Issue with saving an edited infile to an outfile in c++ - c++

Question

Im having an issue with the last section of coding on here. The // Copy files from infile to outfile. The program transfers my infile which is simply a an 8 digit number , 20392207,splits it up into individual digits using the .at method; and is supposed to save that output to an outfile. I cant figure out how to save the output to the outfile. Any advice?
infile looks as follows
20392207
program output looks like this
The input number :20392207
The number 1:2
The number 2:0
The number 3:3
The number 4:9
The number 5:2
The number 6:2
The number 7:0
The number 8:7
outfile is supposed to look like the program out put, but instead just looks like an exact copy of the infile.
#include<iostream>
#include<fstream>
#include<cstdlib>
#include<string>
#include<cmath>
using namespace std;
int main()
{
string ifilename, ofilename, line, line2;
ifstream inFile, checkOutFile;
ofstream outFile;
char response;
int i;
// Input file
cout << "Please enter the name of the file you wish to open : ";
cin >> ifilename;
inFile.open(ifilename.c_str());
if (inFile.fail())
{
cout << "The file " << ifilename << " was not successfully opened." << endl;
cout << "Please check the path and name of the file. " << endl;
exit(1);
}
else
{
cout << "The file is successfully opened." << endl;
}
// Output file
cout << "Please enter the name of the file you wish to write : ";
cin >> ofilename;
checkOutFile.open(ofilename.c_str());
if (!checkOutFile.fail())
{
cout << "A file " << ofilename << " exists.\nDo you want to continue and overwrite it? (y/n) : ";
cin >> response;
if (tolower(response) == 'n')
{
cout << "The existing file will not be overwritten. " << endl;
exit(1);
}
}
outFile.open(ofilename.c_str());
if (outFile.fail())
{
cout << "The file " << ofilename << " was not successfully opened." << endl;
cout << "Please check the path and name of the file. " << endl;
exit(1);
}
else
{
cout << "The file is successfully opened." << endl;
}
// Copy file contents from inFile to outFile
while (getline(inFile, line))
{
cout << "The input number :" << line << endl;
for (i = 0; i < 8; i++)
{
cout << "The number " << i + 1 << ":";
cout << line.at(i);
cout << endl;
}
outFile << line << endl;
}
// Close files
inFile.close();
outFile.close();
} // main

Answer 1

Here we can see that outFile is only written to outside of the while loop:
while (getline(inFile, line))
{
cout << "The input number :" << line << endl;
for (i = 0; i < 8; i++)
{
cout << "The number " << i + 1 << ":";
cout << line.at(i);
cout << endl;
}
}
outFile << line << endl;
It has no chance of containing the same output as the console
Solution: Write inside the loop the same stuff that was written to the console:
while (getline(inFile, line))
{
cout << "The input number :" << line << endl;
outFile << "The input number :" << line << endl;
blah blah blah
}
But this looks like crap and a function makes like a better solution by eliminating duplication and upping re-usability.
void output(std::ostream & out,
const std::string & line)
{
out << "The input number :" << line << endl;
for (int i = 0; i < 8; i++)
{
out << "The number " << i + 1 << ":";
out << line.at(i);
out << endl;
}
}
and called:
while (getline(inFile, line))
{
output(cout, line);
output(outFile, line);
}

Answer 2

You need to write to outFile inside the while(getline(inFile, line)) loop.
[edit] see user4581301's answer for a more thorough treatment.