Title based Slug for URLs in django without app label - regex

Question

I got products app with ListView and DetailView. I need to implement slug with title of products on detail page with no app label in url. Such as in detail page it should say 'mysite.com/complete-product-title' instead of 'mysite.com/products/complete-product-title'. This detail page can help me to great deal for SEO.
Following is the code:
models.py:
class Product(models.Model):
title = models.CharField(max_length=500)
description = models.TextField(blank=True, null=True)
price = models.DecimalField(max_digits=20, decimal_places=2)
sku = models.CharField(null=True, max_length=100)
url = models.URLField(blank=True)
slug = models.SlugField(default='')
categories = models.ManyToManyField('Category', blank=True)
default = models.ForeignKey('Category', related_name='default_category', null=True, blank=True)
def __unicode__(self):
return self.title
def save(self, *args, **kwargs):
self.slug = slugify(self.title)
super().save(*args, **kwargs)
def get_absolute_url(self):
kwargs={"slug": self.slug}
return reverse('product_detail', kwargs=kwargs)
Views.py:
class ProductListView(ListView):
model = Product
paginate_by = 20
def get_context_data(self, *args, **kwargs):
context = super(ProductListView, self).get_context_data(*args, **kwargs)
return context
def get_queryset(self, *args, **kwargs):
query = super(ProductListView, self).get_queryset(*args, **kwargs)
return query
class ProductDetailView(DetailView):
model = Product
slug_field = 'slug'
Project urls.py:
url(r'^products/', include('products.urls')),
App urls.py:
url(r'^(?P<slug>[\w-]+)/$', ProductDetailView.as_view(), name='product_detail'),
I have implemented elasticsearch with haystack and for it I have to add haystack urls in project root urls.py like url(r'^$', include('haystack.urls'), name='search'),
My complete models.py for products app are
class Product(models.Model):
title = models.CharField(max_length=500)
description = models.TextField(blank=True, null=True)
price = models.DecimalField(max_digits=20, decimal_places=2)
sku = models.CharField(null=True, max_length=100)
url = models.URLField(blank=True)
slug = models.SlugField(unique=False)
categories = models.ManyToManyField('Category', blank=True)
default = models.ForeignKey('Category', related_name='default_category', null=True, blank=True)
def __unicode__(self):
return self.title
def get_absolute_url(self):
return reverse('product_detail', kwargs={"slug":self.slug})
def get_image_url(self):
img = self.productimage_set.first()
if img:
return img.image.url
return img
class Category(models.Model):
title = models.CharField(max_length=120, unique=True)
#slug = models.SlugField(unique=True)
description = models.TextField(null=True, blank=True)
timestamp = models.DateTimeField(auto_now=False, auto_now_add=True)
def __unicode__(self):
return self.title
def image_upload_to(instance, filename):
title = instance.product.title
slug = slugify(title)
basename, file_extension = filename.split('.')
new_filename = '%s-%s.%s'%(basename, instance.id, file_extension)
return 'products/%s/%s' %(slug, new_filename)
class ProductImage(models.Model):
product = models.ForeignKey(Product)
image = models.ImageField(upload_to=image_upload_to)
def __unicode__(self):
return self.product.title
When I try to add slug=models.SlugField(unique=True) I get error message like column slug is not unique.
Now I can't remove products/ from url(r'^products/', include('products.urls')), because then it will make haystack urls and product app urls both default. Ultimate goal here is to just implement haystack urls as default but not showing 'mysite.com/products/product-title-as-slug' instead 'mysite.com/product-title-as-slug'.
Please assist how can I achieve this goal.

Answer 1

You can do this immediately by changing:
url(r'^products/', include('products.urls')),
to
url(r'^', include('products.urls')),
This is all you would need to do if your site is not yet live. Otherwise you should also write in a 301 redirect from your old URLs (mysite.com/products/complete-product-title) to your new ones at the same time.