I am working with a Delayed Job that, after its completion, sends an email to the admin user that requested it. So, to do this, I need to know who is the admin user that launched it inside the Spree::Order model.
I've tried with try_spree_current_user and spree_current_user but they don't work returning:
NameError (undefined local variable or method `try_spree_current_user' for #<Spree::Order:0x007f93811d7240>):
app/models/spree/order_decorator.rb:30:in `after_cancel'
app/controllers/spree/admin/orders_controller_decorator.rb:4:in `cancel'
Some how you need to make sure that an admin can launch the order:
# Is this user an admin
if spree_current_user.admin?
# Do some delayed job
# send the email
# because spree_current_user.id is the one that sends it
else
flash[:error] = "You need to be an admin to do this."
redirect_back_or_default(spree.root_path)
end
The above should do what you want to do. You need to test if the current user is an admin then do what he/she needs to do.
I'm sure you meant the OrdersController? Not model.
Related
I want an effect to be applied when a user is entering my website. So therefore I want to check for when a user is coming from outside my website so the effect isnt getting applied when the user is surfing through different urls inside the website, but only when the user is coming from outside my website
You can't really check for where a user has come from specifically. You can check if the user has just arrived on your site by setting a session variable when they load one of your pages. You can check for it before you set it, and if they don't have it, then they have just arrived and you can apply your effect. There's some good examples of how sessions work here: https://developer.mozilla.org/en-US/docs/Learn/Server-side/Django/Sessions
There's a couple of ways to handle this. If you are using function based views, you can just create a separate util function and include it at the top of every page, eg,
utils.py
def first_visit(request):
"""returns the answer to the question 'first visit for session?'
make sure SESSION_EXPIRE_AT_BROWSER_CLOSE set to False in settings for persistance"""
if request.session['first_visit']:
#this is not the first session because the session variable is used.
return False
else:
#This is the first visit
...#do something
#set the session variable so you only do the above once
request.session[first_visit'] = True
return True
views.py
from utils.py import first_visit
def show_page(request):
first_visit = first_visit(request)
This approach gives you some control. For example, you may not want to run it on pages that require login, because you will already have run it on the login page.
Otherwise, the best approach depends on what will happen on the first visit. If you want just to update a template (eg, perhaps to show a message or run a script on th epage) you can use a context processor which gives you extra context for your templates. If you want to interrupt the request, perhaps to redirect it to a separate page, you can create a simple piece of middleware.
docs for middleware
docs for context processors
You may also be able to handle this entirely by javascript. This uses localStorage to store whether or not this is the user's first visit to the site and displays the loading area for 5 seconds if there is nothing in localStorage. You can include this in your base template so it runs on every page.
function showMain() {
document.getElementByID("loading").style.display = "none";
document.getElementByID("main").style.display = "block";
}
const secondVisit = localStorage.getItem("secondVisit");
if (!secondVisit) {
//show loading screen
document.getElementByID("loading").style.display = "block";
document.getElementByID("main").style.display = "none";
setTimeout(5000, showMain)
localStorage.setItem("secondVisit", "true" );
} else {
showMain()
}
Unfortunately I'm using django-channels channels 1.1.8, as I missed all the
updates to channels 2.0. Upgrading now is unrealistic as we've just
launched and this will take some time to figure out correctly.
Here's my problem:
I'm using the *message.user.id *to differentiate between authenticated
users that I need to send messages to. However, there are cases where I'll
need to send messages to un-authenticated users as well - and that message
depends on an external API call. I have done this in ws_connect():
#channel_session_user_from_http
def ws_connect(message):
# create group for user
if str(message.user) == "AnonymousUser":
user_group = "AnonymousUser" + str(uuid.uuid4())
else:
user_group = str(message.user.id)
print(f"user group is {user_group}")
Group(user_group).add(message.reply_channel)
Group(user_group).send({"accept": True})
message.channel_session['get_user'] = user_group
This is only the first part of the issue, basically I'm appending a random
string to each AnonymousUser instance. But I can't find a way to access
this string from the request object in a view, in order to determine who
I am sending the message to.
Is this even achievable? Right now I'm not able to access anything set in
the ws_connect in my view.
EDIT: Following kagronick's advice, I tried this:
#channel_session_user_from_http
def ws_connect(message):
# create group for user
if str(message.user) == "AnonymousUser":
user_group = "AnonymousUser" + str(uuid.uuid4())
else:
user_group = str(message.user.id)
Group(user_group).add(message.reply_channel)
Group(user_group).send({"accept": True})
message.channel_session['get_user'] = user_group
message.http_session['get_user'] = user_group
print(message.http_session['get_user'])
message.http_session.save()
However, http_session is None when user is AnonymousUser. Other decorators didn't help.
