If I run:
iperf -s -u -B 224.0.31.155
and run
sudo tcpdump -ni any 'host 224.0.31.155'
tcpdump is able to capture something:
tcpdump: verbose output suppressed, use -v or -vv for full protocol decode
listening on any, link-type LINUX_SLL (Linux cooked), capture size 65535 bytes
15:49:15.334484 IP [some ip].14386 > 224.0.31.155.14386: UDP, length 1364
15:49:15.334728 IP [some ip].14386 > 224.0.31.155.14386: UDP, length 1374
15:49:15.375026 IP [some ip].14386 > 224.0.31.155.14386: UDP, length 1058
15:49:15.375184 IP [some ip].14386 > 224.0.31.155.14386: UDP, length 832
However, if I kill my iperf process above, and then start my C++ application that also joins the same group and binds the same port, tcpdump no longer sees the traffic.
Here is the snippet:
struct sockaddr_in mc_addr; /* socket address structure */
struct ip_mreq mc_req; /* multicast request structure */
unsigned int from_len = sizeof(mc_addr); /* source addr length */
/* construct a multicast address structure */
memset(&mc_addr, 0, from_len);
mc_addr.sin_family = AF_INET;
inet_aton(mcastGroup.c_str(), &mc_addr.sin_addr);
mc_addr.sin_port = htons(port);
/* bind to multicast address to socket */
if (bind(s, (struct sockaddr *) &mc_addr, sizeof(mc_addr)) < 0) {
std::cerr << "failed to bind to the port " << port << "|error="
<< strerror(errno) << std::endl;
throw;
}
/* construct an IGMP join request structure */
mc_req.imr_multiaddr.s_addr = inet_addr(mcastGroup.c_str());
mc_req.imr_interface.s_addr = htonl(INADDR_ANY);
/* send an ADD MEMBERSHIP message via setsockopt */
if ((setsockopt(s, IPPROTO_IP, IP_ADD_MEMBERSHIP, (void*) &mc_req,
sizeof(mc_req))) < 0) {
std::cerr << "failed to set socket option to request for membership"
<< std::endl;
throw;
}
tcpdump details:
$ tcpdump --version
tcpdump version 4.1-PRE-CVS_2012_03_26
libpcap version 1.4.0
I just checked it on one of my production servers and it shows the same behavior but I see that my C++ application is processing data properly.
Any idea what's going on?
One potential problem in your code is that you bind your socket to the multicast address. This is not required and may cause all kinds of weird behaviors.
If you only want to send UDP packets you do not need to bind your socket at all. The OS will do it for you.
If you want to send and receive multicast traffic you most likely want to bind to INADDR_ANY on Linux. This is almost an idiom. bind() on UDP sockets has very non-intuitive semantics on Linux. The IP address just has a filtering role. It neither binds to the specified IP address, nor does it bind to the interface associated with that IP address.
Another odd thing is that you assign to mc_req.imr_interface which should not be a member of ip_mreq. I think this should read mc_req.imr_address, but of course if this compiles then I shall stay silent.
IGMP messages are conserved. If the host is already a member of the group, it won't send out a new IGMP membership report message when another application joins. If you're receiving multicasts, be happy.
Related
I'm looking at the udp client example here:
http://www.linuxhowtos.org/data/6/client_udp.c
snippet:
/* UDP client in the internet domain */
struct sockaddr_in server, from;
//...snipped
sock= socket(AF_INET, SOCK_DGRAM, 0);
if (sock < 0) error("socket");
server.sin_family = AF_INET;
hp = gethostbyname(argv[1]);
if (hp==0) error("Unknown host");
bcopy((char *)hp->h_addr,
(char *)&server.sin_addr,
hp->h_length);
server.sin_port = htons(atoi(argv[2]));
length=sizeof(struct sockaddr_in);
//... snipped
n=sendto(sock,buffer,
strlen(buffer),0,(const struct sockaddr *)&server,length);
if (n < 0) error("Sendto");
n = recvfrom(sock,buffer,256,0,(struct sockaddr *)&from, &length);
if (n < 0) error("recvfrom");
//... snipped
I'm trying to understand how it knows where to receive the message from. I know when sendto is called an available port is chosen and that is embedded in the udp message and the server application can read that and reply to it. How does the client code know to receive a message on that port?
