Python Threads Run When Created, Not When run() is Called - python-2.7

Question

In my python program (2.7), I attempt to create a thread but it instantly starts when it is created, not when the start() and then the run() attributes are called. Help would be great.
Here is my (server) code:
import sys
import socket
import threading
global connections
connections = []
def srcv(s, conn, data):
while True:
print "Recieving"
#Recieve Strings From Each Connection
for i, n in enumerate(connections):
data.append([connections[1], i.recv(4096)])
#Send String To Each Connection
print "Sending"
for i, n in enumerate(connections):
i.send("{0}: {1}".format(data[n][0], data[n][1]))
def listn(s, conn, data):
s.listen(10)
print "Listening For Connection"
while True:
obj, addr = s.accept()
connections.append([obj, addr])
def start_server():
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
conn = []
data = []
s.bind(("localhost", 12345))
print "Creating Listening Thread"
listen = threading.Thread(target=listn(s,conn,data))
print "Preparing Listening Thread"
listen.start()
print "Starting Listening Thread"
listen.run()
print "Creating Send/Receive Thread"
sandr = threading.Thread(target=srcv(s, conn, data))
print "Preparing Send/Receive Thread"
sandr.start()
print "Connections Now Acceptable"
sandr.run()
if __name__ == '__main__':
sys.exit(start_server())
Please let me know if my code seems clunky/disorganized, I am somewhat new to programming in general.
EDIT:
Another problem I encountered is that I cannot run both of the threads, as when one starts, the other can not be. Why is that, and how can I fix it?

Answer 1

You need to use put the arguments in args= so that the function is not called before listen.start():
listen = threading.Thread(target=listn, args=(s,conn,data))
Not
listen = threading.Thread(target=listn(s,conn,data))
Also you shouldn't call .run(), .start() does that internally on the newly started thread. Therun method is there so that subclasses of Thread can override it.