Can reducing loop times in C++ codes help increase the speed? - c++

I give the following example to illustrate my question:
void fun(int i, float *pt)
{
// do something based on i
std::cout<<*(pt+i)<<std::endl;
}
const unsigned int LOOP = 2000000007;
void fun_without_optmization()
{
float *example;
example = new float [LOOP];
for(unsigned int i=0; i<LOOP; i++)
{
fun(i,example);
}
delete []example;
}
void fun_with_optimization()
{
float *example;
example = new float [LOOP];
unsigned int unit_loop = LOOP/10;
unsigned int left_loop = LOOP%10;
pt = example;
for(unsigend int i=0; i<unit_loop; i++)
{
fun(0,pt);
fun(1,pt);
fun(2,pt);
fun(3,pt);
fun(4,pt);
fun(5,pt);
fun(6,pt);
fun(7,pt);
fun(8,pt);
fun(9,pt);
pt=pt+10;
}
delete []example;
}
As far as I understand, function fun_without_optimization() and function fun_with_optimization() should perform the same. The only argument why the second function is better than the first is that the pointer calculation in fun becomes simple. Any other arguments why the second function is better?

Unrolling a loop in which I/O is performed is like moving the landing strip for a B747 from London an inch eastward in JFK.

Re: "Any other arguments why the second function is better?" - would you accept the answer explaining why it is NOT better?
Manually unrolling a loop is error-prone, as is clearly illustrated by your code: you forgot to process the tail left_loop.
For at least a couple of decades compiler does this optimization for you.
How do you know the optimal number of iteration to put in that unrolled loop? Do you target a specific cache size and calculate the length of assembly instructions in bytes? The compiler might.
Your messing with the otherwise clean loop can prevent other optimizations, like the use of SIMD.
The bottom line is: if you know something that your compiler doesn't (specific pattern of the run-time data, details of the targeted execution environment, etc.), and you know what you are doing - you can try manual loop unrolling. But even then - profile.

The technique you describe is called loop unrolling; potentially this increases performance, as the time for evaluation of the control structures (update of te loop variable and checking the termination condition) becomes smaller. However, decent compilers can do this for you and maintainability of the code decreases if done manually.

This is an optimization technique used for parallel architectures (architectures that support VLIW instructions). Depending on the number DALU (most common 4) and ALU(most common 2) units the architecture supports, and the level of "parallelization" the code supports, multiple instructions can be executes in one cycle.
So this code:
for (int i=0; i<n;i++) //n multiple of 4, for simplicity
a+=temp; //just a random instruction
Will actually execute faster on a parallel architecture if rewritten like:
for (int i=0;i<n ;i+=4)
{
temp0 = temp0 +temp1; //reads and additions can be executed in parallel
temp1 = temp2 +temp3;
a=temp0+temp1+a;
}
There is a limit to how much you can parallelize your code, a limit imposed by the physical ALUs/DALUs the CPU has. That's why it's important to know your architecture before you attempt to (properly) optimize your code.
It does not stop here: the code you want to optimize has to be a continuous block of code, meaning no jumps ( no function calls, no chance of flow instructions), for maximum efficiency.
Writing your code, like:
for(unsigend int i=0; i<unit_loop; i++)
{
fun(0,pt);
fun(1,pt);
fun(2,pt);
fun(3,pt);
fun(4,pt);
fun(5,pt);
fun(6,pt);
fun(7,pt);
fun(8,pt);
fun(9,pt);
pt=pt+10;
}
Wold not do much, unless the compiler inlines the function calls; and it looks like to many instructions anyway...
On a different note: while it's true that you ALWAYS have to work with the compiler when optimizing your code, you should NEVER rely only on it when you what to get the maximum optimization out of your code. Remember, the compiler handles 'the general case' while you are likely interested in a particular situation - that's why some compiles have special directives to help with the optimization process.

Related

Can I replace an if-statement with AND?

