#!/bin/bash
echo "enter the ip address:"
read s
if [[ $s =~ ^(([0-9a-fA-F]{1,4}:){7,7}[0-9a-fA-F]{1,4}|([0-9a-fA-F]{1,4}:){1,7}:|([0-9a-fA-F]{1,4}:){1,6}:[0-9a-fA-F]{1,4}|([0-9a-fA-F]{1,4}:){1,5}(:[0-9a-fA-F]{1,4}){1,2}|([0-9a-fA-F]{1,4}:){1,4}(:[0-9a-fA-F]{1,4}){1,3}|([0-9a-fA-F]{1,4}:){1,3}(:[0-9a-fA-F]{1,4}){1,4}|([0-9a-fA-F]{1,4}:){1,2}(:[0-9a-fA-F]{1,4}){1,5}|[0-9a-fA-F]{1,4}:((:[0-9a-fA-F]{1,4}){1,6})|:((:[0-9a-fA-F]{1,4}){1,7}|:)|fe80:(:[0-9a-fA-F]{0,4}){0,4}%[0-9a-zA-Z]{1,}|::(ffff(:0{1,4}){0,1}:){0,1}((25[0-5]|(2[0-4]|1{0,1}[0-9]){0,1}[0-9])\.){3,3}(25[0-5]|(2[0-4]|1{0,1}[0-9]){0,1}[0-9])|([0-9a-fA-F]{1,4}:){1,4}:((25[0-5]|(2[0-4]|1{0,1}[0-9]){0,1}[0-9])\.){3,3}(25[0-5]|(2[0-4]|1{0,1}[0-9]){0,1}[0-9]))$ ]]; then
echo -e '\E[47;31m'"\033[1mIPv6 Format\033[0m"
echo -n "The IPv6 Address Expanded Form:"
EXPANDED=`sipcalc $s | fgrep Expand | cut -d '-' -f 2`
echo -e "\033[32m $EXPANDED\033[0m"
echo -n "IPv6 address Compress Form:"
Compress=`sipcalc $s | fgrep Comp | cut -d '-' -f 2`
echo -e "\033[32m$Compress\033[0m"
echo -n "Address Type of IPv6:"
type=`sipcalc $s | fgrep type | cut -d '-' -f 2,3,4`
comment=`sipcalc $s | fgrep Comment | cut -d '-' -f 2`
echo -e "\033[32m $type$comment\033[0m"
else
echo -e '\E[37;44m'"\033[1mNOT VALID IPv6 address\033[0m"
fi
Hello everyone. I am trying to validate IPv6 addresses using this script. It is working well. The problem is that it's also accepting IPs like 1111:2222:3333:4444::. Could you help me to avoid this types of IPs?
Why don't you use built-in linux utility,
ipcalc --ipv6 1111:2222:3333:4444::
If it returns nothing then you've provided correct IP
If you provide incorrect IP it returns something like,
ipcalc: bad IPv6 address:
Hope it helps.
This regular expression should do the trick :
([0-9a-fA-F]{1,4}:){7}[0-9a-fA-F]{1,4}
It matches 8 blocks of 1 to 4 hexadecimal values, joined by 7 :.
Related
I have text like:
TEXT="I need to replace the hostname [[google.com]] with it's ip in side the text"
Is there a way to use something like below, but working?
sed -Ee "s/\[\[(.*)\]\]/`host -t A \1 | rev | cut -d " " -f1 | rev`/g" <<< $TEXT
looks like the value of \1 is not being passed to the shell command used inside sed.
Thanks
Backquote interpolation is performed by the shell, not by sed. This means that your backquotes will either be replaced by the output of a command before the sed command is run, or (if you correctly quote them) they will not be replaced at all, and sed will see the backquotes.
You appear to be trying to have sed perform a replacement, then have the shell perform backquote interpolation.
You can get the backquotes past the shell by quoting them properly:
$ echo "" | sed -e 's/^/`hostname`/'
`hostname`
However, in that case you will have to use the resulting string in a shell command line to cause backquote interpolation again.
Depending on how you feel about awk, perl, or python, I'd suggest you use one of them to do this job in a single pass. Alternatively, you could make a first pass extracting the hostnames into a command without backquotes, then execute the commands to get the IP addresses you want, then replace them in another pass.
It's got to be a two part command, one to get a variable that bash can use, the other to do a straight-up /s/ replacement with sed.
