gdb cannot access c_str() function of std::string in boolean expression - c++

Question

I have a file named testing.cpp:
#include <iostream>
#include <string>
struct Foo {
std::string name;
};
int main() {
Foo* foo = new Foo;
foo->name = "hello";
std::cout << foo->name << "\n";
return 0;
}
I compiled it to a.out, and start gdb using gdb a.out.
GNU gdb (Debian 7.10-1.1) 7.10
...
Reading symbols from a.out...done.
(gdb)
I break at line 12 (std::cout << foo->name << "\n";), and run:
(gdb) break 12
Breakpoint 1 at 0x400990: file testing.cpp, line 12.
(gdb) run
Starting program: ...
Breakpoint 1, main () at testing.cpp:12
12 std::cout << foo->name << "\n";
(gdb)
It can print foo->name and foo->name.c_str():
(gdb) print foo->name
$1 = "hello"
(gdb) print foo->name.c_str()
$2 = 0x613c30 "hello"
It can print boolean expression with foo->name.c_str() in the first clause:
(gdb) print foo->name.c_str() && 1
$3 = true
But it can't when I put foo->name.c_str() in second clause:
(gdb) print 1 && foo->name.c_str()
Attempt to take address of value not located in memory.
(gdb)
Is this a bug?
Edit 1:
Use Case
I was trying to use break ... if ... to break at some point if some strings have certain values. E.g.
(gdb) break 14 if foo->name.size() == 5 && $_streq(foo->name.c_str(), "house")
Breakpoint 2 at 0x400aba: file testing.cpp, line 14
(gdb)
When I continue, gdb show the error message and break at line 14 (return 0;) even though foo->name is "hello" but not "house".
(gdb) continue
Continuing.
hello
Error in testing breakpoint condition:
Attempt to take address of value not located in memory.
Breakpoint 2, main () at testing.cpp:14
14 return 0;
(gdb)
Currently a workaround is access data member of std::string directly:
(gdb) break 14 if foo->name.size() == 5 && \
$_streq(foo->name._M_dataplus._M_p, "house")
Some Observations
Is it because my foo is pointer?
Nope. I tried to use Foo foo; instead of Foo* foo = new Foo;. Problem remains.
Does this problem apply for std::string variable created in main(), oppose to as a data member of some object?
Nope. Seems like it only applies for std::string as a data member. Code below works:
(gdb) list 4,8
4 int main() {
5 std::string name("hello");
6 std::cout << name << "\n";
7 return 0;
8 }
(gdb) break 6
Breakpoint 1 at 0x400a93: file testing.cpp, line 6
(gdb) run
Starting program: ...
Breakpoint 1, main() at testing.cpp:6
6 std::cout << name << "\n";
(gdb) print 1 && name.c_str()
$1 = true
Does this problem unique to c_str() only? How about other function?
No, this problem is not unique to c_str(). It is not even unique to std::string. Seems like it happens when we call member function of object inside another object, i.e. foo.bar.func().