Variable length string argument in stata syntax - stata

To cleanup data, I am writing a function which takes a list of variables, and replaces a list of strings with empty strings. While I have code to solve the problem, I want to learn how to use a variable length list of strings as an argument.
To get a sense of the simple version, the following would replace any "X" in myval1 and myval2 with an empty string, and is called like:
replace_string_with_empty myval1 myval2, code("X")
The code is,
capture program drop replace_string_with_empty
program replace_string_with_empty
syntax varlist(min=1), Code(string)
foreach var in `varlist' {
replace `var' = "" if `var' == "`code'"
}
end
But what if I have several codes? Forgetting that there may be cleaner ways to do this, I would like to call this as things like
replace_string_with_empty myval1 myval2, codes("X" "NONE")
But I can't figure out the type in the syntax command, etc. For example, the following does not work
capture program drop replace_string_with_empty
program replace_string_with_empty
syntax varlist(min=1), Codes(namelist)
foreach var in `varlist' {
foreach code in `codes' {
replace `var' = "" if `var' == "`code'"
}
}
end
Any ideas? (again, I am sure there are better ways to solve this exact problem, but I want to figure out how to use the syntax in this way for other tasks as well.

Here's a simple example of one approach to this. The asis option will leave the quotes alone, but we will then need to use compound quotes when referring to the strings that are to be recoded to null:
capture program drop replace_string_with_empty
program replace_string_with_empty
syntax varlist(min=1 string), Codes(string asis)
tokenize `"`codes'"'
while "`1'" != "" {
foreach var of varlist `varlist' {
replace `var' = "" if `var'==`"`1'"'
}
macro shift
}
end
sysuse auto, clear
clonevar make2=make
replace_string_with_empty make*, codes("AMC Concord" "AMC Spirit" "Audi 5000")

Related

R - looping across 2 objects

I'm trying to do something fairly simple (I think) but I can't get my head round it. I'm trying to write a loop that checks if a character variable in a data frame contains any of a certain list of substrings, and to assign a corresponding value to a dummy variable.
so, imagine a data.frame, n=2000, with a variable data.frame$text. Furthermore, I have a character vector containing all the substrings I want to text data.frame$text for. Let's call it hillary_exists :
hillary_exists <- c("Hilary Clinton", "hilary clinton","hilaryclinton", "hillaryclinton", "HilaryClinton",
"HillaryClinton","Hillary Clinton", "Hillary Rodham Clinton", "Hillary", "Hilary", "#Hillary2016", "#ImWithHer",
"Hillary2016", "hillary", "hilary", "Clinton 2016", "Clinton", "Secretary of State Clinton",
"Senator Clinton", "Hilary Rodham", "Hilary Rodham Clinton", "Hilary Rodham-Clinton", "Hillary Rodham-Clinton")
Now, I want my loop to test every row of data.frame$text for the existence of every element of hillary_exists, and if any of them is TRUE, to generate a new value of 1 for the variable data.frame$hillary_mention . This is what I tried:
for(i in hillary_exists){
if(grepl(hillary_exists[i], data.frame$text)){
data.frame$hillary_mention <- 1
} else {
data.frame$hillary_mention <- 0 }
}
But obviously I'm missing the i component for the data.frame$text element, but I don't know how to address it.
Any help would be greatly appreciated! Thanks
One approach we can use to get this to work is to turn hillary_exists into a regex: hillary_regex <- paste(hillary_exists, collapse = "|"). Essentially, this just takes all of your terms and turns it into a big OR statement. This takes care of one of the loops for us automatically. Next, we just loop over our text column, data.frame$text, using sapply.
data.frame$hillary_mention <- sapply(data.frame$text, function(s) grepl(hillary_regex, s, ignore.case = TRUE))
It's good to use ignore.case = TRUE here because there may be mentions in the text that aren't accounted for in hillary_exists, such as "hIllary cLinTon".

