I currently am trying to link a researcher's name if they provided a link, otherwise if they provide a blank input or N/A, then I choose not to link their name. I use the information from the researcher object using Django's template language, but when I check the result it ends up linking all of them, and those without input just have href = "" which links back to the homepage.
I've tried using {{r.website_link|length}} instead, but that just creates errors and the page won't load. I'm a newbie to frontend so I'm not sure if my "if" statement is incorrect or if my HTML logic is incorrect.
<div>
{% for r in researcher %}
<div class="researcher">
{% if "{{r.website_link}}" != "N/A" and "{{r.website_link}}" != "" %}
<p><a class="researcherwebname" href="{{ r.website_link }}">{{ r.fullname|title}}</a> | {{ r.institution }} | {{r.position}} | <i>{{ r.des|capfirst }}</i></p>
{% else %}
<p> {{ r.fullname|title}} | {{ r.institution }} | {{r.position}} | <i>{{ r.des|capfirst }}</i></p>
{% endif %}
</div>
{% endfor %}
</div>
I expect it to link researchers with an actual r.website_link input, otherwise the name should be unlinked.
please try
{% if r.website_link %}
{% if r.website_link != "N/A" %}
{# display researcher #}
{% endif %}
{% endif %}
I made this simple markup on a Shopify product-template.liquid section. It's not returning the second image though on different products outside of the ones specified.
{% if product.handle == "e" or "f" %}
{{ '3.png' | asset_url | img_tag }}
{% else %}
{{ '4.png' | asset_url | img_tag }}
{% endif %}
This seems pretty straight forward according to Shopify's documentation. However I can't get 4.png to come up on the other products in the store.
This seems like a really basic problem, but it's doing me in! What am I missing?
You can't chain conditional statements in liquid you need to redefine the comparison.
{% if product.handle == "e" or product.handle == "f" %}
{{ '3.png' | asset_url | img_tag }}
{% else %}
{{ '4.png' | asset_url | img_tag }}
{% endif %}
I'm using this code to set variable and then check if this variable is 1:
{% if pillar['setup_user'] is defined %}
{% set var_setup_user = pillar['setup_user'] %}
{% else %}
{% set var_setup_user = 1 %}
{% endif %}
{% if var_setup_user == 1 %}
setup-user:
cmd.run:
- name: |
...
- shell: /bin/bash
- user: root
{% endif %}
Is there a way to check this in one or maybe two lines?
Thank you
{% set var_setup_user = pillar['setup_user']|d(1) %}
d is the alias for default filter.
Does a normal ternary operator work?
{% set var_setup_user = pillar['setup_user'] if pillar['setup_user'] is defined else 1 %}
Can some one please explain me why the below code is not adding the value in current_count variable. Also I am using django version 1.3. The below code gives following output.
0
"image"
10
"image"
10
"image"
.
.
.
The "image" means actual image is shown.
What I want is "only show 4 images".
{% with current_count=0 %}
{% for row in people|slice:":4" %}
{% if row %}
{% for event in row %}
{% if current_count < 4 %}
{{current_count}}
<div class="latest-photos-image-box">
<img src="{{ event.mainthumb.url }}" alt="{{ event.title }}" />
</div>
{% endif %}
{{ current_count|add:"1" }}
{% endfor %}
{% endif %}
{% endfor %}
{% endwith %}
The problem here is that {{ current_count|add:"1" }} does the addition but doesn't store anything. Please use the loop counters forloop.counter instead.
However, if you need a counter that works regardless of nesting level; here is a recipe (haven't tested but should work):
>>> def monotonic():
... count = 0
... while True:
... yield count
... count += 1
...
>>> counter = monotonic()
>>> # pass it to you request context dictionary
and use {{ counter.next }} each time you need it.
Please also check out this question: Flatten list of lists , you may want to flatten your list of rows of people to a more simple list of people that you can then slice.
{% for event in row|slice:":4" %}
And get rid of the rest.
It is able to write {{ myval.add:5 }}, {{ myval|add:value }} and even {{ myval|add:-5 }}.
However, I can't find out what I should type to add value * -1 like {{ myval|add:-value }}. This doesn't work, sadly.
You need to use double quotes:
{{ myval|add:"-5" }}
This subtracts five from myval.
The built-in Django template tags/filters aren't all-encompassing, but it's super easy to write your own custom template tags: https://docs.djangoproject.com/en/dev/howto/custom-template-tags/
You could make your own subtract template tag pretty easily:
#register.filter
def subtract(value, arg):
return value - arg
Use django-mathfilters from PyPI: https://pypi.python.org/pypi/django-mathfilters
To install :
$ pip install django-mathfilters
Then add mathfilters in your INSTALLED_APPS.
