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I have in Notepad++ plenty of datetime texts like:
'20160310 17:59:00'
And I want to add '-' character to separate numbers in the date like
'2016-03-10 17:59:00'
How I would be a RegEx expression to do that?
The following regex expression:
('\d{4})(\d{2})(\d{2} \d{2}:\d{2}:\d{2}')
Combined with the following replace expression:
$1-$2-$3
will achieve what you want.
Explanation:
('\d{4}) capture group 1: an apostrophe followed by 4 digits
(\d{2}) capture group 2: 2 digits
(\d{2} \d{2}:\d{2}:\d{2}') capture group 3: 2 digits, a space, 2 digits, a colon, 2 digits, a colon and 2 digits, followed by an apostrophe
$1-$2-$3 - capture group 1, followed by a -, followed by capture group 2, followed by a -, followed by capture group 3
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The below regular expression works with 012, 201, 102, etc. I am trying to change the regular expression so that it matches 002, 200, 020O from a 4 digit number. I tried varies methods, but the regular expression is matching other patterns. Can someone give me some direction on how to resolve this issue. Thank you.
Working:
RegEx012 = re.compile(r'\b(?=[1-9]*0)(?=[02-9]*1)(?=[013-9]*2)\d+\b')
Not Working:
RegEx002 = re.compile(r'\b(?=[1-9]*0)(?=[1-9]*0)(?=[013-9]*2)\d+\b')
Results:
0250(good)
0260(good)
2052(bad)
2062(bad)
If you want to match a string with 2 times a zero and at least 3 digits, you could use a positive lookahead:
\b(?=[1-9]*0[1-9]*0[1-9]*\b)\d{3,}\b
Explanation
\b Word boundary
(?= Positive lookahead, assert what is on the right contains
[1-9]*0[1-9]*0[1-9]*\b Match 2 times a zero between optional digits 1-9
) Close lookahead
\d{3,} Match 3 or more digits
\b Word boundary
Regex demo
Or the other way around, assert 3 digits and match 2 times a zero between optional digits 1-9
\b(?=\d{3})[1-9]*0[1-9]*0[1-9]*\b
To match when the third character is a 3 (Or use a character class [03] to match either a 0 or 3)
\b(?=[1-9]*0[1-9]*0[1-9]*\b)\d{2}3\d*\b
Regex demo
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I have a string with alphanumerical characters like this:
hajshajs12 +1212121 12 1AAsdsd 5665789 +987 ++789 aBcD
Can I extract only the numeric characters with length >= 4 starting with + or without + using regex ?
So in the end I should have +1212121 5665789 +987 ++789
You can use this regex
([+](?:[+]\d{2,}|\d{3,})|\d{4,})\b
Regex Breakdown
( #Capturing group
[+] #Match + sign
(?: #Non-capturing group
[+]\d{2,} #Match another + followed by at least 2 digits
| #Alterantion (OR)
\d{3,} #Match at least 3 digits
)
| #Alterantion (OR)
\d{4,} #Match at least 4 digits
)
\b #Word boundary. Number shouldn't be in between alphabets
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I need help to create a regex to validate one string, the string must be 12 characters, they can all be numbers or they can be 11 numbers and a letter, the letter can be anywhere between those numbers.
Some examples:
20710117540C
00A109822346
005109822346
K05109822346
// error cases
KY0510982234
KY05109822345
5505109822345
Thanks!
You can use this regex that will meet your requirements,
^(?:\d{12}|(?=\d*[a-zA-Z]\d*$)[\da-zA-Z]{12})$
Explanation:
^ - Start of string
(?: - Start of non-grouping pattern
\d{12} - Matches exactly 12 digits
| - alternation for another case where 11 characters can be any digits and one letter
(?=\d*[a-zA-Z]\d*$) - Look ahead to ensure the the incoming data consists of some digits and exactly one occurrence of alphabet
[\da-zA-Z]{12} - Consume 12 characters consisting of numbers and alphabet
)$ - End of non capturing group and end of input
Demo1
Another simple regex you can use is this,
^(?=\d*[a-zA-Z]?\d*$)[\da-zA-Z]{12}$
Explanation:
^ - Start of string
(?=\d*[a-zA-Z]?\d*$) - Look ahead ensuring the input contains some digits and either one alphabet or no alphabets.
[\da-zA-Z]{12} - Match and consume exactly 12 characters
$ - End of input.
Demo2
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I want to match a string where there are 5 characters where first four characters are A-Z and 5th is a digit. Also the first and the fourth character should be same.
I have a regex: [A-Z]{4}\d
However this wont check if 1st and 4th character are same. Please help
Regex: ^([A-Z])[A-Z]{2}\1\d$
1. ^ start of string.
2. ([A-Z]) capture first character.
3. [A-Z]{2} match next two character which can be in A-Z
4. \1 using captured group which contains first character of string.
5. \d a digit which can be 0-9
6. $ for end of string.
Regex demo
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Im looking for a regular expression for a textbox thats accepts either 10 digits, or 8 digits, followed by a dash, followed by 2 digits. Examples:
1212345678
or
12345678-91
If you just want to check if the input is valid without matching any content, this one should be enough:
^\d{8}-?\d\d$
Beginning with 8 digits, followed (or not) by an optional dash, and another 2 digits up to the end.
This Should Work.
((?:^[0-9]{10})|(?:^[0-9]{8}(?:\-\d{2})*))$
Input:
1212345678
12345678-91
12345678901112-10
1234567890-12
Output:
1212345678
12345678-91
See: https://regex101.com/r/AzbVXt/2
^\d{8}(\d{2})?(-\d{2})?$
^ and $ : match from the begging to the end
\d{8} : 8 digits
(\d{2})? : optional two other digits
(-\d{2})? : optional dash, with two other digits
This will match
1212345678
121234567800
Not 1212345678001
1212345678-
1212345678-00
Not 1212345678-001