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I am making a shopping list program. For this program, I need to be able to type in a user input that accepts both number (1564, 121,1, etc) and word (hello, goodbye, etc) combinations. The program reads numbers just fine, but it cannot process words. Thank you in advance. The part of the code I am stuck with is below:
int code, option, count = 0;
double quantity, price, cost;
string description;
cin >> code;
while ((code != 123456789) && (count < 2))
{
cout << "Incorrect code, try again \n";
cin >> code;
count++;
if (count == 2)
{
cout << "max # of tries reached. Goodbye. \n";
system("pause");
}
}
Your code variable is now an int. If you wanted that to be a string, declare it so: std::string code;. Note that you might need to #include <string> in the very beginning. Also, if you want to compare it with numbers, either you call something like atoi() (string has .cstr()), or better yet, you might just compare it with "123456789". HTH.
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I'm sick and tired of solving why my ch[0] is of value "Thomas EdisonÇ#", when it should be "Thomas Edison"
int main(){
using namespace std;
ifstream in("U2.txt");
int n;
in>>n; //n=rows, so in every line there will be "name surname", time, money
char ch[n][21]; //I'm trying to get Name+Surname which must be 20 char long
in.read(ch[0], 20);
cout << ch[0]; //but getting Thomas EdisonÇ#
return 0;}
It works on one dimentional ch[21], but there's gonna be lots of values so I want to use ch[n][21]
Any other out of my box solution is welcome, I'm tired
You are forgetting that C strings need to be nul terminated
in.read(ch[0], 20);
ch[0][20] = '\0'; // add the nul terminator
cout << ch[0]; // now correct output
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Hellow guys i want to add nine integers to array at once time without pressing enter key in run time. please guys tell me how to add nine integers to array simultaneously in C++.
Thanks!
If you want to process each integer value right after its input in console is complete (e.g. in that a blank indicates that the next integer value shall begin), you are in a bad position.
The reason is that terminal input (beyond of what your C++ program can influence) often is buffered, and even cin might not receive any character until Enter or EOF is pressed in the terminal.
There may exist workarounds like conio.h or ncurses, but the are not standard and probably not worth the effort in your situation unless you really need to implement integer scanning for a production environment tightly connected to console input.
Try it out and compare input taken directly from console to input from a stream that is already "filled" with enough input:
int main() {
stringstream ss("12 34 56 78 90 10 11 12 13");
//istream &in = ss; // would output each integer immediately.
istream &in = cin; // will probably wait for enter before processing begins.
int value = 0;
for (int i=0; i<9; i++) {
if (! (in >> value))
break;
cout << value << "; ";
}
}
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I receive text with special characters (such as á) so I have to manually search and replace each one with code (in this case "á")
I would like to have code to search and replace such instances automatically after user input. Since I'm a noob, I'll show you the code I have so far - however meager it may be.
// Text fixer
#include <iostream>
#include <fstream>
#include <string>
int main(){
string input;
cout << "Input text";
cin >> input;
// this is where I'm at a loss. How should I manipulate the variable?
cout << input;
return 0;
}
Thank you!
An easy method is to use an array of substitution strings:
std::string replacement_text[???];
The idea is that you use the incoming character as the index into the array and extract the replacement text.
For example:
replacement_text[' '] = " ";
// ...
std::string new_string = replacement_text[input_character];
Another method is to use switch and case to convert the character.
Alternative techniques are a lookup table and std::map.
The lookup table could be an array of mapping structures:
struct Entry
{
char key;
std::string replacement_text;
}
Search the table using the key field to match the incoming character. Use the replacement_text to get the replacement text.
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Hi I am a beginner to the c++ language and I would like to know if there is any way of writing a program with unlimited inputs. For example: I want to write a calculator program just to add numbers. That's easy enough but is there a way so that the user can add as many numbers as he wants without being asked how many numbers he wants. Such that if he wants to add three numbers he can just type "1+1+1" or if he wants to add four numbers he adds "+1" to the end of the previous line.Like this the user is not stuck to a fixed number of inputs or so he doesn't need to be asked how many inputs he wants. What functions in c++ do I need to know in order to do this
You can use a while loop to read from standard input. (std::cin) Some basic code to read from a while loop, and add the input to a sum is as follows:
#include <iostream>
#include <string>
#include <cstdlib>
int main(){
std::string line = "";
double sum = 0.0;
while(line != "end"){
std::cout<<"The current sum is: "<<sum<<std::endl;
std::cout<<"Enter the number you would like to add or \"end\" to exit: ";
std::cin>>line;
sum += atof(line.c_str());
}
std::cout<<"The final sum is: "<<sum<<std::endl;
}
This will read numbers until it receives the input "end".
For parsing and evaluating expressions that include infix operators, few things are simpler than the Shunting Yard Algorithm.
Implementing this in C++ is scarcely different than any other language with a container library (or built-in support) that provides stacks and queues. Here, you'll want to use std::stack and std::queue. The input to your program could be a single line (containing an expression typed by the user) read from std::cin (standard input, or the console) into an std::string.
This will not only permit expressions of any reasonable length, but also correctly handle arbitrary nesting of parenthesized sub-expressions, evaluation of special functions, and custom operators.
Yes. It is possible. You can use vector of ints. Get user's input and calculate sum of elements from vector. Put this in loop and that is what you wanted.
try this:
#include <iostream>
int main (int argc, char *argv[])
{
for (int i = 0; i < argc; i++)
std::cout << "argument " << i << " is " << argv[i] << std::endl;
return 0;
}
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We have tried to search this problem but we haven't found any answers. If The user inputs a string variable when the system requires a integer how do you evade the problem with out using a while loop?
{
int grade_var=0,grade_1=0,sum=0;
cout<<"Enter the number of grades you have:\t";
cin>>grade_var;
for(int i=1;i<=grade_var;i++)
I don't wish to do a while loop for my program has a lot of integer insertions and want to know an easier way to correct rather than while loops?
While loops are generally the way to go.
However, to keep the code clean, you may want to consider putting said while loop into a helper function, so you can just call PollForIntegerInput(string prompt) from anywhere in your code, and then handle that input in one place. There is almost never a reason you should be duplicating an input loop like that.
As for a truly nonlooping answer, I have none.
Calling operator>> on a stream returns the stream itself, which can be converted to bool to check if the stream is in a good state. If a bad extraction happens, the stream is not in a good state. So you can do something like this:
if (cin >> grade_var)
This will check that it was successful. You can just negate the condition to find it if it wasn't successful. How you handle this condition is up to. Maybe you'll return early on failure. If you want to reprompt the user for correct input, however, you'll need a loop.
It's not too clear what your problem is, but...
It's almost always poor design to input the number of data
points which will follow. If you expect a series of int, for
example:
std::vector<int> grades;
int grade;
while ( std::cin >> grade ) {
grades.push_back( grade );
}
It doesn't get much simpler.
If you do want to insist on an exact number of input, outputting
an error when the user inputs something incorrect, the usual
pattern would be:
std::vector<int> grades;
while ( grades.size() != targetNumber ) {
int grade;
while ( !(std::cin >> grade) ) {
std::cout << "Integer wanted" << std::endl;
std::cin.clear();
std::cin.ignore( INT_MAX, '\n' );
}
grades.push_back( grade );
}
Still no for. (In fact, for loops with input are very, very
rare.)