My prof once said, that if-statements are rather slow and should be avoided as much as possible. I'm making a game in OpenGL, where I need a lot of them.
In my tests replacing an if-statement with AND via short-circuiting worked, but is it faster?
bool doSomething();
int main()
{
int randomNumber = std::rand() % 10;
randomNumber == 5 && doSomething();
return 0;
}
bool doSomething()
{
std::cout << "function executed" << std::endl;
return true;
}
My intention is to use this inside the draw function of my renderer. My models are supposed to have flags, if a flag is true, a certain function should execute.
if-statements are rather slow and should be avoided as much as possible.
This is wrong and/or misleading. Most simplified statements about slowness of a program are wrong. There's probably something wrong with this answer too.
C++ statements don't have a speed that can be attributed to them. It's the speed of the compiled program that matters. And that consists of assembly language instructions; not of C++ statements.
What would probably be more correct is to say that branch instructions can be relatively slow (on modern, superscalar CPU architectures) (when the branch cannot be predicted well) (depending on what you are comparing to; there are many things that are much more expensive).
randomNumber == 5 && doSomething();
An if-statement is often compiled into a program that uses a branch instruction. A short-circuiting logical-and operation is also often compiled into a program that uses a branch instruction. Replacing if-statement with a logical-and operator is not a magic bullet that makes the program faster.
If you were to compare the program produced by the logical-and and the corresponding program where it is replaced with if (randomNumber == 5), you would find that the optimiser sees through your trick and produces the same assembly in both cases.
My models are supposed to have flags, if a flag is true, a certain function should execute.
In order to avoid the branch, you must change the premise. Instead of iterating through a sequence of all models, checking flag, and conditionally calling a function, you could create a sequence of all models for which the function should be called, iterate that, and call the function unconditionally -> no branching. Is this alternative faster? There is certainly some overhead of maintaining the data structure and the branch predictor may have made this unnecessary. Only way to know for sure is to measure the program.
I agree with the comments above that in almost all practical cases, it's OK to use ifs as much as you need without hesitation.
I also agree that it is not an issue important for a beginner to waste energy on optimizing, and that using logical operators will likely to emit code similar to ifs.
However - there is a valid issue here related to branching in general, so those who are interested are welcome to read on.
Modern CPUs use what we call Instruction pipelining.
Without getting too deap into the technical details:
Within each CPU core there is a level of parallelism.
Each assembly instruction is composed of several stages, and while the current instruction is executed, the next instructions are prepared to a certain degree.
This is called instruction pipelining.
This concept is broken with any kind of branching in general, and conditionals (ifs) in particular.
It's true that there is a mechanism of branch prediction, but it works only to some extent.
So although in most cases ifs are totally OK, there are cases it should be taken into account.
As always when it comes to optimizations, one should carefully profile.
Take the following piece of code as an example (similar things are common in image processing and other implementations):
unsigned char * pData = ...; // get data from somewhere
int dataSize = 100000000; // something big
bool cond = ...; // initialize some condition for relevant for all data
for (int i = 0; i < dataSize; ++i, ++pData)
{
if (cond)
{
*pData = 2; // imagine some small calculation
}
else
{
*pData = 3; // imagine some other small calculation
}
}
It might be better to do it like this (even though it contains duplication which is evil from software engineering point of view):
if (cond)
{
for (int i = 0; i < dataSize; ++i, ++pData)
{
*pData = 2; // imagine some small calculation
}
}
else
{
for (int i = 0; i < dataSize; ++i, ++pData)
{
*pData = 3; // imagine some other small calculation
}
}
We still have an if but it's causing to branch potentially only once.
In certain [rare] cases (requires profiling as mentioned above) it will be more efficient to do even something like this:
for (int i = 0; i < dataSize; ++i, ++pData)
{
*pData = (2 * cond + 3 * (!cond));
}
I know it's not common , but I encountered specific HW some years ago on which the cost of 2 multiplications and 1 addition with negation was less than the cost of branching (due to reset of instruction pipeline). Also this "trick" supports using different condition values for different parts of the data.
Bottom line: ifs are usually OK, but it's good to be aware that sometimes there is a cost.