Dynamic regexprep in MATLAB

I have the following strings in a long string:
a=b=c=d;
a=b;
a=b=c=d=e=f;
I want to first search for above mentioned pattern (X=Y=...=Z) and then output like the following for each of the above mentioned strings:
a=d;
b=d;
c=d;
a=b;
a=f;
b=f;
c=f;
d=f;
e=f;
In general, I want all the variables to have an equal sign with the last variable on the extreme right of the string. Is there a way I can do it using regexprep in MATLAB. I am able to do it for a fixed length string, but for variable length, I have no idea how to achieve this. Any help is appreciated.
My attempt for the case of two equal signs is as follows:
funstr = regexprep(funstr, '([^;])+\s*=\s*+(\w+)+\s*=\s*([^;])+;', '$1 = $3; \n $2 = $3;\n');
Not a regexp but if you stick to Matlab you can make use of the cellfun function to avoid loop:
str = 'a=b=c=d=e=f;' ; %// input string
list = strsplit(str,'=') ;
strout = cellfun( #(a) [a,'=',list{end}] , list(1:end-1), 'uni', 0).' %'// Horchler simplification of the previous solution below
%// this does the same than above but more convoluted
%// strout = cellfun( #(a,b) cat(2,a,'=',b) , list(1:end-1) , repmat(list(end),1,length(list)-1) , 'uni',0 ).'
Will give you:
strout =
'a=f;'
'b=f;'
'c=f;'
'd=f;'
'e=f;'
Note: As Horchler rightly pointed out in comment, although the cellfun instruction allows to compact your code, it is just a disguised loop. Moreover, since it runs on cell, it is notoriously slow. You won't see the difference on such simple inputs, but keep this use when super performances are not a major concern.
Now if you like regex you must like black magic code. If all your strings are in a cell array from the start, there is a way to (over)abuse of the cellfun capabilities to obscure your code do it all in one line.
Consider:
strlist = {
'a=b=c=d;'
'a=b;'
'a=b=c=d=e=f;'
};
Then you can have all your substring with:
strout = cellfun( #(s)cellfun(#(a,b)cat(2,a,'=',b),s(1:end-1),repmat(s(end),1,length(s)-1),'uni',0).' , cellfun(#(s) strsplit(s,'=') , strlist , 'uni',0 ) ,'uni',0)
>> strout{:}
ans =
'a=d;'
'b=d;'
'c=d;'
ans =
'a=b;'
ans =
'a=f;'
'b=f;'
'c=f;'
'd=f;'
'e=f;'
This gives you a 3x1 cell array. One cell for each group of substring. If you want to concatenate them all then simply: strall = cat(2,strout{:});
I haven't had much experience w/ Matlab; but your problem can be solved by a simple string split function.
[parts, m] = strsplit( funstr, {' ', '='}, 'CollapseDelimiters', true )
Now, store the last part of parts; and iterate over parts until that:
len = length( parts )
for i = 1:len-1
print( strcat(parts(i), ' = ', parts(len)) )
end
I do not know what exactly is the print function in matlab. You can update that accordingly.
There isn't a single Regex that you can write that will cover all the cases. As posted on this answer:
https://stackoverflow.com/a/5019658/3393095
However, you have a few alternatives to achieve your final result:
You can get all the values in the line with regexp, pick the last value, then use a for loop iterating throughout the other values to generate the output. The regex to get the values would be this:
matchStr = regexp(str,'([^=;\s]*)','match')
If you want to use regexprep at any means, you should write a pattern generator and a replace expression generator, based on number of '=' in the input string, and pass these as parameters of your regexprep func.
You can forget about Regex and Split the input to generate the output looping throughout the values (similarly to alternative #1) .

Google sheet : REGEXREPLACE match everything except a particular pattern

I would try to replace everything inside this string :
[JGMORGAN - BANK2] n° 10 NEWYORK, n° 222 CAEN, MONTELLIER, VANNES / TARARTA TIs
1303222074, 1403281851 & 1307239335 et Cloture TIs 1403277567,
1410315029
Except the following numbers :
1303222074
1403281851
1307239335
1403277567
1410315029
I have built a REGEX to match them :
1[0-9]{9}
But I have not figured it out to do the opposite that is everything except all matches ...
google spreadsheet use the Re2 regex engine and doesn't support many usefull features that can help you to do that. So a basic workaround can help you:
match what you want to preserve first and capture it:
pattern: [0-9]*(?:[0-9]{0,9}[^0-9]+)*(?:([0-9]{9,})|[0-9]*\z)
replacement: $1 (with a space after)
demo
So probably something like this:
=TRIM(REGEXREPLACE("[JGMORGAN - BANK2] n° 10 NEWYORK, n° 222 CAEN, MONTELLIER, VANNES / TARARTA TIs 1303222074, 1403281851 & 1307239335 et Cloture TIs 1403277567, 1410315029"; "[0-9]*(?:[0-9]{0,9}[^0-9]+)*(?:([0-9]{9,})|[0-9]*\z)"; "$1 "))
You can also do this with dynamic native functions:
=REGEXEXTRACT(A1,rept("(\d{10}).*",counta(split(regexreplace(A1,"\d{10}","#"),"#"))-1))
basically it is first split by the desired string, to figure out how many occurrences there are of it, then repeats the regex to dynamically create that number of capture groups, thus leaving you in the end with only those values.
First of all thank you Casimir for your help. It gave me an idea that will not be possible with a built-in functions and strong regex lol.
I found out that I can make a homemade function for my own purposes (yes I'm not very "up to date").
It's not very well coded and it returns doublons. But rather than fixing it properly, I use the built in UNIQUE() function on top of if to get rid of them; it's ugly and I'm lazy but it does the job, that is, a list of all matches of on specific regex (which is: 1[0-9]{9}). Here it is:
function ti_extract(input) {
var tab_tis = new Array();
var tab_strings = new Array();
tab_tis.push(input.match(/1[0-9]{9}/)); // get the TI and insert in tab_tis
var string_modif = input.replace(tab_tis[0], " "); // modify source string (remove everything except the TI)
tab_strings.push(string_modif); // insert this new string in the table
var v = 0;
var patt = new RegExp(/1[0-9]{9}/);
var fin = patt.test(tab_strings[v]);
var first_string = tab_strings[v];
do {
first_string = tab_strings[v]; // string 0, or the string with the first removed TI
tab_tis.push(first_string.match(/1[0-9]{9}/)); // analyze the string and get the new TI to put it in the table
var string_modif2 = first_string.replace(tab_tis[v], " "); // modify the string again to remove the new TI from the old string
tab_strings.push(string_modif2);
v += 1;
}
while(v < 15)
return tab_tis;
}

