Sort subchild into child into parent django - django

Question

This is mainly working (thanks to a lot of help on a previous question. Sort children into parent in django template
Now I would like to sort sub-children objects into the children objects and then sort the children into their parent. Specifically, I want to sort schools into cities into their respective state. Then, I want the schools to display into the right city in its correct state. What I am looking for would like like this:
State
--- City
-----School
-----School
-----School
--- City
-----School
-----School
-----School
--- City
-----School
-----School
-----School
Right now, I have the cities sorting into the state. However, I cannot figure out to make the schools sort into the city. I am reading up on filters in the documentation. I think the answer lies there. However, I when try to filter the schools into the city, no objects come back.
Is there a way to retrieve the 'school_list' as a child of 'city_list' while still keeping the 'city_list a child of the states ? I would love to learn how.
Edit: Added the School model. Sorting the schools by name inside a city would be ideal.
Any and all help would be appreciated.
Edit: dkarchmer's solution worked perfectly. Thanks again. Hopefully, this will be useful to someone else in the future.
models.py
class State(models.Model):
state_name = models.CharField(max_length=20, default='')
state_slug = models.SlugField()
state_image = models.ForeignKey(Image, null=True)
state_summary = models.TextField(null=True)
def __str__(self):
return self.state_slug
class City(models.Model):
city_name = models.CharField(max_length=55, default='')
city_slug = models.SlugField()
state_image = models.ForeignKey(Image, null=True)
school_image = models.ForeignKey(Image, null=True, related_name='+')
state = models.ForeignKey(State, null=True)
def __str__(self):
return self.city_slug
def def sorted_schools(self):
return self.school_set.all().order_by('school_name')
class School(models.Model):
school_name = models.CharField(max_length=55, default='')
school_slug = models.SlugField()
city = models.ForeignKey(City, null=True)
def __str__(self):
return self.school_slug
views.py
class CityInStateView(ListView):
model = City
template = 'template.html'
slug_field = 'state_slug'
context_object_name = 'city_in_state_list'
def get_context_data(self, **kwargs):
context = super(CityInStateView, self).get_context_data(**kwargs)
context['state'] = self.object
context['city_list'] = self.object.city_set.all().order_by('city_name')
return context
urls.py
urlpatterns = [
url(r'^$', SchoolIndexView.as_view(), name='school_index'),
url(r'^(?P<state_slug>[\w-]+)/$', CityInStateView.as_view(), name='state_index'),
]
template.html
{% block main_content %}
<div class="row body">
<div class="main_content">
<div class="row">
<h1>{{ state.state_name }}</h1>
{% for city in city_list %}
<h2>{{ city.city_name }}</h2>
{% for school in city.sorted_schools %}
<h3>{{ school.school_name }} </h3>
{% endfor %}
{% endfor %}
</div>
</div>
</div>
{% endblock %}
This has been kicking my butt for a week. Please explain it to me like I a m five. I appreciate all of your help in advance.

Answer 1

The easiest is to just add a method to the City model to return Schools:
class City(models.Model):
...
def sorted_schools(self):
return self.school_set.all().order_by('school_name')
And then use that directly from the template:
<div class="row body">
<div class="main_content">
<div class="row">
<h1>{{ state.state_name }}</h1>
{% for city in city_list %}
<h2>{{ city.city_name }}</h2>
{% for school in city.sorted_schools %}
<h3>{{ school.school_name }} </h3>
{% endfor
{% endfor %}
</div>
</div>
</div>
If you don't want to add that method to the Model, the second alternative is to use a templatetag to basically do the same.