no viable conversion from 'int' to 'student' c++ - c++

Question

(Edited version)
I am currently coding Binary Search Tree algorithm. (using xCode IDE)
I'm taking the data from txt file and insert it as binarysearchtree.
This is the sample of data from txt file.
3800 Lee, Victor; 2.8
3000 Brown, Joanne; 4.0
As you can see in student.h, there are 2 variables which are id and student. Id contains the data "3800" and student contains "Lee, Victor; 2.8". Each line of the txt consider as one root.
Now, I have to search by a unique key which is id(Ex. "3800") and print out if it is found in the tree.
I have 5 files, BinaryNode.h, BinaryTree.h, BinarySearchTree.h, Student.h, main.cpp.
All 3 of the binary header file are using template and Student.h has no template.
So, here is my int main.
int main()
{
BinarySearchTree<Student> tree;
getData(tree); (I didn't include getData part, but consider tree has txtfile data.)
bool found = false;
char input;
do
{
cout << "Enter a key letter to access to a corresponding menu." << endl << endl;
cout << "T – Print tree as an indented list" << endl;
cout << "S – Search by a unique key (student ID)" << endl;
cout << "B – Tree Breadth-First Traversal: Print by level" << endl;
cout << "D – Depth-First Traversals: inorder, preorder, postorder" << endl;
cout << "R – Find the longest branch and print it (from leaf to root)" << endl;
cout << "H – Help" << endl;
cout << "Q – Quit" << endl << endl;
cout << "Input: ";
cin >> input;
cout << endl;
if(input == 'T' || input == 'S' || input == 'B' || input == 'D' || input == 'R' || input == 'H' || input == 'Q' || input == 'A')
{
if(input == 'T')
{
//print tree as indented
}
else if(input == 'S')
{
//search by student ID
Student *result = new Student;
int id;
cout << "Enter the student ID to search the matching student." << endl;
cin >> id;
result->setId(id);
found = tree.getEntry(*result);
}
I cin the input data into result and tried to search for the data.
//My getEntry function in public function definition
template<class ItemType>
bool BinarySearchTree<ItemType>::getEntry(ItemType& anEntry)
{
BinaryNode<ItemType>* returnedItem = findNode(BinaryTree<ItemType>::rootPtr, anEntry);
if (returnedItem)
{
anEntry = returnedItem->getItem();
return true;
}
else return false;
}
//findNode function
template<class ItemType>
BinaryNode<ItemType>*
BinarySearchTree<ItemType>::findNode(BinaryNode<ItemType>* nodePtr,
ItemType & target)
{
ItemType result = result.getId(); <------- ******error here*******
ItemType root = nodePtr->getItem().getId();
if (nodePtr == nullptr)
return nullptr;
if (result == root)
return root;
if (result > root)
root = findNode(nodePtr->getRightPtr(), target);
else
root = findNode(nodePtr->getLeftPtr(), target);
return root;
}
I have an error on my findNode function.
->No viable conversion from 'int' to 'Student'
//Student.h
class Student
{
private:
int id;
std::string name;
public:
Student() { id = 0; name = ""; }
Student(int newId, std::string newName) { id = newId; name = newName; }
friend bool operator >= (const Student l, const Student& r)
{
return std::tie(l.id, l.name) < std::tie(r.id, r.name);
}
friend bool operator == (const Student l, const Student& r)
{
return std::tie(l.id, l.name) < std::tie(r.id, r.name);
}
friend bool operator < (const Student l, const Student& r)
{
return std::tie(l.id, l.name) < std::tie(r.id, r.name);
}
friend bool operator > (const Student l, const Student& r)
{
return std::tie(l.id, l.name) < std::tie(r.id, r.name);
}
/*
Student& operator = (Student& t_id)
{
if(this != &t_id)
id = t_id.getId();
return *this;
}
*/
void getStudent() { std::cin >> id; }
int getId() const { return id; }
void setId(int t_id) { id = t_id; }
std::string getName() const { return name; }
void setName(std::string t_name) { name = t_name; }
//ItemType getGpa() const { return gpa; }
//virtual void setGpa(std::string t_gpa) { gpa = t_gpa; }
Do I need = operator to fix that problem?
Actually, I created the = operator but if I enable that = operator code,
the other codes with equal sign that are in other functions
encounter errors. (no viable overloaded '=')
How can I fix this errors?
Thank you for your helping.

Answer 1

Just see this line.
ItemType root = nodePtr->getItem().getId();
Do you feel that something is wrong here?