Stata - run code if variable name contained in local

I would like to have an if condition in Stata which runs the code in braces for a certain variable only if that variable's name is contained in a local. E.g.
if (`variable` element of `variablenames_local`) {
gen variable2 = variable + 2
}
How can this be done in Stata?
You can use extended macro functions for that, which are documented in help extended_fcn. In this case help macrolist is very useful. (I never remember the names of those help-files, instead I usually type help macro or help local and follow the links in that help-file.)
sysuse auto, clear
local vars "price mpg foreign"
foreach var of varlist _all {
if `: list var in vars' {
di "do something smart with `var'"
}
}
// alternatively:
foreach var of varlist `vars' {
di "do something smart with `var'"
}

VB.Net Matching and replacing the contents of multiple overlapping sets of brackets in a string

I am using vb.net to parse my own basic scripting language, sample below. I am a bit stuck trying to deal with the 2 separate types of nested brackets.
Assuming name = Sam
Assuming timeFormat = hh:mm:ss
Assuming time() is a function that takes a format string but
has a default value and returns a string.
Hello [[name]], the time is [[time(hh:mm:ss)]].
Result: Hello Sam, the time is 19:54:32.
The full time is [[time()]].
Result: The full time is 05/06/2011 19:54:32.
The time in the format of your choice is [[time([[timeFormat]])]].
Result: The time in the format of your choice is 19:54:32.
I could in theory change the syntax of the script completely but I would rather not. It is designed like this to enable strings without quotes because it will be included in an XML file and quotes in that context were getting messy and very prone to errors and readability issues. If this fails I could redesign using something other than quotes to mark out strings but I would rather use this method.
Preferably, unless there is some other way I am not aware of, I would like to do this using regex. I am aware that the standard regex is not really capable of this but I believe this is possible using MatchEvaluators in vb.net and some form of recursion based replacing. However I have not been able to get my head around it for the last day or so, possibly because it is hugely difficult, possibly because I am ill, or possibly because I am plain thick.
I do have the following regex for parts of it.
Detecting the parentheses: (\w*?)\((.*?)\)(?=[^\(+\)]*(\(|$))
Detecting the square brackets: \[\[(.*?)\]\](?=[^\[+\]]*(\[\[|$))
I would really appreciate some help with this as it is holding the rest of my project back at the moment. And sorry if I have babbled on too much or not put enough detail, this is my first question on here.
Here's a little sample which might help you iterate through several matches/groups/captures. I realize that I am posting C# code, but it would be easy for you to convert that into VB.Net
//these two may be passed in as parameters:
string tosearch;//the string you are searching through
string regex;//your pattern to match
//...
Match m;
CaptureCollection cc;
GroupCollection gc;
Regex r = new Regex(regex, RegexOptions.IgnoreCase);
m = r.Match(tosearch);
gc = m.Groups;
Debug.WriteLine("Number of groups found = " + gc.Count.ToString());
// Loop through each group.
for (int i = 0; i < gc.Count; i++)
{
cc = gc[i].Captures;
counter = cc.Count;
int grpnum = i + 1;
Debug.WriteLine("Scanning group: " + grpnum.ToString() );
// Print number of captures in this group.
Debug.WriteLine(" Captures count = " + counter.ToString());
if (cc.Count >= 1)
{
foreach (Capture cap in cc)
{
Debug.WriteLine(string.format(" Capture found: {0}", cap.ToString()));
}
}
}
Here is a slightly simplified version of the code I wrote for this. Thanks for the help everyone and sorry I forgot to post this before. If you have any questions or anything feel free to ask.
Function processString(ByVal scriptString As String)
' Functions
Dim pattern As String = "\[\[((\w+?)\((.*?)\))(?=[^\(+\)]*(\(|$))\]\]"
scriptString = Regex.Replace(scriptString, pattern, New MatchEvaluator(Function(match) processFunction(match)))
' Variables
pattern = "\[\[([A-Za-z0-9+_]+)\]\]"
scriptString = Regex.Replace(scriptString, pattern, New MatchEvaluator(Function(match) processVariable(match)))
Return scriptString
End Function
Function processFunction(ByVal match As Match)
Dim nameString As String = match.Groups(2).Value
Dim paramString As String = match.Groups(3).Value
paramString = processString(paramString)
Select Case nameString
Case "time"
Return getLocalValueTime(paramString)
Case "math"
Return getLocalValueMath(paramString)
End Select
Return ""
End Function
Function processVariable(ByVal match As Match)
Try
Return moduleDictionary("properties")("vars")(match.Groups(1).Value)
Catch ex As Exception
End Try
End Function