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How can I convert a string to a byte array in C++?
For example, "Hello" → 48 65 6c 6c 6f.
I'm trying to pattern search the memory with this byte array after.
std::string::c_str() yields the underlyng c string / byte array.
Also see std::string::c_str() for a list of occasions when the returned pointer might be invalidated (basically everytime you modify the string and of course when the std::string itself is destroyed).
You can create a copy of it using memcpy() if required.
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I have a very basic question how can I assign a string value to a variable that already has integer value. For example, int a = 10 then I need to assign a ='hey'. Is it possible in c++?
I think you are new to C++? In C++ you assign the variable a fixed type (int in your case). It is not possibile to change that type inside the scope. You have to convert a to a string and save them in a new variable. How to convert a string (char* or std::string) you can look here:
Easiest way to convert int to string in C++
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I'm trying to make a function that takes the first and last letters of a string, divides them for the modulus and stores them in an array spot related to the modulus number. However I don't know how I would get the first and last letters of the string.
Assuming std::string str, you can use either:
str.front() and str.back() (C++11 and later only).
str[0] and str[str.size()-1], if str is not empty.
You can have the first letter of your string by just using yourString[0] and to get the last latter you can use yourString[yourString.size()-1]
EDIT
As said in the comments, assuming you're using std::string
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Is there any way I can append the size of a particular variable? For instance, if I have:
static_cast<char>(0x0147)
an 8 bit char and I want to increase it to say 16 bits without changing the data type, is that possible?
No.
The size of the object is not only related to its type; the size is defined by the type.
You cannot change one and not the other.
Just initialize a new int16_t from this char if that's what you want.
Or, you could have a vector<char> and add new elements to this collection as needed.
(Shifting has nothing to do with it; that's about transforming data.)
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I am extremely new to C++ so I'm probably asking a very trivial question, but if you could help that'd be great!
I have an array[n].
Indexed from 0 to some unknown value.
I need to access the index of the array, the n value but I need to do so in binary. I am intending to do a bit reversal on it.
So, if I have an array of 2048 points how do I represent the 1024 array in binary?
If you want to write a value in binary, you can do so in C++14 with
int my_binary_value = 0b01010101;
If you'd like to test a specific bit of an int, you can do that by masking it, i.e.
bool is_bit_4_set = my_binary_value & 0b00001000;
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I have a file like:
a [able%5:00:00:capable:00] [able] capable
a [abnormal%3:00:00::] [abnormal]
a [absent%3:00:00::] [absent]
a [absolute%3:00:00::] [absolute] perfect or complete
a [abstract%3:00:00::] [abstract] existing only in the mind
a [abundant%3:00:00::] [abundant] plentiful
I want to get first column "avle", "abnormal" etc to my object. How to crop them and how storage them?
Use the string tokenizer, the best/easiest way to split a line into different variables.
char* word = strtok(line," [%:]");
char* word2 = strtok(0," [%:]");
int value = strtoi(strtok(0," [%:]"));
to store there is a vector container, but there can be used any type of arrays, what is more convenient