << msg << std::endl; };
};
int main()
{
{
Printer p;
MessageSource s;
s.connect(&Printer::print, &p);
s.send_msg("test");
}
system("pause");
return 0;
}
I think the magic here is the fact that boost::bind() is able to handle a variety of types for its first argument. I just don't get how it can hold onto it in a private field of some sort without knowing the type...
Is this a case where a functor is really the right solution? It seems like member functions are so much more convenient to use...
Based on the comment by cdhowie above, I was able to come up with the following solution using std::function and std::bind:
#include <iostream>
#include <string>
#include <functional>
using namespace std;
struct MessageSource
{
function<void(const string& msg)> _callback;
template<typename A, typename B>
void connect(A func_ptr, B obj_ptr)
{
_callback = bind(func_ptr, obj_ptr, placeholders::_1);
}
void send_msg(const string& msg)
{
if (_callback)
_callback(msg);
}
void disconnect()
{
_callback = nullptr;
}
};
struct Printer
{
void print(const string& msg) { std::cout << msg << std::endl; };
};
int main()
{
{
Printer p;
MessageSource s;
s.connect(&Printer::print, &p);
s.send_msg("test");
s.disconnect();
s.send_msg("test again");
}
system("pause");
return 0;
}

wrapping std::packaged_task inside a custom class

I'm trying to wrap std::packaged_task inside another class in order to be used together with a task scheduler.
At the moment I got it all working except std::future support. To get std::future support I figured out I need to use std::packaged_task for the get_future() function that it provides.
I've been trying whole day all sorts of ways to get this to work, but I seem to be unable to properly declare and initialise the packaged_task using the return value from a std::bind. I have tried to decipher the implementations of all the related libstdc++ functions such as std::async, std::future, std::thread etc but with no luck.
The following code is the implementation of both the not working version and the working one. To get it to work uncomment the two /* --- WORKS*/ and comment the other related line.
#include <vector>
#include <deque>
#include <memory>
#include <thread>
#include <mutex>
#include <condition_variable>
#include <future>
#include <iostream>
#include <chrono>
#include <functional>
#include <windows.h>
class task
{
private:
struct task_implementation_base
{
virtual void execute() = 0;
};
template <class callable>
struct task_implementation : public task_implementation_base
{
task_implementation(callable&& f) : /*m_task(std::forward<callable>(f)) WORKS*/m_task(f) { }
void execute() { m_task(); }
//callable m_task; // WORKS
std::packaged_task<typename result_of<callable>::type> m_task;
};
template <class callable>
std::shared_ptr<task_implementation<callable>> make_routine(callable&& f)
{
return std::make_shared<task_implementation<callable>>(std::forward<callable>(f));
}
public:
template <class callable, class... arguments>
task(callable&& f, arguments&&... args) : m_function(make_routine(std::bind(std::forward<callable>(f), std::forward<arguments>(args)...))) {}
void operator()() { run(); }
void run() { m_function->execute(); }
private:
std::shared_ptr<task_implementation_base> m_function;
};
int testint(int i)
{
std::cout << "test6" << " :: ran from thread " << std::this_thread::get_id() << "\n";
fflush(stdout);
return i+100;
}
void test(const char* text)
{
std::cout << text << " :: ran from thread " << std::this_thread::get_id() << "\n";
fflush(stdout);
}
class testclass
{
public:
void print1() { test("test3"); }
void print2() { test("test4"); }
void print3(const char* text) { test(text); }
};
int main()
{
testclass testclass1;
testclass* testclass2 = new testclass;
task test1(test, "test1");
task test2([]() { test("test2"); });
task test3(&testclass::print1, &testclass1);
task test4(&testclass::print2, &*testclass2);
task test5(&testclass::print3, &*testclass2, "test5");
task test6(&testint, 1);
test1();
test2();
test3();
test4();
test5();
test6();
Sleep(2000);
return 0;
}
I'm thinking the problem is typename result_of<callable>::type. I'm guessing it doesn't properly evaluates to the return type of the callable function.
I'm using c++ (Built by MinGW-builds project) 4.8.0 20121225 (experimental) on a Windows 8 64bit. I'm suspecting the errors are irrelevant since I guess I'm just simply trying to get this work the wrong way but here is a pastebin for the errors anyway: errors
std::packaged_task not only takes the result type of the invoked function as a template argument but also the types of the arguments you are passing to the to be invoked function.
You can define them as follows:
// somewhere
int foo(bool, int);
// somewhere else
std::packaged_task<int(bool, int)> p(foo);
To fix your code you need to add two empty parenthesis pairs. What I explained above also applies to std::result_of.
std::packaged_task<typename std::result_of<callable()>::type()> m_task;
It is only response to main topic question. "How to implement"
Example short implementation:
template <typename Signature> /// <---- 1
class Task;
template <typename Res, typename... ArgTypes>
class Task<Res(ArgTypes...)> /// <---- 2
{
public:
template <typename Function>
explicit Task(Function&& callback)
: _task{std::forward<Function>(callback)}
{ }
void execute(ArgTypes... args) noexcept(false)
{
//...
_task(std::forward<ArgTypes>(args)...);
}
private:
std::packaged_task<Res(ArgTypes...)> _task;
};
Not sure why step 1 & 2 are required but I did the same as in lib implementation. Maybe someone could extend this response.