TEXT="I need to replace the hostname [[google.com]] with it's ip in side the text"
DOMAIN=$(echo $TEXT | sed -e 's/^.*\[\[//' -e 's/\]\].*$//')
echo $TEXT | sed -e 's/\[\[.*\]\]/'$(host -tA $DOMAIN | rev | cut -d " " -f1 | rev)'/'
But, more cleanly using how to split a string in shell and get the last field
TEXT="I need to replace the hostname [[google.com]] with it's ip in side the text"
DOMAIN=$(echo $TEXT | sed -e 's/^.*\[\[//' -e 's/\]\].*$//')
HOSTLOOKUP=$(host -tA $DOMAIN)
echo $TEXT | sed -e 's/\[\[.*\]\]/'${HOSTLOOKUP##* }/
The short version is that you can't mix sed and bash the way you're expecting to.
This works:
#!/bin/bash
txt="I need to replace the hostname [[google.com]] with it's ip in side the text"
host_name=$(sed -E 's/^[^[]*\[\[//; s/^(.*)\]\].*$/\1/' <<<"$txt")
ip_addr=$(host -tA "$host_name" | sed -E 's/.* ([0-9.]*)$/\1/')
echo "$txt" | sed -E 's/\[\[.*\]\]/'"$ip_addr/"
# I need to replace the hostname 172.217.4.174 with it's ip in side the text
Thank you all,
I made the below solution:
function host_to_ip () {
echo $(host -t A $1 | head -n 1 | rev | cut -d" " -f1 | rev)
}
function resolve_hosts () {
local host_placeholders=$(grep -o -e "##.*##" $1)
for HOST in ${host_placeholders[#]}
do
sed -i -e "s/$HOST/$(host_to_ip $(sed -Ee 's/##(.*)##/\1/g' <<< $HOST))/g" $1
done
}
Where resolve_hosts gets a text file as an argument
I have a string something like this
xsd:import schemaLocation="AppointmentManagementService.xsd6.xsd" namespace=
I want to extract the following from it :
AppointmentManagementService.xsd6.xsd
I have tried using regex, bash and sed with no success. Can someone please help me out with this?
The regex that I used was this :
/AppointmentManagementService.xsd\d{1,2}.xsd/g
Your string is:
nampt#nampt-desktop:$ cat 1
xsd:import schemaLocation="AppointmentManagementService.xsd6.xsd" namespace=
Try with awk:
cat 1 | awk -F "\"" '{print $2}'
Output:
AppointmentManagementService.xsd6.xsd
sed doesn't recognize \d, use [0-9] or [[:digit:]] instead:
sed 's/^.*schemaLocation="\([^"]\+[[:digit:]]\{1,2\}\.xsd\)".*$/\1/g'
## or
sed 's/^.*schemaLocation="\([^"]\+[0-9]\{1,2\}\.xsd\)".*$/\1/g'
You can use bash native regex matching:
$ in='xsd:import schemaLocation="AppointmentManagementService.xsd6.xsd" namespace='
$ if [[ $in =~ \"(.+)\" ]]; then echo "${BASH_REMATCH[1]}"; fi
Output:
AppointmentManagementService.xsd6.xsd
Based on your example, if you want to grant, at least, 1 or, at most, 2 digits in the .xsd... component, you can fine tune the regex with:
$ if [[ $in =~ \"(AppointmentManagementService.xsd[0-9]{1,2}.xsd)\" ]]; then echo "${BASH_REMATCH[1]}"; fi
using PCRE in GNU grep
grep -oP 'schemaLocation="\K.*?(?=")'
this will output pattern matched between schemaLocation=" and very next occurrence of "
Reference:
https://unix.stackexchange.com/a/13472/109046
Also we can use 'cut' command for this purpose,
[root#code]# echo "xsd:import schemaLocation=\"AppointmentManagementService.xsd6.xsd\" namespace=" | cut -d\" -f 2
AppointmentManagementService.xsd6.xsd
s='xsd:import schemaLocation="AppointmentManagementService.xsd6.xsd" namespace='
echo $s | sed 's/.*schemaLocation="\(.*\)" namespace=.*/\1/'
I'm writing my function to replace an effective option in a file to my setting.
The 1.txt is like:
PasswordAuthentication yes
PermitRootLogin yes
My function will process the file then output like:
#PasswordAuthentication yes
PasswordAuthentication no
#PermitRootLogin yes
PermitRootLogin no
The sed parameter is from a string generated by the function,sed_chain(), like below:
The problem is if there's space between ${pattern} and ${option}, then I got error:
sed: -e expression #1, char 46: unterminated `s' command
If there's no space between them, the function works, but it's not what I want.
