Compiled C++ application gives random float values - c++

After compiling a console application and entering wrong data it gives strange output value, like 2.0434e-006, while it was requesting numerals. Here is the code:
#include <iostream>
#include <conio.h>
int main() {
using namespace std;
float l,w,h;
float s;
cout << "\nCalculating surface area of the parallelepiped\n";
cout << "Enter the raw data:\n";
cout << "Length (cm) -> ";
cin >> l;
cout << "Width (cm) -> ";
cin >> w;
cout << "Height (cm) -> ";
cin >> h;
s = (l*w + l*h + w*h)*2;
cout << "Surface area: " << s << " sq. cm\n";
cout << "\n\nPress any key...";
getch();
}
I heared something about IEEE 754 floating-point faults, but even this information doesn't make me sure in my knowledge.

Values of uninitialized non-static local variables are indeterminate.
Check if the input succeeded and handle errors.
#include <iostream>
int main() {
using namespace std;
float l,w,h;
float s;
cout << "\nCalculating surface area of the parallelepiped\n";
cout << "Enter the raw data:\n";
cout << "Length (cm) -> ";
if (!(cin >> l)) {
cout << "input error\n";
return 1;
}
cout << "Width (cm) -> ";
if (!(cin >> w)) {
cout << "input error\n";
return 1;
}
cout << "Height (cm) -> ";
if (!(cin >> h)) {
cout << "input error\n";
return 1;
}
s = (l*w + l*h + w*h)*2;
cout << "Surface area: " << s << " sq. cm\n";
cout << "\n\nPress any key...";
}

Related

how to use if else c++

How do you provide a condition in the if statement, if the variable is an integer data type then it will be displayed, and if the variable is any other data type then something else will be displayed?
#include <iostream>
#include <stdlib.h>
#include <windows.h>
#include <conio.h>
using namespace std;
int main() {
char pilih,pilih2;
int p, l, a, t, r,ulang = 4;
float luas1, luas2, luas3, keliling1, keliling2, keliling3, phi = 3.14;
while (ulang > 0) {
pilihUlang:
cout << "Pilih jenis bangun datar berikut :\n 1. Persegi panjang\n 2. Segitiga sama sisi\n 3. Lingkaran" << endl;
cout << "Masukan pilihan anda [1/2/3] : ";
cin >> pilih;
system("cls");
switch (pilih) {
case '1':
system("color 07");
cout << "Luas Dan Keliling Persegi Panjang" << endl;
cout << "Masukan Panjang = ";
cin >> p;
if (?) { // <-- here
cout << "Masukan Lebar = ";
cin >> l;
system("cls");
cout << "Luas dan keliling Persegi Panjang dengan panjang " << p << " dan lebar " << l << ", yaitu :" << endl;
luas1 = p * l;
keliling1 = 2 * (p + l);
cout << "Luas = " << luas1 << endl;
cout << "Keliling = " << keliling1 << endl;
cout << "Sisa bisa memilih ulang " << ulang - 1 << " kali." << endl;
break;
}
else {
//...
}
From the istream::operator>> man page:
If extraction fails (e.g. if a letter was entered where a digit is
expected), zero is written to value and failbit is set.
So, your function could test the cin.good() method to see if the >> operation was successful, like this:
cin >> p;
if (cin.good()) {
cout << "The integer you typed was " << p << endl;
} else {
cout << "Hey, that wasn't an integer!" << endl;
}