Function calls with class members?

Before I present the code which is found at the bottom of this post I would like to talk about the issue and the fix's that I do not desire. Okay basically I've created a GUI from scratch sort of and one requirement I wanted for this was allow components to have their own click executions so if i click a button or tab etc.. It would call Component->Execute(); Well normally you would do something like a switch statement of ids and if that components ID equaled n number then it would perform this action. Well that seemed kinda dumb to me and I thought there has to be a better way. I eventually tried to incorporate a feature in JAVA where you would do like Component.AddActionListener(new ActionListener( public void execute(ActionEvent ae) { })); or something like that and I thought that this feature has to be possible in C++. I eventually came across storing void functions into a variable in which could be executed at any time and modified at any time. However I hadn't noticed an issue and that was this only worked with static functions. So below you'll see my problem. I've patched the problem by using a pointer to SomeClass however this would mean having an individual function call for every class type is there no way to store a function callback to a non-static class member without doing the below strategy? and instead doing a strategy like the commented out code?
//Main.cpp
#include <iostream> //system requires this.
#include "SomeClass.h"
void DoSomething1(void)
{
std::cout << "We Called Static DoSomething1\n";
}
void DoSomething2(void)
{
std::cout << "We Called Static DoSomething2\n";
}
int main()
{
void (*function_call2)(SomeClass*);
void (*function_call)() = DoSomething1; //This works No Problems!
function_call(); //Will Call the DoSomething1(void);
function_call = DoSomething2; //This works No Problems!
function_call(); //Will Call the DoSomething2(void);
SomeClass *some = new SomeClass(); //Create a SomeClass pointer;
function_call = SomeClass::DoSomething3; //Static SomeClass::DoSomething3();
function_call(); //Will Call the SomeClass::DoSomething3(void);
//function_call = some->DoSomething4; //Non-Static SomeClass::DoSomething4 gives an error.
//function_call(); //Not used because of error above.
function_call2 = SomeClass::DoSomething5; //Store the SomeClass::DoSomething(SomeClass* some);
function_call2(some); //Call out SomeClass::DoSomething5 which calls on SomeClass::DoSomething4's non static member.
system("pause");
return 0;
}
//SomeClass.hpp
#pragma once
#include <iostream>
class SomeClass
{
public:
SomeClass();
~SomeClass();
public:
static void DoSomething3(void);
void DoSomething4(void);
static void DoSomething5(SomeClass* some);
};
//SomeClass.cpp
#include "SomeClass.h"
SomeClass::SomeClass(void)
{
}
SomeClass::~SomeClass(void)
{
}
void SomeClass::DoSomething3(void)
{
std::cout << "We Called Static DoSomething3\n";
}
void SomeClass::DoSomething4(void)
{
std::cout << "We Called Non-Static DoSomething4\n";
}
void SomeClass::DoSomething5(SomeClass *some)
{
some->DoSomething4();
}
Secondary Fix for what I'll do not an exact answer I wanted but it meets my needs for now along with allowing additional features which would have become overly complicate had this not existed.
//Component.hpp
#pragma once
#include <iostream>
#include <windows.h>
#include <d3dx9.h>
#include <d3d9.h>
#include "Constants.hpp"
#include "ScreenState.hpp"
#include "ComponentType.hpp"
using namespace std;
class Component
{
static void EMPTY(void) { }
static void EMPTY(int i) { }
public:
Component(void)
{
callback = EMPTY;
callback2 = EMPTY;
callback_id = -1;
}
Component* SetFunction(void (*callback)())
{
this->callback = callback;
return this;
}
Component* SetFunction(void (*callback2)(int), int id)
{
this->callback_id = id;
this->callback2 = callback2;
return this;
}
void execute(void)
{
callback();
callback2(callback_id);
}
}
The syntax for pointers-to-member-functions is as follows:
struct Foo
{
void bar(int, int);
void zip(int, int);
};
Foo x;
void (Foo::*p)(int, int) = &Foo::bar; // pointer
(x.*p)(1, 2); // invocation
p = &Foo::zip;
(x.*p)(3, 4); // invocation
Mind the additional parentheses in the function invocation, which is needed to get the correct operator precedence. The member-dereference operator is .* (and there's also ->* from an instance pointer).

