Given the following list:
colors=['#c85200','#5f9ed1','lightgrey','#ffbc79','#006ba4','dimgray','#ff800e','#a2c8ec'
,'grey','salmon','cyan','silver']
And this list:
Hospital=['a','b','c','d']
After I get the number of colors based on the length of the list - 'Hospital':
num_hosp=len(Hospital)
colrs=colors[:num_hosp]
colrs
['#c85200', '#5f9ed1', 'lightgrey', '#ffbc79']
...and zip the lists together:
hcolrs=zip(Hospitals,colrs)
Next, I'd like to be able to select 1 or more colors from hcolrs if given a list of one or more hospitals from 'Hospitals'.
Like this:
newHosps=['a','c'] #input
newColrs=['#c85200','lightgrey'] #output
Thanks in advance!
Pass the result of zip to the dict constructor to make lookup simple/fast:
# Don't need to slice colors; zip stops when shortest iterable exhausted
hosp_to_color = dict(zip(Hospitals, colors))
then use it:
newHosps = ['a','c']
newColrs = [hosp_to_color[h] for h in newHosps]
Related
Having 2 lists, I want check which values of List1 are in List2. I'm trying as below but I get error
List1 = {3,2,8,7,5}
List2 = {1,3,4,2,6,7,9}
= List.Transform(List1, each Text.Contains(List2, _))
Expression.Error: We cannot convert a value of type List to type Text.
Details:
Value=[List]
Type=[Type]
My expected output would be 3,2,7.
How can I do this?
See List.Intersect Documentation
Intersect = List.Intersect({List1,List2})
#horseyride has probably the best answer but using your original logic, you could also write the intersection like this:
List.Select(List1, each List.Contains(List2, _))
This uses Select instead of Transform since you are trying to select/filter instead of changing the elements and uses the appropriate List type instead of Text for the Contains part.
I'm quite new in python coding and I can´t solve the following problem:
I have a list with trackingpoints for different animals(ID,date,time,lat,lon) given in strings:
aList = [[id,date,time,lat,lon],
[id2,date,time,lat,lon],
[...]]
The txt file is very big and the IDs(a unique animal) is occuring multiple times:
i.e:
aList = [['25','20-05-13','15:16:17','34.89932','24.09421'],
['24','20-05-13','15:16:18','35.89932','23.09421],
['25','20-05-13','15:18:15','34.89932','24.13421'],
[...]]
What I'm trying to do is order the ID's in dictionaries so each unique ID will be the key and all the dates, times, latitudes and longitudes will be the values. Then I would like to write each individual ID to a new txt file so all the values for a specific ID are in one txt file. The output should look like this:
{'25':['20-05-13','15:16:17','34.89932','24.09421'],
['20-05-13','15:18:15','34.89932','24.13421'],
[...],
'24':['20-05-13','15:16:18','35.89932','23.09421'],
[...]
}
I have tried the following (and a lot of other solutions which didn't work):
items = {}
for line in aList:
key,value = lines[0],lines[1:]
items[key] = value
Which results in a key with the last value in the list forthat particular key :
{'25':['20-05-13','15:18:15','34.89932','24.13421'],
'24':['20-05-13','15:16:18','35.89932','23.09421']}
How can I loop through my list and assign the same IDs to the same key and all the corresponding values?
Is there any simple solution to this? Other "easier to implement" solutions are welcome!
I hope it makes sense :)
Try adding all the lists that match to the same ID as list of lists:
aList = [['25','20-05-13','15:16:17','34.89932','24.09421'],
['24','20-05-13','15:16:18','35.89932','23.09421'],
['25','20-05-13','15:18:15','34.89932','24.13421'],
]
items = {}
for line in aList:
key,value = line[0],line[1:]
if key in items:
items[key].append(value)
else:
items[key] = [value]
print items
OUTPUT:
{'24': [['20-05-13', '15:16:18', '35.89932', '23.09421']], '25': [['20-05-13', '15:16:17', '34.89932', '24.09421'], ['20-05-13', '15:18:15', '34.89932', '24.13421']]}
I'm using scrapy to iteratively scrape some data, and the data is being output as two lists through each iteration. I want to combine the two lists into one list at each iteration, so that in the end I will have one big list with many sublists(each sublist being the combination of the two lists created from each iteration)
That may be confusing so I will show my current output and code:
using Scrapy I"m iterating in the following way,
for i in response.css(''tr.insider....."):
i.css(a.tab-link:text).extract() #creating the first list
i.css('td::text').extract() #creating the second list
So the current output is something like this
[A,B,C] #first iteration
[1,2,3]
[D,E,F] #second iteration
[4,5,6]
[G,H,I] #third iteration
[7,8,9]
Desired output is
[[A,B,C,1,2,3], [D,E,F,4,5,6],[G,H,I,7,8,9]]
I tried the following code but I'm getting a list of None.