Yes you can save to the session and access it in the view. But you need to use the http_session and not the channel session. Use the #http_session decorator or #channel_and_http_session. You may need to call message.http_session.save() (I don't remember, I'm on Channels 2 now.). But after that you will be able to see the user's group in the view.
Also, using a group for this is kind of overkill. If the group will only ever have 1 user, put the reply_channel in the session and do something like Channel(request.session['reply_channel']).send() in the view. That way it doesn't need to look up the one user that is in the group and can send directly to the user.
If this solves your problem please mark it as accepted.
EDIT: unfortunately this only works locally but not in production. when AnonymousUser, message.http_sesssion doesn't exist.
user kagronick got me on the right track, where he pointed that message has an http_session attribute. However, it seems http_session is always None in ws_connect when user is AnonymousUser, which defeats our purpose.
I've solved it by checking if the user is Anonymous in the view, and if he is, which means he doesn't have a session (or at least channels can't see it), initialize one, and assign the key get_user the value "AnonymousUser" + str(uuid.uuid4()) (this way previously done in the consumer).
After I did this, every time ws_connect is called message will have an http_session attribute: Either the user ID when one is logged in, or AnonymousUser-uuid.uuid4().
Is there any way to check if the admin is logged in at front-end in Opencart? I would like to show a notice bar with content "Admin Logged In" when I open my store.
To be precise, in the controller of my module, i would like to add:
$data['admin_logged'] = some_function;
and when I echo it in my .tpl to get 1 if admin is logged in or 0 if not.
Actually i got it done by:
// Check if admin is logged in - frontend
$this->user = new User($this->registry);
$data['admin_logged']=($this->user->isLogged())
Now you can use if($admin_logged) /* do stuff here */
Thank you anyway
Yes, you can check it, using the User class:
$data['admin_logged'] = $this->user->isLogged() ? 1 : 0;
I am new to django/python and working my way through my webapp. I need assistance in solving one of my problems.
In my app, I am planning to assign each user (from auth_user) to one of the group ( from auth_group). Each group can have multiple users. I have entry in auth_group, auth_user and auth_user_groups. Here is my question:
At time of login I want to check that logging user belongs to which group?
I want to keep that group info in session/cache so all pages I can show information about that group only.
If you have any sample code will be great.
Giving support to the very well #trinchet's answer with an example of context_processor code.
Puts inside your webapp a new file called context_processors.py and writes this lines on it:
def user_groups(request):
"""
Add `groups` var to the context with all the
groups the logged in user has, so you can access
in your templates to this var as: {{ groups }}
"""
groups = None
if request.user.is_authenticated():
groups = user.groups
return {'groups': groups}
Finally on your settings.py add 'webbapp.context_processors.user_groups'to TEMPLATE_CONTEXT_PROCESSOR:
TEMPLATE_CONTEXT_PROCESSORS = (
'webbapp.context_processors.user_groups',
)
1) Be user an instance of auth.models.User, you can get all groups the user belong to, through user.groups. If you want to ask at time of login then you should do this in your login view.
2) You can use session or cache approaches to deal with, this is irrelevant, but once you have the group you need to render the pages having this value, i mean, you need to provide the group to the template rendering, to do this I suggest to you using a custom context processor.
I am working on a tiny movie manager by using the out-of-the-box admin module in Django.
I add a "Play" link on the movie admin page to play the movie, by passing the id of this movie. So the backend is something like this:
import subprocess
def play(request, movie_id):
try:
m = Movie.objects.get(pk=movie_id)
subprocess.Popen([PLAYER_PATH, m.path + '/' + m.name])
return HttpResponseRedirect("/admin/core/movie")
except Movie.DoesNotExist:
return HttpResponse(u"The movie is not exist！")
As the code above reveals, every time I click the "play" link, the page will be refreshed to /admin/core/movie, which is the movie admin page, I just do not want the backend to do this kind of things, because I may use the "Search" functions provided by the admin module, so the URL before clicking on "Play" may be something like: "/admin/core/movie/?q=gun", if that response takes effect, then the query criteria will be removed.
So, my thought is whether I can forbid the HttpResponse, in order to let me stay on the current page.
Any suggestions on this issue ?
Thanks in advance.
I used the custom action in admin to implement this function.
So finally I felt that actions are something like procedures, which have no return values, and requests are something like methods(views) with return values...
Thanks !