Timing of using variables passed by reference and by value in C++

I have decided to compare the times of passing by value and by reference in C++ (g++ 5.4.0) with the following code:
#include <iostream>
#include <sys/time.h>
using namespace std;
int fooVal(int a) {
for (size_t i = 0; i < 1000; ++i) {
++a;
--a;
}
return a;
}
int fooRef(int & a) {
for (size_t i = 0; i < 1000; ++i) {
++a;
--a;
}
return a;
}
int main() {
int a = 0;
struct timeval stop, start;
gettimeofday(&start, NULL);
for (size_t i = 0; i < 10000; ++i) {
fooVal(a);
}
gettimeofday(&stop, NULL);
printf("The loop has taken %lu microseconds\n", stop.tv_usec - start.tv_usec);
gettimeofday(&start, NULL);
for (size_t i = 0; i < 10000; ++i) {
fooRef(a);
}
gettimeofday(&stop, NULL);
printf("The loop has taken %lu microseconds\n", stop.tv_usec - start.tv_usec);
return 0;
}
It was expected that the fooRef execution would take much more time in comparison with fooVal case because of "looking up" referenced value in memory while performing operations inside fooRef. But the result proved to be unexpected for me:
The loop has taken 18446744073708648210 microseconds
The loop has taken 99967 microseconds
And the next time I run the code it can produce something like
The loop has taken 97275 microseconds
The loop has taken 99873 microseconds
Most of the time produced values are close to each other (with fooRef being just a little bit slower), but sometimes outbursts like in the output from the first run can happen (both for fooRef and fooVal loops).
Could you please explain this strange result?
UPD: Optimizations were turned off, O0 level.
If gettimeofday() function relies on operating system clock, this clock is not really designed for dealing with microseconds in an accurate manner. The clock is typically updated periodically and only frequently enough to give the appearance of showing seconds accurately for the purpose of working with date/time values. Sampling at the microsecond level may be unreliable for a benchmark such as the one you are performing.
You should be able to work around this limitation by making your test time much longer; for example, several seconds.
Again, as mentioned in other answers and comments, the effects of which type of memory is accessed (register, cache, main, etc.) and whether or not various optimizations are applied, could substantially impact results.
As with working around the time sampling limitation, you might be able to somewhat work around the memory type and optimization issues by making your test data set much larger such that memory optimizations aimed at smaller blocks of memory are effectively bypassed.
Firstly, you should look at the assembly language to see if there are any differences between passing by reference and passing by value.
Secondly, make the functions equivalent by passing by constant reference. Passing by value says that the original variable won't be changed. Passing by constant reference keeps the same principle.
My belief is that the two techniques should be equivalent in both assembly language and performance.
I'm no expert in this area, but I would tend to think that the reason why the two times are somewhat equivalent is due to cache memory.
When you need to access a memory location (Say, address 0xaabbc125 on an IA-32 architecure), the CPU copies the memory block (addresses 0xaabbc000 to 0xaabbcfff) to your cache memory. Reading from and writing to the memory is very slow, but once it's been copied into you cache, you can access values very quickly. This is useful because programs usually require the same range of addresses over and over.
Since you execute the same code over and over and that your code doesn't require a lot of memory, the first time the function is executed, the memory block(s) is (are) copied to your cache once, which probably takes most of the 97000 time units. Any subsequent calls to your fooVal and fooRef functions will require addresses that are already in your cache, so they will require only a few nanoseconds (I'd figure roughly between 10ns and 1µs). Thus, dereferencing the pointer (since a reference is implemented as a pointer) is about double the time compared to just accessing a value, but it's double of not much anyway.
Someone who is more of an expert may have a better or more complete explanation than mine, but I think this could help you understand what's going on here.
A little idea : try to run the fooVal and fooRef functions a few times (say, 10 times) before setting start and beginning the loop. That way, (if my explanation was correct!) the memory block will (should) be already into cache when you begin looping them, which means you won't be taking caching in your times.
About the super-high value you got, I can't explain that. But the value is obviously wrong.
It's not a bug, it's a feature! =)

An example of an optimization that involves compiler reordering

C & C++ compilers are allowed to reorder operations as long as the as-if rule holds. What is an example of such a reordering performed by a compiler, and what is the potential performance gain to be had by doing it?
Examples involving any (C/C++) compiler on any platform are welcome.
Suppose you have the following operations being performed:
int i=0,j=0;
i++;
i++;
i++;
j++;
j++;
j++;
Ignoring for the moment that the three increments would likely be optimized away by the compiler into one +=3, you will end up having a higher processor-pipeline throughput if you reordered the operations as
i++;
j++;
i++;
j++;
i++;
j++;
since j++ doesn't have to wait for the result of i++ while in the previous case, most of the instructions had a data dependency on the previous instruction. In more complicated computations, where there isn't an easy way to reducing the number of instructions to be performed, the compiler can still look at data dependencies and reorder instructions so that an instruction depending on the result of an earlier instruction is as far away from it as possible.
Another example of such an optimization is when you are dealing with pure functions. Looking at a simple example again, assume you have a pure function f(int x) which you are summing over a loop.
int tot = 0;
int x;//something known only at runtime
for(int i = 0; i < 100; i++)
tot += f(x);
Since f is a pure function, the compiler can reorder calls to it as it pleases. In particular, it can transform this loop to
int tot = 0;
int x;//something known only at runtime
int fval = f(x);
for(int i = 0; i < 100; i++)
tot += fval;
I'm sure there are quite a few examples where reordering operations will yield faster performance. An obvious example would be to reorder loads as early as possible, since these are typically much slower than other CPU operations. By doing other, unrelated work whilst the memory is being fetched, the CPU can save time overall.
That is, given something like this:
expensive_calculation();
x = load();
do_something(x);
We can reorder it like this:
x = load();
expensive_calculation();
do_something(x);
So while we're waiting for the load to complete, we can essentially do expensive_calculation() for free.
Suppose you have a loop like:
for (i=0; i<n; i++) dest[i] = src[i];
Think memcpy. You might want the compiler to be able to vectorize this, i.e. load 8 or 16 bytes at a time and then store 8 or 16 at a time. Making that transformation is a reordering, since it would cause src[1] to be read before dest[0] is stored. Moreover, unless the compiler knows that src and dest don't overlap, it's an invalid transformation, i.e. one the compiler is not allowed to make. Use of the restrict keyword (C99 and later) allows you to tell the compiler that they don't overlap so that this kind of (extremely valuable) optimization is possible.
The same sort of thing arises all the time in operations on arrays that aren't just copying - things like vector/matrix operations, transformations of sound/image sample data, etc.

