String no print c++ - c++

Question

i'm very new in programming, i have this big code, but when i try to print the data never prints the string variable, can you help?
this is just for
i use "goto" just for practicall reassons.
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;
class producto
{
public:
int id;
string nombre;
string descripcion;
int precio;
void registrar();
void ver();
};
void producto::registrar()
{
cout << "Codigo:" << endl;
cin >> id;
cin.ignore();
cout << "Nombre del producto:" << endl;
getline(cin, nombre);
cout << "Descripcion del producto:" << endl;
getline(cin, descripcion);
cout << "Precio:" << endl;
cin >> precio;
}
void producto::ver()
{
cout << "ID del producto:";
cout << id << endl;
cout << "Nombre del producto:" << endl;
cout << nombre;
cout << "Descripcion del producto:";
cout << descripcion<<endl;
cout << "Precio:";
cout << "$" << precio << endl;
}
int main()
{
menu1:
int menu;
producto cosa;
cout << "************************" << endl;
cout << "1.- Registrar Producto" << endl;
cout << "2.- Ver Producto" << endl;
cout << "************************" << endl;
cin >> menu;
cin.ignore();
switch (menu)
{
case 1:
cout << "INGRESE PRODUCTO NUEVO:\nPresione enter para continuar" << endl;
cin.ignore();
system("cls");
cosa.registrar();
cin.ignore();
break;
case 2:
cosa.ver();
cout << "Presione enter para regresar al menu principal." << endl;
cin.ignore();
break;
}
goto menu1;
return 0;
}
Edit
Here is the int main

Answer 1

The use of goto is not recommended and considered a very bad practice even for a beginner. If you are begining in C++, following best practice is the best way to begin. The goto is supported in C/C++ only for backward compatibility.
For your issue try to use a loop instead of a goto.
int main()
{
//Condition to show the menu or exit
bool bContinue = true;
producto cosa;
do{
int menu;
cout << "************************" << endl;
cout << "1.- Registrar Producto" << endl;
cout << "2.- Ver Producto" << endl;
cout << "3.- Exit" << endl;
cout << "************************" << endl;
cin >> menu;
cin.ignore();
switch (menu)
{
case 1:
cout << "INGRESE PRODUCTO NUEVO:\nPresione enter para continuar" << endl;
cin.ignore();
system("cls");
cosa.registrar();
cin.ignore();
break;
case 2:
cosa.ver();
cout << "Presione enter para regresar al menu principal." << endl;
cin.ignore();
break;
case 3:
bContinue = false;
break;
}
}while(bContinue)
return 0;
}
Like this way, your issue will be fixed and you learn a better way to do it.