In template:
{% load mathfilters %}
<ul>
<li>8 + 3 = {{ 8|add:3 }}</li>
<li>13 - 17 = {{ 13|sub:17 }}</li>
{% with answer=42 %}
<li>42 * 0.5 = {{ answer|mul:0.5 }}</li>
{% endwith %}
{% with numerator=12 denominator=3 %}
<li>12 / 3 = {{ numerator|div:denominator }}</li>
{% endwith %}
<li>|-13| = {{ -13|abs }}</li>
</ul>
I recently started working with Django and stumbled upon this one as well: I needed a very simple template loop that stops printing after n times and shows a "more" link to toggle the rest of the items.
With great interest I read the struggle of people trying to understand why this is not being added to the Django default filters (since before 2013). I didn't feel like creating a custom template tag and I kind of found a way to subtract 2 variables using strings and add in combination with with and stringformat
Let's say I have a list of items where I want to print the first 2 and hide the rest, showing how many hidden items are there, eg.
John, Anna and 5 others like this (when given a list of 7 items)
As long as the number of visible items is harcoded in the template (eg. 2), it's possible to add the negative 2 |add:"-2", but I wanted the number of visible items to be a variable as well. The Math-filter library as suggested above doesn't seem up to date (I haven't tested it with Django 2.x).
The trick seems to be to use the add helper to concat the strings "-" with the integer as string, so it can be coerced back to a negative integer in a any consecutive calls to the add helper. This doesn't work however if the value is not a string, so that's where the stringformat helper comes in.
With string value
template posts.html (note how visible is explicitely passed as string - alternative below)
{% for post in posts %}
<h4>{{ post.title }}</h4>
...
{% include 'show_likes.html' with likes=post.likes visible="3" %}
{% endfor %}
template show_likes.html (note the add:0 to make the boolean operator work)
{% with show=visible|default:"2" %}
{% for like in likes %}
{% if forloop.counter <= show|add:0 %}
{% if not forloop.first %},{% endif %}
{{ like.username }}
{% endif %}
{% endfor %}
{% if likes|length > show|add:0 %}
{% with rest="-"|add:show %}
and {{ likes|length|add:rest }} more
{% endwith %}
{% endif %}
like this
{% endwith %}
Alternative with integer
You could just convert your integer to a string in the calling template using |stringformat:"d"
If however the number of visible items you want to show is an integer, you'll have to add a call to stringformat:"d" to have it converted to string
template posts.html
{% for post in posts %}
<h4>{{ post.title }}</h4>
...
{% include 'show_likes.html' with likes=post.likes visible=3 %}
{% endfor %}
template show_likes.html
{% with show=visible|default:2 %}
{% with show_str=show|stringformat:"d" %}
{% for like in likes %}
{% if forloop.counter <= show %}
{% if not forloop.first %},{% endif %}
{{ like.username }}
{% endif %}
{% endfor %}
{% if likes|length > show|add:0 %}
{% with rest="-"|add:show_str %}
and {{ likes|length|add:rest }} more
{% endwith %}
{% endif %}
{% endwith %}
{% endwith %}
Since I'm a very beginner with Django and Python, I'm pretty sure this approach is far worse than actually creating a custom helper! So I'm not suggesting anyone should be using this. This was just my attempt on trying to solve this with the available template helpers and without any custom stuff.
Hope this helps
Lo primero es multiplicar por -1 para convertirlo en una valor negativo y guardarlo en una variable y posterior a usar la suma
The first thing is to multiply by -1 to turn it into a negative value
and save it in a variable and then use the add
{% widthratio val2 1 -1 as result %}
{{result|add:val1}}
After search I found that I can make {% with var=value %} with filters to make the arithmetic operations "with other variables or not"
For example: I have x = 5 and y = 3 and need to add the y's value to x value, all what I need is these steps:
1- Create variable x : {% with x=5 %}
2- Create variable y : {% with y=3 %}
3- In my HTML tags, say <h1>, write that : <h1>{{ x|add:y }}</h1>
4- Close the y's with : {% endwith %}
5- Close the x's with : {% endwith %}
Hope it works with you, it worked with me.
{% with i=3 %}
{% with x=1 %}
<h1>{{i|add:x}}</h1> <!-- result is 4 -->
{% endwith %}
{% endwith %}