This answer: https://stackoverflow.com/a/48245273/2748602 indicates there is kind of an implicit bind when the sendto function is called. How does it work? Is it in fact a bind with a random available port number that is as permanent as if I had called bind or something else? It seems there's some aspect of permanence. Just interested in a little more detail.
There is an implicit bind if the socket is unbound since all packets have to carry both a source port. So the API assumes that if you didn't care enough about the port to bind your socket beforehand, then it can just bind the socket to a random port. And while unfortunately I don't know the implementation details of sendto, I can offer some official documentation.
For Linux, from the udp man page:
When a UDP socket is created, its local and remote addresses are
unspecified. Datagrams can be sent immediately using sendto(2) or
sendmsg(2) with a valid destination address as an argument. When
connect(2) is called on the socket, the default destination
address is set and datagrams can now be sent using send(2) or write(2)
without specifying a destination address. It is still possible to
send to other destinations by passing an address to sendto(2) or
sendmsg(2). In order to receive packets, the socket can be bound to a
local address first by using bind(2). *Otherwise, the socket layer
will automatically assign a free local port out of the range defined
by /proc/sys/net/ipv4/ip_local_port_range and bind the socket to
INADDR_ANY.
For Windows, a snippet from the documentation for Winsock 2's sendto:
If the socket is unbound, unique values are assigned to the local
association by the system, and the socket is then marked as bound. If
the socket is connected, the getsockname function can be used to
determine the local IP address and port associated with the socket.
... there is kind of an implicit bind when the sendto function is called. How does it work? Is it in fact a bind with a random available port number that is as permanent as if I had called bind or something else?
man ip(7):
ip_local_port_range (since Linux 2.2)
This file contains two integers that define the default local
port range allocated to sockets that are not explicitly bound
to a port number—that is, the range used for ephemeral ports.
An ephemeral port is allocated to a socket in the following
circumstances:
* the port number in a socket address is specified as 0 when calling bind(2);
* listen(2) is called on a stream socket that was not previously bound;
* connect(2) was called on a socket that was not previously bound;
* sendto(2) is called on a datagram socket that was not previously bound.
I'm in the process of writing a project for college involving writing a chat client and server using POSIX sockets and C++.
The clients are supposed to converse with each other using P2P, such as each client has his own open UDP socket through which he sends and recieves messages from/to other clients.
My problem is 2-fold:
My UDPSocket class constructor seems to be ignoring the port number completely, binding to port 65535 regardless of the parameter.
The port is binding to IP 255.255.255.255 rather than my own IP (10.0.0.3), or at least that's what i get when I call getpeername.
To the best of my knowledge passing INADDR_ANY should bind to my local address, and passing port number 0 should make the OS choose a free port, what am I doing wrong?
This is the constructor of my UDPSocket class:
UDPSocket::UDPSocket(int port){
socket_fd = socket (AF_INET, SOCK_DGRAM, 0);
// clear the s_in struct
bzero((char *) &in, sizeof(in)); /* They say you must do this */
//sets the sin address
in.sin_family = (short)AF_INET;
in.sin_addr.s_addr = htonl(INADDR_ANY); /* WILDCARD */
in.sin_port = htons((u_short)port);
fsize = sizeof(from);
//bind the socket on the specified address
if(bind(socket_fd, (struct sockaddr *)&in, sizeof(in))<0){
perror ("Error naming channel");
}
}
This is the initialization:
m_Socket = new UDPSocket(0);
And this is the method I use to retrieve the binded address: (UDPSocket inherits Socket)
std::string Socket::GetSocketAddress()
{
struct sockaddr_in addr;
int len = sizeof(addr);
getpeername(socket_fd, (struct sockaddr*)&addr, (socklen_t*)&len);
char ipAddressBuffer[50];
memset(ipAddressBuffer, 0, sizeof(ipAddressBuffer));
sprintf(ipAddressBuffer, "%s:%d", inet_ntoa(addr.sin_addr), ntohs(addr.sin_port));
return ipAddressBuffer;
}
Any help would be greatly appreciated,
Avi.
You're using getpeername , which gives you the remote address of a connected socket. If you check the return value of getpeername(), it should indicate failure.
You need to use getsockname() instead of getpeername() to get the address of your local socket
You need to check that getsockname() succeeds.
Note that your socket is bound to the special 0.0.0.0 address, which means "all local interfaces", so that's what getsockname() will also return.
