I wrote a program to accept 15 integer values in an array, then pass this array to a function which will multiply each even index value by 4.
Currently the program displays the initial array, but seems like it's getting hung up before it displays the modified array.
Please help me understand why the program is getting stuck here!
int main(){
const int SIZE = 15;
int quad[SIZE] = {};
void quadruple(int[], const int);
cout << "Enter 15 integer values into an array." << endl;
for (int i = 0; i < SIZE; i++) // Accept 15 int values
{
cout << i << ": ";
cin >> quad[i];
}
cout << "Before quadruple function is called: " << endl;
for (int i = 0; i < SIZE; i++)
{
cout << quad[i] << " ";
}
cout << endl;
quadruple(quad, SIZE);
cout << "After even index value multiplication: " << endl;
for (int i = 0; i < SIZE; i++)
{
cout << quad[i] << " ";
}
cout << endl;
return 0;
}
void quadruple(int values[], const int SZ){
for (int i = 0; i < SZ; i + 2) // Multiply even values by 4
{
if ((i % 2) == 0)
{
values[i] = values[i] * 4;
}
else // Keep odd values the same
{
values[i] = values[i] * 1;
}
}
}
for (int i = 0; i < SZ; i + 2)
"i + 2" doesn't do anything.
You probably meant "i += 2;".
Your homework assignment is to find some documentation about your system's debugger. And find where your rubber duck is, as it's been suggested in the comments.
Related
My program analyzes the array in the loop "for". If all elements satisfy the condition, it should print a message one time, but my program does it after each iteration.
Here's my code:
#include <iostream>
using namespace std;
int main()
{
const int size = 32;
int ARR[size];
cout << "The size of the set is " << size << " elements." << endl << endl;
cout << "Enter the elements of the set: ";
for (int i = 0; i < size; i++)
{
cin >> ARR[i];
}
for (int i = 0; i < size; i++)
{
if (ARR[i] > ARR[i])
cout << "\nThe relation is reflexive." << endl;
else
cout << "\nThe relation is not reflexive." << endl;
}
return 0;
}
I need that message to be printed after all the iterations are done. How can I achieve that result?
It's pretty easy, just use a boolean flag to determine if the condition is met:
bool isReflexive = true;
for (int i = 0; i < size; i++) {
if (ARR[i] <= ARR[i]) {
isReflexive = false;
break;
}
}
if(isReflexive)
cout << "\nThe relation is reflexive." << endl;
else
cout << "\nThe relation is not reflexive." << endl;
Note: The code above will always set isReflexive to false. You also need to compare two different indices:
for (int i = 1; i < size; i++) {
if (ARR[i-1] <= ARR[i]) { // Or whatever the correct comparison is
isReflexive = false;
break;
}
}
I would suggest to separate analysis of "reflexiveness" from printing the result. That would allow you to simply end the loop as soon as negative result is determined:
#include <iostream>
using namespace std;
bool IsReflexive(int a[], int size)
{
for (int i = 0; i < size; i++)
{
if (a[i] > a[i]) // TODO: correct this!!!
return false;
}
return true;
}
int main()
{
const int size = 32;
int ARR[size];
cout << "The size of the set is " << size << " elements." << endl << endl;
cout << "Enter the elements of the set: ";
for (int i = 0; i < size; i++)
{
cin >> ARR[i];
}
if (IsReflexive(ARR, size))
cout << "\nThe relation is reflexive." << endl;
else
cout << "\nThe relation is not reflexive." << endl;
return 0;
}
I need to write a C++ program where it swaps between two 1-dimensional
arrays using pointers and functions. Firstly, a void function named showValues to display both arrays before swapping takes and also a void function named swap to swap the elements between both arrays.
