Exception handling for <mutex> and <condition_variable> - c++

Question

Assuming
no undefined behaviour occurs,
no deadlocks occur,
mutexes are locked and unlocked in the correct order by the correct threads the correct number of times,
non-recursive mutexes are not locked multiple times,
locking recursive mutexes does not exceed the maximum level of ownership,
no predicates passed to condition variables throw, and
only clocks, time points, and durations provided by the standard library are used with the std:: mutexes and condition variables
is it guaranteed that operating on the different types of std:: mutexes and condition variables (other than on constructing them) does not throw any exceptions (especially of type std::system_error)?
For example, in case of methods like:
void MyClass::setVariable() {
std::lock_guard<std::mutex> const guard(m_mutex);
m_var = 42; // m_var is of type int
m_conditionVariable.notify_all();
}
void MyClass::waitVariable() {
std::unique_lock<std::mutex> lock(m_mutex);
m_conditionVariable.wait(lock, [this]() noexcept { return m_var == 42; });
}
Is it safe to assume noexcept or should one write some try-catch blocks around the callsites? Or are there any caveats?
Please consider all types of mutexes and condition variables in C++11, C++14 and later.

Answer 1

Short answer: No (sorry)
Any of these operations will throw std::system_error if the underlying synchronisation object fails to perform its operation.
This is because correct operation of synchronisation primitives depends on:
available system resources.
some other part of the program not invalidating the primitive
Although in fairness, if (1) is happening it's probably time to redesign the application or run it on a less-loaded machine.
And if (2) is happening, the program is not logically consistent.
That being said,
or should one write some try-catch blocks around the callsites?
Also no.
You should write try/catch blocks under the following conditions:
Where the program is in a position to do something useful about the error condition (such as repairing it or asking the user if he wants to try again)
You would like to add some information to the error and re-throw it in order to provide a diagnostic breadcrumb trail (nested exceptions, for example)
You wish to log the failure and carry on.
Otherwise, the whole point of c++ exception handling is that you allow RAII to take care of resource reacquisition and allow the exception to flow up the call stack until is finds a handler that wants to handle it.
example of creating a breadcrumb trail:
void wait_for_object()
try
{
_x.wait(); // let's say it throws a system_error on a loaded system
}
catch(...)
{
std::throw_with_nested(std::runtime_error(__func__));
}

Answer 2

Thank's to the link T.C. provided now I'd say yes — your code should be safe. Since in the future standard device_or_resource_busy will be removed and as the author of the issue says that this situation can't occur in any reasonable way then there are only 2 possibilities for lock to throw:
(13.1) — operation_not_permitted — if the thread does not have the
privilege to perform the operation.
(13.2) — resource_deadlock_would_occur — if the implementation detects
that a deadlock would occur.
And both of these situations are excluded by your preconditions. So your code should be safe to use noexcept.