Noob boost::bind member function callback question

#include <boost/bind.hpp>
#include <iostream>
using namespace std;
using boost::bind;
class A {
public:
void print(string &s) {
cout << s.c_str() << endl;
}
};
typedef void (*callback)();
class B {
public:
void set_callback(callback cb) {
m_cb = cb;
}
void do_callback() {
m_cb();
}
private:
callback m_cb;
};
void main() {
A a;
B b;
string s("message");
b.set_callback(bind(A::print, &a, s));
b.do_callback();
}
So what I'm trying to do is to have the print method of A stream "message" to cout when b's callback is activated. I'm getting an unexpected number of arguments error from msvc10. I'm sure this is super noob basic and I'm sorry in advance.
replace typedef void (*callback)(); with typedef boost::function<void()> callback;
A bound function doesn't produce an ordinary function, so you cannot just store it in a regular function pointer. However, boost::function is able to handle anything as long as it is callable with the correct signature, so that's what you want. It will work with a function pointer, or a functor created with bind.
After a few corrections to your code, I came up with this:
#include <boost/bind.hpp>
#include <boost/function.hpp>
#include <iostream>
// i prefer explicit namespaces, but that's a matter of preference
class A {
public:
// prefer const refs to regular refs unless you need to modify the argument!
void print(const std::string &s) {
// no need for .c_str() here, cout knows how to output a std::string just fine :-)
std::cout << s << std::endl;
}
};
// holds any arity 0 callable "thing" which returns void
typedef boost::function<void()> callback;
class B {
public:
void set_callback(callback cb) {
m_cb = cb;
}
void do_callback() {
m_cb();
}
private:
callback m_cb;
};
void regular_function() {
std::cout << "regular!" << std::endl;
}
// the return type for main is int, never anything else
// however, in c++, you may omit the "return 0;" from main (and only main)
// which will have the same effect as if you had a "return 0;" as the last line
// of main
int main() {
A a;
B b;
std::string s("message");
// you forget the "&" here before A::print!
b.set_callback(boost::bind(&A::print, &a, s));
b.do_callback();
// this will work for regular function pointers too, yay!
b.set_callback(regular_function);
b.do_callback();
}