My question is: I'm supposed to swap the function but for some reason it wont run and I am not sure where is the error in my code
#include <iostream>
#include <iomanip>
using namespace std;
const int SIZE = 5;
void showValues(int[],int[]);
void swap(int[],int[]);
int main() {
int array1[SIZE] = {10,20,30,40,50};
int array2[SIZE] = {60,70,80,90,100};
showValues (array1, array2);
swap(array1, array2);
return 0;
}
void showValues(int array1[], int array2[]){
cout<<"The original arrays are as shown below: " << endl;
cout << " Array 1 is: ";
for (int i = 0; i < 5; ++i) {
cout << array1[i] << " ";
}
cout << "\n Array 2 is: ";
for (int i = 0; i < 5; ++i) {
cout << array2[i] << " ";
}
}
void swap(int array1[], int array2[])
{
int temp,i;
for(i=0; i<5; ++i)
{
temp = array1[SIZE];
array1[SIZE] = array2[SIZE];
array2[SIZE] = temp;
}
cout << "\nThe swapped arrays are as shown below: " << endl;
cout << " Array 1 is: ";
for (int i = 0; i < 5; ++i) {
cout << array1[i] << " ";
}
cout << "\n Array 2 is: ";
for (int i = 0; i < 5; ++i) {
cout << array2[i] << " ";
}
}
This part of your code doesn't make sense:
temp = array1[SIZE];
array1[SIZE] = array2[SIZE];
array2[SIZE] = temp;
SIZE is 5. So, you are accessing array1[5] and array2[5], i.e. the 6th element of the array. Yet, your arrays have only 5 elements to begin with (array1[0] to array1[4], same for array2), so you are accessing elements beyond the end of the array, which is undefined behavior that is probably just corrupting memory somewhere!
You probably meant to use i here, not SIZE, then the code makes sense. Instead, it would be useful to replace the "magic number" 5 with SIZE:
for(i = 0; i < SIZE; ++i)
{
temp = array1[i];
array1[i] = array2[i];
array2[i] = temp;
}
The void swap(int array1[], int array2[]) function is where you are having trouble. You actually don't even need to have another function for the swapping. You could just use std::swap() which is defined in the #include <utility> header. Since both arrays have the same size.
For example you could do something along these lines:
#include <iostream>
#include <iomanip>
#include <utility>
const int SIZE = 5;
void showValues(int[], int[]);
void swap(int[], int[]);
int main() {
int array1[SIZE] = { 10,20,30,40,50 };
int array2[SIZE] = { 60,70,80,90,100 };
int n = sizeof(array1) / sizeof(array2[0]);
showValues(array1, array2);
std::swap(array1, array2);
std::cout << "\n\nThe swapped arrays are as shown below:\n ";
std::cout << "\nArray 1 is: ";
for (int i = 0; i < n; i++)
std::cout << array1[i] << ", ";
std::cout << "\nArray 2 is: ";
for (int i = 0; i < n; i++)
std::cout << array2[i] << ", ";
return 0;
}
void showValues(int array1[], int array2[]) {
std::cout << "The original arrays are as shown below: " << std::endl;
std::cout << "\nArray 1 is: ";
for (int i = 0; i < 5; ++i) {
std::cout << array1[i] << " ";
}
std::cout << "\nArray 2 is: ";
for (int i = 0; i < 5; ++i) {
std::cout << array2[i] << " ";
}
}
Also consider not using using namespace std;.
Why do I get a program crash for large values but not small values for my program? If I input 1-3 the program does what it is supposed to but when I enter a number greater than that the program crashes and/or does not complete? Is it something to do with a pointer error or the way I've referenced something? I'm unsure so any help is appreciated. Thanks!
Code:
#include <iostream>
using namespace std;
void getData (int size, int *Arr){
cout << "\n\nEnter integer data one line at a time\n" << endl ;
for (int i=0; i < size; i++){
cin >> Arr[i];
}
}
void findMinAndMax(int array[], int size, int *min, int *max) {
int smallest = array[0];
int largest = array[0];
*min = smallest;
*max = largest;
for (int i = 1; i < size; i++)
{
if (array[i] > *max){
*max = array[i];
cout << "Max Value (loop): " << *max << endl;
}
if (array[i] < *min){
*min = array[i];
cout << "Min Value (loop): " << *max << endl;
}
}
// testing code
cout << "Min Value: " << *min << endl;
cout << "Max Value: " << *max << endl;
}
int *makeFrequency (int data[], int dSize, int *minDataValue, int *maxDataValue) {
cout << "Min Value Pre: " << *minDataValue << endl;// testing code
cout << "Max Value Pre: " << *maxDataValue << endl;// testing code
findMinAndMax(data, dSize, minDataValue, maxDataValue);
cout << "Min Value Post: " << *minDataValue << endl; // testing code
cout << "Max Value Post: " << *maxDataValue << endl;// testing code
int fSize = *minDataValue + *maxDataValue;
cout << "fSize: " << fSize << endl; // testing code
int *frequency;
frequency = new int [fSize];
// if frequency is 0, end