clearing console in cpp

system("cls") doesnt work, it finishes the program without printing anything.
the program works without it but doesnt look nice in the console without all the previous prints cleared. I've tried putting the command in different places but it doesnt matter where i put it the program finishes instantly.
#include <iostream>
#include <math.h>
#include <windows.h>
#include <stdlib.h>
using namespace std;
float c, temp, eq;
char odp = 't';
int main()
{
do
{
cout << "Choose from what value you'd like to convert." << endl;
cout << "Celsius = 1 ; Fahrenheit = 0" << endl;
cin >> c;
if (c==1)
{
cout << "Insert Celsius value: ";
cin >> temp;
eq = temp * 1.8 + 32;
cout << "It is " << eq << " degrees Fahrenheit." << endl;
cout << "If you want to continue converting please insert: t" << endl;
cin >> odp;
}
else if (c==0)
{
cout << "Insert Fahrenheit value: ";
cin >> temp;
eq = (temp * 1.8) - 32;
cout << "It is " << eq << " degrees Celsius." << endl;
cout << "If you want to continue converting please insert: t" << endl;
cin >> odp;
}
else
{
cout << "Please choose correctly" << endl;
}
}
while(odp = 't');
return 0;
}
how i put the command and it finishes the whole program instantly
#include <iostream>
#include <math.h>
#include <windows.h>
#include <stdlib.h>
using namespace std;
float c, temp, eq;
char odp = 't';
int main()
{
do
{
cout << "Choose from what value you'd like to convert." << endl;
cout << "Celsius = 1 ; Fahrenheit = 0" << endl;
cin >> c;
if (c==1)
{ system("cls") //here
cout << "Insert Celsius value: ";
cin >> temp;
eq = temp * 1.8 + 32;
cout << "It is " << eq << " degrees Fahrenheit." << endl;
cout << "If you want to continue converting please insert: t" << endl;
cin >> odp;
}
else if (c==0)
{
cout << "Insert Fahrenheit value: ";
cin >> temp;
eq = (temp * 1.8) - 32;
cout << "It is " << eq << " degrees Celsius." << endl;
cout << "If you want to continue converting please insert: t" << endl;
cin >> odp;
}
else
{
cout << "Please choose correctly" << endl;
}
}
while(odp = 't');
return 0;
}
i really dont know, thanks for the replies

How do i fix this error: undefined reference to `distance(float, float, float, float)'

So I am not really sure what to do here, I have gone back over my code multiple times and it all seems to be right but I keep getting the error code
Stubblefield9.cpp:74: undefined reference to `distance(float, float, float, float)'
collect2.exe: error: ld returned 1 exit status
Here is my code if anyone can help me.
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
int main()
{
const float pi=3.14;
int choice;
char again;
do
{
cout << " IHCC Computer Science Registration Menu\n";
cout << " ======================================\n";
cout << " 1. The Volume of a Cone\n";
cout << " 2. The Volume of a Sphere\n";
cout << " 3. The Area of an Octagon\n";
cout << " 4. The Destance between two Points\n";
cout << " ======================================\n";
cout << " Enter your selection: ";
cin >> choice;
switch (choice)
{
case 1:
float coneRadius,coneHeight,coneVolume;
cout<<"Enter the Radius of the cone:";
cin>>coneRadius;
cout<<"\nEnther the Height of the Cone: ";
cin>>coneHeight;
coneVolume=pi*coneRadius*coneRadius*coneHeight/3;
cout<<"\nThe Volume of a Cone with Radius ("<< coneRadius << ") and Height (" << coneHeight << setprecision(2) << fixed << ") is " << coneVolume;
break;
case 2:
float sphereRadius,sphereVolume;
cout << "Please insert the Radius: ";
cin >>sphereRadius;
sphereVolume = (4/3)*(pi)*(sphereRadius*sphereRadius*sphereRadius);
cout<<"Volume with radius "<< setprecision(1) << fixed << sphereRadius << setprecision(2) << fixed << " is "<<sphereVolume;
break;
case 3:
float octagonSide, octagonArea;
cout << "Input side length: ";
cin >> octagonSide;
octagonArea =(2 * (1 + sqrt(2)) * octagonSide * octagonSide);
cout << "\nThe area of the octagon with side length (" << octagonSide << setprecision(2) << fixed << ") is "<< octagonArea;
break;
case 4:
float x, y, a, b, answer;
float distance(float x, float y, float a, float b);
cout << "Enter the points for the coordinates";
cout << endl;
cout << "Point x for first coordinates: ";
cin >> x;
cout << endl;
cout << endl;
cout << "Point y for first coordinate: ";
cin >> y;
cout << endl;
cout << endl;
cout << "Point x for the second coordinate: ";
cin >> a;
cout << endl;
cout << endl;
cout << "Point y for the second coordinate: ";
cin >> b;
cout << endl;
cout << endl;
answer = distance(x, y, a, b);
cout << "The answer is " << answer;
break;
default:
cout << "Not a Valid Choice. \n";
cout << "Choose again.\n";
cin >> choice;
break ;
}
cout << "\n\n Would you like to do it again(y or n)";
cin >> again;
} while( again == 'y' || again == 'Y' );
return 0;
}
You get that error because you try to call a function distance() that is declared in your code by
float distance(float x, float y, float a, float b);
but not defined.

Can Xcode mix buffered and non-buffered input functions?