Answering the more general question "How to set up peer-to-peer communications with UDP":
With UDP sockets, while you can use connect, you generally don't want to, as that restricts you to a single peer per socket. Instead, you want to use a single unconnected UDP socket in each peer with the sendto and recvfrom system calls to send and receive packets with a different address for each packet.
The sendto function takes a packet and a peer address to send it to, while the recvfrom function returns a packet and the peer address it came from. With a single socket, there's no need to multiplexing with select or poll -- you just call recvfrom to get the next packet from any source. When you get a packet, you also get the peer address to send packets (back) to.
On startup, your peer will create a single socket and bind it to INADDR_ANY (allowing it to receive packets on any interface or broadcast address on the machine) and either the specific port assigned to you program or port 0 (allowing the OS to pick any unused port). In the latter case, you'll need to use getsockname to get the port and report it to the user. Once the socket is set up, the peer program can sendto any peer it knows about, or recvfrom any peer at all (including those it does not yet know about).
So the only tricky part is bootstrapping -- getting the first packet(s) flowing so that peers can recieve them and figure out their peer addresses to talk to. One method is specifying peer addresses on the command line when you start each peer. You'll start the first one with no arguments (as it has no peers -- yet). It will just recvfrom (after socket setup) to get packets from peers. Start the second with the address of the first as an argument. It sends a packet (or several) to the first peer, which will then know about the new peer as soon as it gets the first packet. Now start a third client with the addresses of the first two on the command line...
I have a device that is discovered by sending a broadcast packet to 255.255.255.255 on port 4930 and the device responds by sending a packet back to 255.255.255.255 on port 4930.
I have a snippet of C++ code which can send a packet to 255.255.255.255 on port 4930 (both source and destination port), but it can't receive a packet back from the broadcast address 255.255.255.255.
I can see the device is working fine, wireshark can see the packets coming back and forth and the propriety software supplied with the device can discover the device just fine, the problem is with the C++ program so please keep on topic with your responses.
Now, as I have said I can send a packet just find, but firstly I can't bind to the IP address 255.255.255.255 to receive the packets. I can change the multicast address to 239.255.255.250 and the socket will bind but I need the address 255.255.255.255.
My snippet of code is below, I am using VC++2010
bool CPTUProgramDlg::FindPTU(u_short port, const char * Destaddress){
{
//Data to send
char packet_data[10] = {0x44,0x43,0x55,0x44,0x5f,0x50,0x49,0x4e,0x47,0x00};
int packet_size=10;
SOCKET sock;
struct sockaddr_in addr;
sock = socket(AF_INET, SOCK_DGRAM, 0);
// set SO_BROADCAST on a socket to true (1): (so we can transmit to 255 addr)
//In order to use broadcast the options of socket must change
char broadcastON = 1;
setsockopt(sock, SOL_SOCKET, SO_BROADCAST, &broadcastON, sizeof broadcastON);
if (sock < 0)
return false;
addr.sin_family = AF_INET;
addr.sin_port = htons(port);
addr.sin_addr.s_addr = inet_addr(Destaddress); // Specify dest IP
sendto(sock, packet_data, packet_size, 0, (struct sockaddr*)&addr, sizeof(addr));
if (bind(sock,(struct sockaddr*) &addr,sizeof(addr)) != -1){
char Buff[512];
recv(sock,Buff,512,0);
}
closesocket(sock);
}
return 1;
}
Wireshark screenshot to prove packets are being send:
From the wireshark output its seen that the special device is using broadcast to communicate and will use the same port number as source and destination.
Normal socket communication will require using matching port numbers but broadcast messages cannot be exchanged over the same socket, especially when the port numbers do not match as seen with wireshark.
Binding on 255.255.255.255 (INADDR_BROADCAST) should generally work but may be limited by your OS privileges and permissions.
You may try to solve the problem by using two sockets - one for receiving and one for sending. Of course the listening socket have to be setup first and bound to 0.0.0.0 (INADDR_ANY) and port 4930. In this case there is no easy way to filter by destination address (as I wrongly written in my comment) because most standard socket APIs do not provide a way to get the destination addess from the socket. On Linux there is an exception - IP_PKTINFO at SOL_IP...
By using recvfrom you will get the source unicast address of the responding device(s). You have to note that if you have more that one such device on your network you will get more than one response.