if (frequency == 0)
{
return 0;
}
// set all elements to 0 in array frequency
for (int i = 0; i <= fSize; i++) {
frequency[i] = 0;
}
for (int i = 0; i <= dSize; i++) {
int j = data[i] - (*minDataValue) + 1;
frequency[j] = frequency[j] + 1;
}
return frequency;
}
void makeHistogram (int *freq, int min, int max ){
cout << "Frequency Value HISTOGRAM: " << *freq << endl;
cout << "\n\n\n ----------- Histogram ----------------\n" << endl;
int size = min + max;
cout << "Size Value HISTOGRAM: " << size << endl;
for (int i = 0; i < size; i++){
if (freq[i] > 0) {
cout << "\n" << min + i - 1 << ": ";
for (int j = 0; j < freq[i]; j++) {
cout << '*';
}
}
}
cout << endl << endl;
}
int main() {
int dSize;
int *ArrayOfInts;
cout << "How many data values? ";
cin >> dSize;
ArrayOfInts = new int [dSize];
getData(dSize, ArrayOfInts);
int *frequency, min, max;
frequency = makeFrequency(ArrayOfInts, dSize, &min, &max);
if (frequency == 0) return -1;
cout << "Min Value MAIN: " << min << endl; // testing code
cout << "Max Value MAIN: " << max << endl; // testing code
cout << "Frequency Value MAIN: " << *frequency << endl;
makeHistogram(frequency, min, max);
delete [] frequency;
return 0;
}
One place where you have undefined behaviour which can cause crashes:
here you allocate fSize elements:
frequency = new int [fSize];
later you iterate it until fSize:
for (int i = 0; i <= fSize; i++) {
you should change to i < fSize, because there is no fSize element in your array. And the same problem with i <= dSize later on. Should be i < dSize.
btw. I dont see why only large values should cause crashes in your code, maybe this is just UB.
You're setting fSize incorrectly. It should be the difference between the maximum and minimum values, not the sum of them. Otherwise, if you have negative numbers in your list, the frequency array will be too small. And if absolute value of any of the negative numbers is larger than the highest number, fSize will be negative, which is not valid for the size of an array.
Then you need to add 1 to include both endpoints. So it should be:
int fSize = *maxDataValue - *minDataValue + 1;
Then, as the other answer pointed out, you need to fix your for loops. When the size of an array is N, the array indexes from from 0 to N-1. So it should be:
for (int i = 0; i < fSize; i++) {
using < as the loop test, not <=. If you try to write outside an array, you invoke undefined behavior, so anything can happen -- if you're lucky you get a crash, but that's not guaranteed.
You have a similar problem when you assign to frequency:
for (int i = 0; i <= dSize; i++) {
int j = data[i] - (*minDataValue) + 1;
frequency[j] = frequency[j] + 1;
}
There's no need to add 1 when subtracting *minDataValue, and doing so will cause you to go outside the array when data[i] is the maximum.
I'm trying to do some of my C++ homework, but I seem to have run into an issue. I need to make it so that the user inputs 8 numbers, and those said 8 get stored in an array. Then, if one of the numbers is greater than 21, to output said number. The code is below, and it's kind of sloppy. Yes, first year C++ learner here :p
#include <iostream>
using namespace std;
int main() {
const int NUM_ELEMENTS = 8; // Number of elements
int userVals[NUM_ELEMENTS]; // User numbers
int i = 0; // Loop index
int sumVal = 0; // For computing sum
int prntSel = 0; // For printing greater than 21
// Prompt user to populate array
cout << "Enter " << NUM_ELEMENTS << " integer values..." << endl;
for (i = 0; i < NUM_ELEMENTS; ++i) {
cin >> userVals[i];
}
for (int i = NUM_ELEMENTS - 1; i > 21; i--)
cout << "Value: " << sumVal << endl;
// Determine sum
sumVal = 0;
for (i = 0; i < NUM_ELEMENTS; ++i) {
sumVal = sumVal + userVals[i];
}
cout << "Sum: " << sumVal << endl;
return 0;
}
Don't reinvent the wheel, use standard algorithms:
std::copy_if(std::begin(userVals), std::end(userVals),
std::ostream_iterator<int>(std::cout, "\n"),
[] (auto x) { return x > 21; });
I improved the rest of your program as well:
#include <algorithm>
#include <iostream>
#include <iterator>
#include <numeric>
#include <vector>
auto constexpr count = 8;
int main() {
std::vector<int> numbers(count);
std::cout << "Enter " << count << " integer values...\n";
std::copy_n(std::istream_iterator<int>(std::cin), numbers.size(), numbers.begin());
std::copy_if(numbers.begin(), numbers.end(),
std::ostream_iterator<int>(std::cout, "\n"),
[] (auto x) { return x > 21; });
auto sum = std::accumulate(numbers.begin(), numbers.end(), 0);
std::cout << "Sum: " << sum << '\n';
return 0;
}
See it live on Coliru!
