Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 6 years ago.
Improve this question
I am looking to extract all the entries from the following string:
[
"GUID_ID_ONE",
"2016-07-11T18:35:29Z",
"email#address.com",
"HASH_STRING",
"GUID_KEY_TWO",
"GUID_KEY_THREE"
]
I would like a RegEx to extract all the strings, quotes omitted. I have used
"(.*?)"
but this would appear to only find the first string.
Depending on the language you're using, the implementation can be different but you need to use the global modifier(g) to get all the matching strings, like this :
/"(.*?)"/g
Check here
Related
Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 2 years ago.
Improve this question
I have string that could come in several forms
“PSM000216556880035450088|TRF”
“VNM000216556880035450088|TRF FROM MACK”
“NXG000216556880035450088”
“Transfer from josh SL000216556880035450088 to jack”
“X00000216556880035450088 0098123 TRANSFER 789121”
I need a Regex pattern that could get the string that starts with PSM, VNM, NXG, SL00 or X00.
i.e. in 1, I need “PSM000216556880035450088”. This string is the reference and it is what I need. It can be found in any position in a sentence and sometimes the reference might not be separated from the other words by a space. Sometimes a special character can be used as a separator. i…e. in 2 “VNM000216556880035450088|TRF FROM MACK”.
I will be using the Regex in my VB.NET code.
What about this with multiline flag?
((?:PSM|VNM|NXG|(SL|X)00)\d+)
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 5 years ago.
Improve this question
Ok so I have a string encryption thing that goesXorStr( "" ).
How can I put this on all strings without doing them one by one?
You can use the fact, that "Find and Replace" functionality also provides support for regular expressions. Thus, you may easily find all strings, capture them and wrap with XorStr().
In "Find" field, ((\".+?\")|('.+?')) will match all strings with double or single quotes. If you want only the double-quoted, reduce this to (\".+?\").
In "Replace with" field, use: XorStr($1).
Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 8 years ago.
Improve this question
I'm looking for the regular expression to find failures in a log file.
The format is "Failures: " following the number of error, a digit not zero
Thanks!
You can use this:
"Failures:\s+[1-9]\d*"
this would be what you are looking for:
Failures:\s*[1-9]\d*
btw, you may want to know that in character class, the not notation is ^, not !.
E.g. [^a-zA-Z] means not letters.
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 8 years ago.
Improve this question
In Perl, I would like to determine if a given string is valid, the rule is to check if values exist between commas.
e.g. abc,abc is a valid case, but abc, or abc,,abc are not.
m/^\s*,|,\s*,|,\s*$/
matches all invalid combinations, assuming whitespace does not count as "values".
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 9 years ago.
Improve this question
preg_match('.*<a\b(?=\s)(?=(?:[^>=]|='[^']*'|="[^"]*"|=[^'"][^\s>]*)*?\shref=['"]([^"]*)['"]?)(?:[^>=]|='[^']*'|="[^"]*"|=[^'"\s]*)*"\s?\/?>/m',$data,result);
how can i work with
php regex
find anchor link here.
This giving syntax error. how can we fix that.
you can see here working status.
http://www.rubular.com/r/G5F6AD5UyL
You need to escape the quotes in your regex - in Ruby that's not necessary because regexes are first-class objects with their own literal syntax, but not in PHP. Also, you need to add delimiters:
preg_match('~.*<a\b(?=\s)(?=(?:[^>=]|=\'[^\']*\'|="[^"]*"|=[^\'"][^\s>]*)*?\shref=[\'"]([^"]*)[\'"]?)(?:[^>=]|=\'[^\']*\'|="[^"]*"|=[^\'"\s]*)*"\s?/?>~m',$data,result);