mod_wsgi cannot be loaded as Python module - django

Question

I'm trying to access a Django application using apache and I'm getting Internal Server Error. I've opened the logs to see what is going on and I found this:
[Thu Jun 23 03:10:03 2016] [notice] suEXEC mechanism enabled (wrapper: /usr/sbin/suexec)
[Thu Jun 23 03:10:03 2016] [notice] Digest: generating secret for digest authentication ...
[Thu Jun 23 03:10:03 2016] [notice] Digest: done
[Thu Jun 23 03:10:03 2016] [notice] Apache/2.2.15 (Unix) DAV/2 mod_wsgi/3.2 Python/2.6.6 configured -- resuming normal operations
[Thu Jun 23 03:10:10 2016] [error] [client 197.41.248.175] mod_wsgi (pid=5612): Target WSGI script '/home/TaskManagement/teamwork/wsgi.py' cannot be loaded as Python module.
[Thu Jun 23 03:10:10 2016] [error] [client 197.41.248.175] mod_wsgi (pid=5612): Exception occurred processing WSGI script '/home/TaskManagement/teamwork/wsgi.py'.
[Thu Jun 23 03:10:10 2016] [error] [client 197.41.248.175] Traceback (most recent call last):
[Thu Jun 23 03:10:10 2016] [error] [client 197.41.248.175] File "/home/TaskManagement/teamwork/wsgi.py", line 15, in <module>
[Thu Jun 23 03:10:10 2016] [error] [client 197.41.248.175] from django.core.wsgi import get_wsgi_application
[Thu Jun 23 03:10:10 2016] [error] [client 197.41.248.175] File "/home/py3venv/lib/python3.4/site-packages/django/__init__.py", line 1, in <module>
[Thu Jun 23 03:10:10 2016] [error] [client 197.41.248.175] from django.utils.version import get_version
[Thu Jun 23 03:10:10 2016] [error] [client 197.41.248.175] File "/home/py3venv/lib/python3.4/site-packages/django/utils/version.py", line 7, in <module>
[Thu Jun 23 03:10:10 2016] [error] [client 197.41.248.175] from django.utils.lru_cache import lru_cache
[Thu Jun 23 03:10:10 2016] [error] [client 197.41.248.175] File "/home/py3venv/lib/python3.4/site-packages/django/utils/lru_cache.py", line 28
[Thu Jun 23 03:10:10 2016] [error] [client 197.41.248.175] fasttypes = {int, str, frozenset, type(None)},
[Thu Jun 23 03:10:10 2016] [error] [client 197.41.248.175] ^
[Thu Jun 23 03:10:10 2016] [error] [client 197.41.248.175] SyntaxError: invalid syntax
I'm using python 3.4, Django 1.9, apache 2.2.
and here is my apache configuration:
WSGISocketPrefix /var/run/wsgi
WSGIScriptAlias / /home/TaskManagement/teamwork/wsgi.py process-group=hrm.jodod.info
WSGIDaemonProcess hrm.jodod.info python-path=/home/TaskManagement:/home/py3venv/lib/python3.4/site-packages
WSGIProcessGroup hrm.jodod.info
Alias /robots.txt /home/TaskManagement/robots.txt
Alias /favicon.ico /home/TaskManagement/favicon.ico
Alias /static/ /home/TaskManagement/static/
<Directory /path/to/mysite.com/static>
Order deny,allow
Allow from all
</Directory>
<Directory /home/TaskManagement/teamwork>
<Files wsgi.py>
Order deny,allow
Allow from all
</Files>
and here is my wsgi.py file:
import os
import sys
sys.path.append('/home/TaskManagement')
sys.path.append('/home/TaskManagement/teamwork')
from django.core.wsgi import get_wsgi_application
os.environ["DJANGO_SETTINGS_MODULE"] = "{{ project_name }}.settings"
application = get_wsgi_application()
Can anybody figure out what am I doing wrong?

Answer 1

Python/2.6.6 configured -- resuming normal operations
Looks like your mod_wsgi is compiled against Python 2.6.6 and you're trying to run Python3 code with it. The Set syntax you are seeing in the error appeared in Py3. Recompile mod_wsgi and try again.

Answer 2

Your wsgi.py line 9 has to be
os.environ["DJANGO_SETTINGS_MODULE"] = "teamwork.settings"
if the directory it's stored is called teamwork (your project's name)
also in your manage.py it has to be "teamwork.settings"