C++ unique_ptr and arrays - c++

Question

I'm trying to use arrays with unique_ptr with no success.
What is the correct way to declare a unique_ptr of some size?
(size is some paramter).
unique_ptr<A[]> ptr = make_unique<A[]>(size);
Here's an example:
#include <iostream>
#include <string>
#include <vector>
#include <functional>
#include <memory>
using namespace std;
class A {
string str;
public:
A(string _str): str(_str) {}
string getStr() {
return str;
}
};
int main()
{
unique_ptr<A[]> ptr = make_unique<A[]>(3);
}
This is not working, however, if I delete the constructor of A, it works.
I want the 3 to represent the size of the array, and not an argument to A's constructor, how do I make that happen?

Answer 1

This is not working, however, if I delete the constructor of A, it
works.
When you removed the user defined constructor, the compiler implicitly generates a default one. When you provide a user defined constructor, the compiler doesn't implicitly generate a default constructor.
std::make_unique<T[]> requires the use of default constructors...
So, provide one, and all should work well
#include <iostream>
#include <string>
#include <vector>
#include <functional>
#include <memory>
using namespace std;
class A {
string str;
public:
A() = default;
A(string _str): str(_str) {}
string getStr() {
return str;
}
};
int main()
{
unique_ptr<A[]> ptr = make_unique<A[]>(3);
}