I created this simple program to practice working with classes. I'm certain there are some errors with the way I used the class, but I'm just beginning to learn about them, so I haven't learned all of the conventions and etiquette. My main question is, can Xcode have functions that are buffered and other functions that are non-buffered? I'd like my function void InputValuesAndDisplayTotals(); to be buffered and my function void ManuallyAddCoinsAndDisplayTotals(); to be non-buffered (basically, hit a key and the character is instantly processed without using the enter key). Is this possible? Thanks in advanced.
#include <iostream>
#include <iomanip>
using namespace std;
class Coin
{
private:
const float PENNYVALUE = 0.01;
const float NICKELVALUE = 0.05;
const float DIMEVALUE = 0.10;
const float QUARTERVALUE = 0.25;
int PennyInput=0;
int NickelInput=0;
int DimeInput=0;
int QuarterInput=0;
public:
void InputValuesAndDisplayTotals();
void ManuallyAddCoinsAndDisplayTotals();
void Total();
};
int main()
{
int Choice;
Coin Count;
cout << "1 to enter total coin counts, 2 to manually count coins: ";
cin >> Choice;
if (Choice==1)
{
Count.InputValuesAndDisplayTotals();
Count.Total();
}
else
{
Count.ManuallyAddCoinsAndDisplayTotals();
}
cout << endl;
}
void Coin::InputValuesAndDisplayTotals()
{
cout << fixed << setprecision(2) << endl;
cout << "Input penny count: ";
cin >> PennyInput;
cout << "Total penny value: $" << PENNYVALUE*PennyInput;
Total();
cout << endl;
cout << "Input nickel count: ";
cin >> NickelInput;
cout << "Total nickel value: $" << NICKELVALUE*NickelInput;
Total();
cout << endl;
cout << "Input dime count: ";
cin >> DimeInput;
cout << "Total dime value: $" << DIMEVALUE*DimeInput;
Total();
cout << endl;
cout << "Input quarter count: ";
cin >> QuarterInput;
cout << "Total quarter value: $" << QUARTERVALUE*QuarterInput;
Total();
}
void Coin::ManuallyAddCoinsAndDisplayTotals()
{
char Choice2;
cout << "\n'1' for penny,\n'2' for nickel,\n'3' for dime,\n'4' for quarter,\n'q' to quit\n";
do
{
cout << "\nInput: ";
cin >> Choice2;
if (Choice2=='1')
++PennyInput;
if (Choice2=='2')
++NickelInput;
if (Choice2=='3')
++DimeInput;
if (Choice2=='4')
++QuarterInput;
cout << endl;
cout << "Pennies: " << PennyInput << endl;
cout << "Nickels: " << NickelInput << endl;
cout << "Dimes: " << DimeInput << endl;
cout << "Quarters: " << QuarterInput << endl;
Total();
}
while (Choice2!='q' && Choice2!='Q');
}
void Coin::Total()
{
cout << "\nTotal amount: $";
cout << fixed << setprecision(2) << (PENNYVALUE*PennyInput)+(NICKELVALUE*NickelInput)+(DIMEVALUE*DimeInput)+(QUARTERVALUE*QuarterInput);
cout << "\n";
}

Why do my stream input operations get skipped over?

