How to emulate linkClicked(QUrl) signal in QWebEngineView? - c++

Question

I am porting my project from Qt WebKit to Qt WebEngine in Qt5.6. I want to emit linkClicked(QUrl) signal when a href is clicked on the QWebView, but QWebEngineView has no signal linkClicked(QUrl).
How to emulate linkClickedSignal(QUrl)?
Porting from Qt WebKit to Qt WebEngine.

Answer 1

Thank you #Alexis P. I have got it.
class MyWebPage : public QWebEnginePage
{
Q_OBJECT
public:
MyWebPage(QObject* parent = 0) : QWebEnginePage(parent){}
bool acceptNavigationRequest(const QUrl & url, QWebEnginePage::NavigationType type, bool)
{
if (type == QWebEnginePage::NavigationTypeLinkClicked)
{
//QDesktopServices::openUrl(url);
emit linkClicked(url);
return false;
}
return true;
}
signals:
void linkClicked(const QUrl&);
};
In my window class:
webView = new QWebEngineView(ui->verticalLayoutWidget);
webView->setPage(new MyWebPage());
ui->verticalLayout->addWidget(webView);
connect(webView- >page(),SIGNAL(linkClicked(QUrl)),this,SLOT(linkClicked(QUrl)));

Answer 2

I am not sure it will be useful for you, but in my app using QWebEngineView, I have clickable links which must open the corresponding website in a browser.
The way I am doing it is like that :
class MyQWebEnginePage : public QWebEnginePage
{
Q_OBJECT
public:
MyQWebEnginePage(QObject* parent = 0) : QWebEnginePage(parent){}
bool acceptNavigationRequest(const QUrl & url, QWebEnginePage::NavigationType type, bool)
{
if (type == QWebEnginePage::NavigationTypeLinkClicked)
{
QDesktopServices::openUrl(url);
return false;
}
return true;
}
};
As you can see, I just reimplemented the virtual method acceptNavigationRequest of QWebEnginePage in order to retrieve the url from the link clicked : url. I don't know it is what you want to achieve, but I hope that helps.