#!/bin/bash
A="PasswordAuthentication no"
B="PermitRootLogin no"
F="/tmp/1.txt"
sed_chain() {
args=("$#")
file=${#:(-1)}
pattern_params=""
for i in $(seq 0 $(($#-2)))
do
pattern=$(echo ${args[$i]}|cut -d" " -f1)
option=$(echo ${args[$i]}|cut -d" " -f2)
echo $pattern
echo $option
pattern_params="-e s/^[^#]*${pattern}.*$/#&\n${pattern} ${option}/g $pattern_params" # failed
#pattern_params='-e s/^[^#]*'${pattern}'.*$/#&'"\n${pattern}${option}"'/g '${pattern_params} # passed
echo "*** $pattern_params ***"
done
sed $pattern_params $file
}
sed_chain "$A" "$B" "$F"
Try wrapping single-quotes around the expression.
pattern_params="-e 's/^[^#]*${pattern}.*$/#&\n${pattern} ${option}/g' $pattern_params"
I have a workaround, instead of combining all of the parameter into one, I run sed command one by one for each parameter. It works fine. However I still want to know how to combine the parameters into one.
sed_chain() {
args=("$#")
file=${#:(-1)}
for i in $(seq 0 $(($#-2)))
do
pattern=$(echo ${args[$i]}|cut -d" " -f1)
option=$(echo ${args[$i]}|cut -d" " -f2)
echo $pattern
echo $option
pattern_param="s/^[^#]*${pattern}.*$/#&\n${pattern} ${option}/g"
sed -i -e "$pattern_param" $file
done
}
Does this
[[:space:]]
perhaps work?
I have a path such as thus ..
/Users/me/bla/dev/trunk/source/java/com/mecorp/sub/misc/filename.java
I'd like to be able to use bash to create the package structure in another dir somewhere e.g.
com/mecorp/sub/misc/
I tried the following but it wont work .. I was able to get a match if I change my regex to .* so that implies my bash is ok - There must be something wrong with the way im quoting the regex or maybe the regex its self. I do see working here ..
http://regexr.com?3439m
So im confused ?
regex="(?<=/java)(.*)(?=/)"
[[ $fullfile =~ $regex ]]
echo "pkg name " ${BASH_REMATCH[0]}
Thanks for your time.
EDIT - I'm using OSX so it doesn't have all those nice spiffy GNU extensions.
Try this :
using GNU grep :
$ echo '/Users/me/bla/dev/trunk/source/java/com/mecorp/sub/misc/filename.java' |
grep -oP 'java/\K.*/'
com/mecorp/sub/misc/
See http://regexr.com?3439p
Or using bash :
x="/Users/me/bla/dev/trunk/source/java/com/mecorp/sub/misc/filename.java"
[[ $x =~ java/(.*/) ]] && echo ${BASH_REMATCH[1]}
Or with awk :
echo "$x" | awk -F/ '{print gensub(".*/java/(.*/).*", "\\1", $0)}'
Or with sed :
echo "$x" | sed -e 's#.*/java/\(.*/\).*#\1#'
If you try to extract the path after /java/ you can do it with this:
path=/Users/me/bla/dev/trunk/source/java/com/mecorp/sub/misc/filename.java
package=`echo $path | sed -r 's,^.*/java/(.*/).*$,\1,'`
I want to get the first string that matches my regular expression.
For example I have the String
RCPT from unknown[211.147.3.74]: 450 4.7.1 Client host rejected: cannot find your hostname, [211.147.3.74];
and my script looks like this:
IP=`echo $LINE | grep -E -o --max-count=1 '(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)'`
echo $IP
As result I get
211.147.3.74 211.147.3.74
But I would like to get the IP only once. I tried 'grep --max-count=1' but there are still two ip's.
LINE='RCPT from unknown[211.147.3.74]: 450 4.7.1 Client host rejected: cannot find your hostname, [211.147.3.74];'
ipn='(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)'
IP=`echo $LINE | grep -E -o "$ipn\.$ipn\.$ipn\.$ipn" | head -1`
echo "$IP"
or from here
echo "$LINE" | perl -MRegexp::Common=net -ne '/($RE{net}{IPv4})/ and print "$1\n"'