I have this code where in option lists will display when run. my problem is when I enter number 2, the option 2 program doesn't work well. It just go directly to asking the amount paid instead of asking first the cost of purchase.
#include <iostream>
#include <string>
#include <sstream>
using namespace std;
float circle (float a)
{
float z;
z = 3.141593 * (a * a);
return (z);
}
float square (float b)
{
float y;
y = b * b;
return (y);
}
float rectangle (float c, float d)
{
float x;
x = c * d;
return (x);
}
float triangle (float e, float f)
{
float w;
w = (e * f) / 2;
return (w);
}
void exit ()
{
cout << "THANK YOU! GOODBYE!" << endl;
}
int main()
{
int x;
do
{
cout << "Please choose an option below: \n";
cout << "1. Area of Shapes\n";
cout << "2. Cost of your items\n";
cout << "3. Flood Control\n";
cout << "4. Fibonacci Numbers\n";
cout << "5. Addition Table\n";
cout << "6. Exit\n";
cin >> x;
if (x == 1)
{
system("cls");
float n;
float l;
float m;
float radius;
float side;
float length;
float width;
float base;
float height;
do
{
cout << "1 => Area of Circle" << endl;
cout << "2 => Area of Square" << endl;
cout << "3 => Area of Rectangle" << endl;
cout << "4 => Area of Trian1gle" << endl;
cout << "5 => Return to Main Menu" << endl;
cout << "0 => Exit" << endl;
cout << "Please enter number of your choice: ";
cin >> n;
system("cls");
{
if (n == 0)
{
exit ();
system("pause");
return 0;
}
else if (n == 1)
{
cout << "Enter radius of the circle: ";
cin >> radius;
l = circle (radius);
cout << "Area of the circle is: " << l << endl;
system("pause");
system("cls");
}
else if (n == 2)
{
cout << "Enter side of the square: ";
cin >> side;
cout << "Area of the square is: " << square (side) << endl;
system("pause");
system("cls");
}
else if (n == 3)
{
cout << "Enter length of the rectangle: ";
cin >> length;
cout << "Enter width of the rectangle: ";
cin >> width;
m = rectangle (length, width);
cout << "Area of the rectangle is: " << m << endl;
system("pause");
system("cls");
}
else if (n == 4)
{
cout << "Enter base of the triangle: ";
cin >> base;
cout << "Enter height of the triangle: ";
cin >> height;
cout << "Area of the triangle is: " << triangle (base, height) << endl;
system("pause");
system("cls");
}
else if (n == 5)
{
exit ();
}
else
cout << "Invalid number. Please enter a valid number below" << endl;
}
}
while (n != 0 && n != 5);
cout << endl << endl;
system("pause");
system("cls");
}
else if (x == 2)
{
system("cls");
string mystr;
float cost = 0;
float amount = 0;
float total;
cout << "Total Cost: P";
getline (cin, mystr);
stringstream(mystr) >> cost;
cout << endl;
total = cost * .06;
cout << "Sales Tax Value: P" << total << endl;
cout << endl;
cout << "Cost of Item: P" << cost + total << endl;
cout << endl;
cout << "Amount Paid: P";
getline (cin, mystr);
stringstream(mystr) >> amount;
cout << endl;
cout << "Total Amount Purchased: P" << cost << endl;
cout << "Sales Tax Value: P" << total << endl;
cout << "Total Amount + Sales Tax: P" << cost + total << endl;
cout << "Total Amount Paid: P" << amount << endl;
cout << "Change: P" << amount - (cost + total) << endl;
system("pause");
cout << endl;
cout << "THANK YOU! ENJOY YOUR MEAL!" << endl;
system("pause");
system("cls");
}
else if (x > 6)
cout << "Invalid Input";
else
{
system("pause");
return 0;
}
}
while (x != 6);
system("pause");
return 0;
}
EDIT
For the posters education
You do
switch (n) {
case 1:
//... Code for n == 1 - If long put into another function. If using local variables put code bloc in braces
break;
case 2:
// Diitto for n==2
default: // No match
// All other values of n not listed above
}
What went wrong
Say you type your menu selection:
2<Enter>
Then the content of the std::cin stream will be:
2\n
When your menu selection runs...
cin >> x;
...it reads a number off the line but doesn't consume any trailing whitespace nor the newline, so the remaining state content could be denoted like this:
\n
Then your code for menu option 2 starts running:
cout << "Total Cost: P";
getline (cin, mystr);
...the getline looks at std::cin and finds the left over \n mentioned above, and says "hey, an empty line - I'll set mystr to an empty string". Notice that it did not do what you'd hoped: namely wait for you to type some more input and read that into mystr.
How to fix it
Before calling getline(cin, mystr) you want to remove the left-over \n typed when entering the menu selection. The code changes for that (adding error handling too):
#include <limits>
...
cout << "Total Cost: P";
std::cin.ignore(std::numeric_limits<streamsize>::max(), '\n');
if (!std::getline(std::cin, mystr))
{
std::cerr << "unable to read mystr\n";
exit(1);
}
std::istringstream iss(mystr);
iss >> cost;
if (!iss)
{
std::cerr << "mystr doesn't contain a valid cost number\n";
exit(1);
}
How you could have found the problem
When you get stuck like this, try adding some "trace" statements to print out the values of variables and find where they differ from your expectation... that can at least give you a better idea how to isolate and describe the problem, and what to google for to fix it.
std::out << "mystr '" << mystr << "'\n";`
Try to use error handling like I've illustrated so the program stops (or prompts for better input) when there's a problem parsing the user's input.