Ok, I'm going to explain this to you and keep it simple. This loop
`for (int i = NUM_ELEMENTS - 1; i > 21; i--)`
will never execute because in your first iteration you are checking if (NUM_ELEMENTS-1=7)>21. You are then decrementing i so this will take the series (6,5,4,...) and nothing would ever happen here.
If you have to sum the numbers greater than 21, which I presume is what you need then you will have to remove the above loop and modify your second loop to:
for (i = 0; i < NUM_ELEMENTS; i++) {
if(userVals[i]>21)
sumVal = sumVal + userVals[i];
}
This way, you add the numbers in the array that are only greater than 21. The index of userVals is determined by the i variable which also acts as a counter.
You're on the right track. There's just a few things wrong with your approach.
#include <iostream>
#include <stdlib.h>
using namespace std;
int main() {
const int NUM_ELEMENTS = 8;
int userVals[NUM_ELEMENTS];
int i = 0;
int sumVal = 0;
int prntSel = 0;
int size = sizeof(userVals) / sizeof(int); // Get size of your array
// 32/4 = 8 (ints are 4 bytes)
cout << "Enter " << NUM_ELEMENTS << " integer values..." << endl;
for (i = 0; i < NUM_ELEMENTS; ++i) {
cin >> userVals[i];
}
for(int i = 0; i < size; i++) {
if(userVals[i] > 21) { // Is number > 21?
cout << userVals[i] << endl; // If so, print said number
exit(0); // And exit
}
else
sumVal += userVals[i]; // Else sum your values
}
cout << "Sum: " << sumVal << endl;
return 0;
}
#include <iostream>
using namespace std;
int main() {
const int NUM_ELEMENTS = 8; // Number of elements
int userVals[NUM_ELEMENTS]; // User numbers
int i = 0; // Loop index
int sumVal = 0; // For computing sum
int prntSel = 0; // For printing greater than 21
// Prompt user to populate array
cout << "Enter " << NUM_ELEMENTS << " integer values..." << endl;
for (i = 0; i < NUM_ELEMENTS; ++i) {
cin >> userVals[i];
}
// for (int i = NUM_ELEMENTS - 1; i > 21; i--)
// cout << "Value: " << sumVal << endl;
for( i = 0; i < NUM_ELEMENTS; ++i )
{
if( userVals[ i ] > 21 )
{
cout << "Value: " << i << " is " << userVals[ i ] << endl;
}
}
for (i = 0; i < NUM_ELEMENTS; ++i) {
sumVal = sumVal + userVals[i];
}
cout << "Sum: " << sumVal << endl;
return 0;
}
Try
for (int i = NUM_ELEMENTS - 1; i > 21; i--)
cout << "Value: " << sumVal << endl;
to
for (i = 0; i < NUM_ELEMENTS; ++i) {
if(userVals[i] > 21)
cout << "Value: " << userVals[i] << endl;
}
This line isnt needed as well, as you arent using it.
int prntSel = 0; // For printing greater than 21
for (int i = NUM_ELEMENTS - 1; i > 21; i--)
cout << "Value: " << sumVal << endl;
Here you are printing the value of sumVal, not the value of the array in the position i. The line should be:
cout << "Value: " << usersVals[i] << endl;
Also that that your for is not doing what you think it does. for doesn't use the condition you gave to decide if will execute the current iteration or not, it uses the condition to decide if the loop should continue or not. So when you put i > 21, means that it will continue running while i is bigger than 21. To achieve your goal, you should make a test (if statement) inside the loop.
The final result it would be:
for (i = 0; i < NUM_ELEMENTS; ++i) {
if (usersVals[i] > 21) {
cout << "Value: " << usersVals[i] << endl;
}
}
I am Having Problem with Passing a 2D array to a c++ Function. The function is supposed to print the value of 2D array. But getting errors.
In function void showAttributeUsage(int)
Invalid types for int(int) for array subscript.
I know the problem is with the syntax in which I am passing the particular array to function but I don't know how to have this particular problem solved.
