<a rel="profile-edit" class="app js-user-name" href="/profile/0471482493?from_my_profile=1">Mia</a></b> <
Hello I have a variable defined with the above text can someone please tell me the regex that would be required to extract jst the word "Mia" from the html? The word will not always be Mia.
Thank you in advance
Use this pattern:
/>.*?([^<]+)/
Online Demo
Related
I am trying to use Dreamweaver Find and Replace regex feature, to find and replace all href links that start with "/url-to-page.html" to "./url-to-page.html"? But not sure how to do so. Can someone please help with any example on how to do so (Regex required to do so) ? Thanks
Find : <a href="\/(.*?)">
Replace: <a href="./$1">
Make sure you check Use regular expression at the bottom
I would say if you just had to do this for a single string:
Find: .*/url-to-page.html
Replace: ./url-to-page.html
href="(.*)" to search and find it in all your tags
attributeName=(.*) to pin your regex search
I am using angularjs. I want to use validation for my name field. I am a beginner in regex expressions.
I want that the first letter of every word should be capital.
For E.g Naveen Kumar should be valid
and Naveen kumar is invalid.
I am using ng-pattern to validate the name field. What regex expression should i use? Appreciate your help.
You can use this regex with ng-pattern:
ng-pattern="/^\b[A-Z][a-z]*(\s*\b[A-Z][a-z]*\b)*$/"
Demo
This regex will match only entries that have words (that do not contain digits or underscore) in title case only. Thus, Avinash Raj1 or Avinash_Raj Raj will fail the validation.
Example code:
<label>Single word:
<input type="text" name="input" ng-model="example.text"
ng-pattern="/^\b[A-Z][a-z]*(\s*\b[A-Z][a-z]*\b)*$/" required ng-trim="false">
</label>
You can use
^\b(?:[A-Z]\w+\b(?:\s*)?)+$
See Demo and Explanation
How about ^(\b[A-Z]\w*\s*)+$?
See https://regex101.com/r/qP5xG5/1
I need some help with Regular expression to Search and Replace in Sublime to do the following.
I have HTML-code with links like
href="http://www.example.com/test=123"
href="http://www.example.com/test=6546"
href="http://www.example.com/test=3214"
I want to replace them with empty links:
href=""
href=""
href=""
Please help me to create a Reg. ex. filter to match my case. I guess it would sound like "starts with Quote, following with http:// .... ends with Quote and has digitals and '=' sign", but I'm not very confident of how to write this in Reg. ex. way.
(?<=href=")[^"]*
Try this.Replace by empty string.
See demo.
https://regex101.com/r/sH8aR8/40
Sorry this might be a simple question, but I could not figure it out. What I need is to filter out all the <a href...> and </a> strings out from a html text. Not sure what regular expression I should use? I tried the following search without any luck:
/<\shref^(>)>
what I mean here is to search for any string starting with "< href" and any string not containing '>' and finally '>'. My search code is not working. What is the correct one?
If I understand what you're looking for it should be <\shref[^>]*>.
Another way would be to use non-greedy matching:
/<a\shref.\{-}>
I think I got it:
/<a\shref[^>]+>
where [] is a set and ^ is not.
I have a string like this:
This <span class="highlight">is</span> a very "nice" day!
What should my RegEx-pattern in VB look like, to find the quotes within the tag? I want to replace it with something...
This <span class=^highlight^>is</span> a very "nice" day!
Something like <(")[^>]+> doesn't work :(
Thanks
It depends on your regex flavor, but this works for most of them:
"(?=[^<]*>)
EDIT: For anyone curious how this works. This translates into English as "Find a quote that is followed by a > before the next <".
Regexes are fundamentally bad at parsing HTML (see Can you provide some examples of why it is hard to parse XML and HTML with a regex? for why). What you need is an HTML parser. See Can you provide an example of parsing HTML with your favorite parser? for examples using a variety of parsers.
If you are using VB.net you should be able to use HTMLAgilityPack.
Try this: <span class="([^"]+?)?">
This should get your the first attribute value in a tag:
<[^">]+"(?<value>[^"]*)"[^>]*>
If your intention is to replace ALL quotation marks within tags, you could use the following regular expression:
(<[^>"]*)(")([^>]*>)
That will isolate the substrings before and after your quotation mark. Note that this does not attempt to match opening and closing quotation marks. It simply matches a quotation mark within a tag.