x =[]
for i in response.css(''tr.insider....."):
x.append(i.css(a.tablink::text).extract().extend(i.css('td::text').extract()))
But the return is just
None
None
None
None
None.....
Thanks!
extend function returns None, so you always append None to x.
For your purpose, I this is what you want:
for i in response.css(''tr.insider....."):
i.css('a.tab-link:text, td::text').extract()
You can simply add two lists together and append them to your results list.
results = []
for i in response.css("tr.insider....."):
first = i.css(a.tab-link:text).extract()
second = i.css('td::text').extract()
# combine both and append to results
results.append(first + second)
print(results)
# e.g.: [[A,B,C,1,2,3], [D,E,F,4,5,6],[G,H,I,7,8,9]]
I have got a list of different names. I have a script that prints out the names from the list.
req=urllib2.Request('http://some.api.com/')
req.add_header('AUTHORIZATION', 'Token token=hash')
response = urllib2.urlopen(req).read()
json_content = json.loads(response)
for name in json_content:
print name['name']
Output:
Thomas001
Thomas002
Alice001
Ben001
Thomas120
I need to find the max number that comes with the name Thomas. Is there a simple way to to apply regexp for all the elements that contain "Thomas" and then apply max(list) to them? The only way that I have came up with is to go through each element in the list, match regexp for Thomas, then strip the letters and put the remaining numbers to a new list, but this seems pretty bulky.
You don't need regular expressions, and you don't need sorting. As you said, max() is fine. To be safe in case the list contains names like "Thomasson123", you can use:
names = ((x['name'][:6], x['name'][6:]) for x in json_content)
max(int(b) for a, b in names if a == 'Thomas' and b.isdigit())
The first assignment creates a generator expression, so there will be only one pass over the sequence to find the maximum.
You don't need to go for regex. Just store the results in a list and then apply sorted function on that.
>>> l = ['Thomas001',
'homas002',
'Alice001',
'Ben001',
'Thomas120']
>>> [i for i in sorted(l) if i.startswith('Thomas')][-1]
'Thomas120'
I am working on a project where i am trying to plot the rainfall pattern of various states of my country. By using this command i fetch the data from my database:
cur.execute('SELECT JAN,FEB,MAR,APR,MAY,JUN,JUL,AUG,SEP,OCT,NOV,DECEMBER FROM Rainfall_In_Cm where STATE_UT = %s && DISTRICT = %s' ,(state , district))
The result comes in the form of a list with 1 element(the 1 row from the query output) :
(Decimal('17.5'), Decimal('9.9'), Decimal('8.9'), Decimal('4.0'), Decimal('9.3'), Decimal('53.8'), Decimal('227.1'), Decimal('280.90'), Decimal('125.4'), Decimal('28.1'), Decimal('5.0'), Decimal('4.7'))
Now i want all the elements to be in form of a list that i can use with matplotlib to plot a graph and I want to remove 'Decimal' string from infront of every value . How can i do it?
Your result is a tuple, not a list, but that is not a problem.
Casting should work for these Decimal objects. You can use a list comprehension:
#Data from your example
foo = (Decimal('17.5'), Decimal('9.9'), Decimal('8.9'), Decimal('4.0'), Decimal('9.3'), Decimal('53.8'), Decimal('227.1'), Decimal('280.90'), Decimal('125.4'), Decimal('28.1'), Decimal('5.0'), Decimal('4.7'))
bar = [float(i) for i in foo]
If you want to have rather integers, use:
bar = [int(i) for i in foo]