C++ simple matrix - c++

Question

can someone fix my code?
this is the result that should be showed when i input number 5 in c++
1
2 6
3 7 10
4 8 11 13
5 9 12 14 15
my result:
1
2 6
3 7 10
4 8 11 14
5 9 12 15 18
my code:
#include <iostream.h>
#include <conio.h>
#include <math.h>
void main()
{
int n,i,j;
cout<<"insert number"<<endl;
cin>>n;
for (i=1;i<=n;i++)
{
int y=1;
int g=1;
cout<<i<<" ";
for (j=1;j<=i-1;j++)
{
int x=n;
int b=i;
x--;
g--;
cout<<(x*y)+b+g<<" ";
y++;
}
cout<<endl;
}
getch ();
}
what did i do wrong?
sorry if my code messy i'm a c++ new learner.

Answer 1

You could it like this:
#include <iostream>
using namespace std;
int main()
{
int n , i ,j, sum;
cout << "masukkan bilanga" << endl;
cin >> n;
for(i = 0; i < n; i++)
{
cout << i + 1 << " ";
sum = i + 1;
for(j = 0; j < i; j++)
{
sum += n - 1 - j;
cout << sum << " ";
}
cout << endl;
}
return 0;
}
where the key point is that you want to print all the numbers, starting from 1, in a column-major manner, until a triangular n x n matrix is created.
Driven from the output, one can easily see that every element of the next column is what the current element is, plus n - 1, and that factor decreases by one as we advance to the right part of the matrix.

Answer 2

Try this code, hope this is what you need:
#include <iostream>
#include <string>
void printMatrix(int number);
void main()
{
int number = 1;
std::cout << "Enter a number: ";
std::cin >> number;
printMatrix(number);
}
void printMatrix(int number) {
std::cout << std::endl;
for (int i = 1; i <= number; i++) {
std::cout << i << " ";
int n = i;
for(int j = 1; j < i; j++) {
n += number - j;
std::cout << n << " ";
}
std::cout << std::endl;
}
}