I'm working on this project where the source and destination ports are specified for sending a message via a UDP socket in C++. I've got the TCP portion of the project working fine, but I don't understand how to specify both the source and destination ports when setting this up.
The way I would know how to do it is the "receiver" sets up a recvfrom() call, with the port that the "sender" will also use in the sendto() command... but it would need to be the same port.
So, given that I need port x on the "receiver" to talk to port y on the "sender", how would I do that?
Thanks
You can define a source port when you call bind on the sender side. For instance:
sockfd = socket(AF_INET, SOCK_STREAM, 0);
if (sockfd < 0) { /*error*/}
sockaddr_in sin;
sin.sin_family = AF_INET;
sin.sin_addr.s_addr = htonl(INADDR_ANY);
sin.sin_port = htons(source_port); // here
int res = bind(sockfd,(struct sockaddr*)&sin, sizeof(sin));
if (res < 0) { /*error*/}
And the destination port goes into the sockaddr parameter passed to sendto.
If this is one-to-one mapping, i.e. one source talks to one destination, then simply bind(2) the local port and connect(2) to the remote IP and port (contrary to common misconception you can connect UDP sockets). Do that on both sides (with appropriate remote and local IPs/ports of course), and now you can just use recv(2) and send(2) without explicit addressing.
If one side needs to wait for the other to send the first packet, then extract source address/port received with recvfrom(2), and then connect(2) to it.
If, on the other hand, one side acts as a multi-client server, then do same bind(2)/connect(2) dance on the client, but only do bind(2) to local port and then use recvfrom(2)/sendto(2) on the server.
If you need simultaneous duplex communication, then you should use sockets in blocking mode -- fcntl(...O_NONBLOCK...), and use select() to determine if your socket is writable or readable or both. Here is a nice example on how this can be done http://www.lowtek.com/sockets/select.html
In my Linux C++ application I'm using getpeername and getsockname.
when IPv6 enabled on the OS, both getpeername and getsockname return only port!
code:
int GetSockAndPeer(int sock)
{
struct sockaddr_storage ss;
socklen_t salen = sizeof(ss);
struct sockaddr *sa;
struct addrinfo hints, *paddr, *paddrp;
sa = (struct sockaddr *)&ss;
if (getpeername(sock, sa, &salen) != 0)
{
return -1;
}
if (getsockname(sock, sa, &salen) != 0)
{
return -1;
}
}
sa variable hold after the systemcalls in sa_data only the sa_data[0] and sa_data[1] which means port. all the other bytes are 0;
Any help???
Related to RFC2553 you have to use the IN6_IS_ADDR_V4MAPPED and IN6_IS_ADDR_V4COMPAT macros to identify if there is any usable IPv4 information available within yours socket_storage, or to be exact the sockaddr_in6 structure:
struct sockaddr_in6 {
sa_family_t sin6_family; /* AF_INET6 */
in_port_t sin6_port; /* transport layer port # */
uint32_t sin6_flowinfo; /* IPv6 traffic class & flow info */
struct in6_addr sin6_addr; /* IPv6 address */
uint32_t sin6_scope_id; /* set of interfaces for a scope */
};
If both macros returns true, the IPv4 address is in sockaddr_in6.sin6_addr[12-15]:
printf("%u.%u.%u.%u\n", sockaddr_in6.sin6_addr[12], sockaddr_in6.sin6_addr[13], \
sockaddr_in6.sin6_addr[14], sockaddr_in6.sin6_addr[15])
It's important to remember that, unless a socket is connected (or, for a connectionless socket, has transferred data), there may not be any IP addresses, local or remote, associated with the socket.
Let's say the computer is multihomed and has both local and Internet IP addresses. Maybe even multiple local network IP addresses. If you choose to bind a socket to "any" local address (using an INADDR_ANY-type flag), or never call bind() in the first place, the socket API does not have a single local IP address associated with the socket, just a port number at the most. When you call connect() on a socket, the system chooses which local IP to use based on who you are connecting to. So if you connect to a machine over the Internet, your Internet IP is associated with the socket, and if you connect to a machine on the local network, your LAN IP address is used.
So may sure that you connect() to a remote computer or bind() to a specific local IP before you use getsockname(). I wonder if enabling IPv6 has caused your machine to see multiple potential local IPs to use. Obviously you much be connected to a machine to use getpeername().