Cache Optimization Theory

I am thinking about heavy memory cache optimization and like to have some feedback.
Consider this example:
class example
{
float phase1;
float phaseInc;
float factor;
public:
void process(float* buffer,unsigned int iSamples)//<-high prio audio thread
{
for(unsigned int i = 0; i < iSamples; i++)// mostly iSamples is 32
{
phase1 += phaseInc;
float f1 = sinf(phase1);//<-sinf is just an example!
buffer[i] = f1*factor;
}
}
};
optimization idea:
void example::process(float* buffer,unsigned int iSamples)
{
float stackMemory[3];// should fit in L1
memcpy(stackMemory,&phase1,sizeof(float)*3);// get all memory at once
for(unsigned int i = 0; i < iSamples; i++)
{
stackMemory[0] += stackMemory[1];
float f1 = sinf(stackMemory[0]);
buffer[i] = f1*stackMemory[2];
}
memcpy(&phase1,stackMemory,sizeof(float)*1);// write back only changed mameory
}
Note that the real sample loop will contain thousands of operations.
So the stackMemory can become quite big.
I think it will be not more then 32kb (are there any smaller L1's out there ?).
Does the order of the used variables in this stackmemory matter ?
I hope not, because i'd like to order them so that i can reduce the writeback size.
Or does the L1 cache have the same cachline behaviour that RAM has ?
I have the feeling that i am somehow doing what prefetch is made for, but all i read about prefetch is relative vague about how to use it efficently. Try and error is not an option with 5000+ lines of code.
Code will run on Win,Mac and iOS.
Any ARM<->Intel issues to expect ?
Is it possible that this kind optimization is useless since all memory is accessed and transferred to L1 on the first iteration of the loop anyway ?
Thanks for any hints and ideas.
At first I thought there was a good chance that the second one could be slower as a result of additional memory access and instructions required for memcpy, while the first could simply work directly with these three class members already loaded into registers.
Nevertheless, I tried fiddling with the code in GCC 5.2 with both -O2 and -O3 and found that, no matter what I tried, I got identical assembly instructions for both. This is pretty amazing considering all the extra conceptual work that memcpy typically has to do that apparently got squashed away to zilch.
The one case I can think of where your second version might be faster in some scenario, on some compiler, is if the aliasing involved to access this->data_member interfered with an optimization and caused redundant loads and stores to/from registers.
It would have nothing to do with the L1 cache in that case and everything to do with register allocation on the compiler side. Caches are largely irrelevant here when you're loading the same memory (member variables) regardless for a contiguous chunk of data, it has entirely to do with registers. Nevertheless, I couldn't find a single scenario where I could cause that to happen where the compiler did a worse job with one over the other -- every case I tested yielded identical results. In a sufficiently complex real world case, perhaps there might be a difference.
Then again, in such a case, it should be on the safer side to simply do:
void process(float* buffer,unsigned int iSamples)
{
const float pi = phaseInc;
const float p1 = phase1;
const float fact = factor;
for(unsigned int i = 0; i < iSamples; i++)
{
phase1 += pi;
float f1 = sinf(p1);
buffer[i] = f1*fact;
}
}
There's no need to jump through hoops with memcpy to store the results into an array and back. That puts additional strain on the optimizer even if, in my findings, the optimizer managed to eliminate the overhead typically associated.
I realize your example is simplified, but there should not be a need to reduce the structure down to such a primitive array no matter how many data members you're dealing with (unless such an array actually is the most convenient representation). From a performance standpoint, a compiler will have an "easier" time (even if optimizers today are pretty amazing and can handle this) optimizing if you just use local variables instead of an array to which you memcpy aggregate data members in and out.

Strange C++ performance difference?

