'+' Operator overloading in C++ - c++

Question

I just started learning about operator overloading and was just playing around with code to learn how it works. So, I wrote a code that adds two characters. Ex: '#' + '%' = 'H' because of ASCII value addition.
Here is my code:
#include <iostream>
using namespace std;
class Strings {
//everything is public
public:
char str;
//empty constructor
Strings();
Strings(char);
//operator takes in an object of Strings
Strings operator+(Strings);
};
Strings::Strings()
{}
//constructor
Strings::Strings(char a) {
str = a;
}
//aso is "another string object"
//makes new empty object "brandNew"
//brandNew is the two characters added together
//returns object brandNew
Strings Strings::operator+(Strings aso) {
Strings brandNew;
brandNew.str = str + aso.str;
return brandNew;
}
int main() {
Strings a('#');
Strings b('%');
Strings c;
//now, we can use + operator to add characters
c = a + b;
cout << c.str << endl;
return 0;
}
What if I wanted to add two strings? If I make the input
Strings a("###");
Strings b("%%%");
And I want the output to be
HHH
How would I alter my code to add the two strings? I started with changing all of the char type declarations into string. I'm thinking I would have to make a for loop inside the operator function to iterate through each character of both inputs while adding them. But, I'm confused on the syntax for it and also confused on how to implement that. Any help and explanation would be appreciated!

Answer 1

I will give you some help declaring the class.
class Strings {
private:
char* str;
unsigned int length;
unsigned int size;
public:
//constructor
Strings();
~Strings();
Strings(const char*);
Strings(const Strings&);
//operator
Strings operator+(const Strings&);
Strings operator+(const char*);
Strings operator=(const Strings&);
Strings operator=(const char*);
Strings operator+=(const Strings&);
Strings operator+=(const char*);
///Accessors
const char* GetStr()const;
unsigned int GetLength()const;
unsigned int GetSize()const;
};