I just stumbled upon a change that seems to have counterintuitive performance ramifications. Can anyone provide a possible explanation for this behavior?
Original code:
for (int i = 0; i < ct; ++i) {
// do some stuff...
int iFreq = getFreq(i);
double dFreq = iFreq;
if (iFreq != 0) {
// do some stuff with iFreq...
// do some calculations with dFreq...
}
}
While cleaning up this code during a "performance pass," I decided to move the definition of dFreq inside the if block, as it was only used inside the if. There are several calculations involving dFreq so I didn't eliminate it entirely as it does save the cost of multiple run-time conversions from int to double. I expected no performance difference, or if any at all, a negligible improvement. However, the perfomance decreased by nearly 10%. I have measured this many times, and this is indeed the only change I've made. The code snippet shown above executes inside a couple other loops. I get very consistent timings across runs and can definitely confirm that the change I'm describing decreases performance by ~10%. I would expect performance to increase because the int to double conversion would only occur when iFreq != 0.
Chnaged code:
for (int i = 0; i < ct; ++i) {
// do some stuff...
int iFreq = getFreq(i);
if (iFreq != 0) {
// do some stuff with iFreq...
double dFreq = iFreq;
// do some stuff with dFreq...
}
}
Can anyone explain this? I am using VC++ 9.0 with /O2. I just want to understand what I'm not accounting for here.
You should put the conversion to dFreq immediately inside the if() before doing the calculations with iFreq. The conversion may execute in parallel with the integer calculations if the instruction is farther up in the code. A good compiler might be able to push it farther up, and a not-so-good one may just leave it where it falls. Since you moved it to after the integer calculations it may not get to run in parallel with integer code, leading to a slowdown. If it does run parallel, then there may be little to no improvement at all depending on the CPU (issuing an FP instruction whose result is never used will have little effect in the original version).
If you really want to improve performance, a number of people have done benchmarks and rank the following compilers in this order:
1) ICC - Intel compiler
2) GCC - A good second place
3) MSVC - generated code can be quite poor compared to the others.
You may also want to try -O3 if they have it.
Maybe the result of getFreq is kept inside a register in the first case and written to memory in the second case? It might also be, that the performance decrease has to do with CPU mechanisms as pipelining and/or branch prediction.
You could check the generated assembly code.
This looks to me like a pipeline stall
int iFreq = getFreq(i);
double dFreq = iFreq;
if (iFreq != 0) {
Allows the conversion to double to happen in parallel with other code
since dFreq is not being used immediately. it gives the compiler something
to do between storing iFreq and using it, so this conversion is most likely
"free".
But
int iFreq = getFreq(i);
if (iFreq != 0) {
// do some stuff with iFreq...
double dFreq = iFreq;
// do some stuff with dFreq...
}
Could be hitting a store/reference stall after the conversion to double since you begin using the double value right away.
Modern processors can do multiple things per clock cycle, but only when the things are independent. Two consecutive instructions that reference the same register often result in a stall. The actual conversion to double may take 3 clocks, but all but the first clock can be done in parallel with other work, provided you don't refer to the result of the conversion for an instruction or two.
C++ compilers are getting pretty good at re-ordering instructions to take advantage of this, it looks like your change defeated some nice optimization.
One other (less likely) possibility is that when the conversion to float was before the branch, the compiler was able remove the branch entirely. Branchless code is often a major performance win in modern processors.
It would be interesting to see what instructions the compiler actually emitted for these two cases.
Try moving the definition of dFreq outside of the for loop but keep the assignment inside the for loop/if block.
Perhaps the creation of dFreq on the stack every for loop, inside the if, is causing issue (although the compiler should take care of that). Perhaps a regression in the compiler, if the dFreq var is in the four loop its created once, inside the if inside the for its created every time.
double dFreq;
int iFreq;
for (int i = 0; i < ct; ++i)
{
// do some stuff...
iFreq = getFreq(i);
if (iFreq != 0)
{
// do some stuff with iFreq...
dFreq = iFreq;
// do some stuff with dFreq...
}
}
maybe the compiler is optimizing it taking the definition outside the for loop. when you put it in the if the compiler optimizations aren't doing that.
There's a likelihood that this changed caused your compiler to disable some optimizations. What happens if you move the declarations above the loop?
Once I've read a document about optimization that said that as defining variables just before their usage and not even before was a good practice, the compilers could optimize code following that advice.
This article (a bit old but quite valid) say (with statistics) something similar : http://www.tantalon.com/pete/cppopt/asyougo.htm#PostponeVariableDeclaration
It's easy enough to find out. Just take 20 stackshots of the slow version, and of the fast version. In the slow version you will see on roughly 2 of the shots what it is doing that it is not doing in the fast version. You will see a subtle difference in where it halts in the assembly language.