Code:
#include <iostream>
using namespace std;
void showAttributeUsage(int);
int main()
{
int qN, aN;
cout << "Enter Number of Queries : ";
cin >> qN;
cout << "\nEnter Number of Attributes : ";
cin >> aN;
int attVal[qN][aN];
cout << "\nEnter Attribute Usage Values" << endl;
for(int n = 0; n < qN; n++) { //for looping in queries
cout << "\n\n***************** COLUMN " << n + 1 << " *******************\n\n";
for(int i = 0; i < aN; i++) { //for looping in Attributes
LOOP1:
cout << "Use(Q" << n + 1 << " , " << "A" << i + 1 << ") = ";
cin >> attVal[n][i];
cout << endl;
if((attVal[n][i] > 1) || (attVal[n][i] < 0)) {
cout << "\n\nTHE VALUE MUST BE 1 or 0 . Please Re-Enter The Values\n\n";
goto LOOP1; //if wrong input value
}
}
}
showAttributeUsage(attVal[qN][aN]);
cout << "\n\nYOUR ATTRIBUTE USAGE MATRIX IS\n\n";
getch();
return 0;
}
void showAttributeUsage(int att)
{
int n = 0, i = 0;
while(n != '\0') {
while(i != '\0') {
cout << att[n][i] << " ";
i++;
}
cout << endl;
n++;
}
}
I really suggest to use std::vector : live example
void showAttributeUsage(const std::vector<std::vector<int>>& att)
{
for (std::size_t n = 0; n != att.size(); ++n) {
for (std::size_t i = 0; i != att.size(); ++i) {
cout << att[n][i] << " ";
}
cout << endl;
}
}
And call it that way:
showAttributeUsage(attVal);
Looking at your code, I see no reason why you can't use std::vector.
First, your code uses a non-standard C++ extension, namely Variable Length Arrays (VLA). If your goal is to write standard C++ code, what you wrote is not valid standard C++.
Second, your initial attempt of passing an int is wrong, but if you were to use vector, your attempt at passing an int will look almost identical if you used vector.
#include <iostream>
#include <vector>
#include <algorithm>
#include <iterator>
typedef std::vector<int> IntArray;
typedef std::vector<IntArray> IntArray2D;
using namespace std;
void showAttributeUsage(const IntArray2D&);
int main()
{
int qN, aN;
cout << "Enter Number of Queries : ";
cin >> qN;
cout << "\nEnter Number of Attributes : ";
cin >> aN;
IntArray2D attVal(qN, IntArray(aN));
//... Input left out ...
showAttributeUsage(attVal);
return 0;
}
void showAttributeUsage(const IntArray2D& att)
{
for_each(att.begin(), att.end(),
[](const IntArray& ia) {std::copy(ia.begin(), ia.end(), ostream_iterator<int>(cout, " ")); cout << endl;});
}
I left out the input part of the code. The vector uses [] just like a regular array, so no code has to be rewritten once you declare the vector. You can use the code given to you in the other answer by molbdnilo for inputing the data (without using the goto).
Second, just to throw it into the mix, the showAttributeUsage function uses the copy algorithm to output the information. The for_each goes throw each row of the vector, calling std::copy for the row of elements. If you are using a C++11 compliant compiler, the above should compile.
You should declare the function like this.
void array_function(int m, int n, float a[m][n])
{
for (int i = 0; i < m; i++)
for (int j = 0; j < n; j++)
a[i][j] = 0.0;
}
where you pass in the dimensions of array.
This question has already been answered here. You need to use pointers or templates. Other solutions exists too.
In short do something like this:
template <size_t rows, size_t cols>
void showAttributeUsage(int (&array)[rows][cols])
{
for (size_t i = 0; i < rows; ++i)
{
std::cout << i << ": ";
for (size_t j = 0; j < cols; ++j)
std::cout << array[i][j] << '\t';
std::cout << std::endl;
}
}
You're using a compiler extension that lets you declare arrays with a size determined at runtime.
There is no way to pass a 2D array with such dimensions to a function, since all but one dimension for an array as a function parameter must be known at compile time.
You can use fixed dimensions and use the values read as limits that you pass to the function:
const int max_queries = 100;
const int max_attributes = 100;
void showAttributeUsage(int array[max_queries][max_attributes], int queries, int attributes);
int main()
{
int attVal[max_queries][max_attributes];
int qN = 0;
int aN = 0;
cout << "Enter Number of Queries (<= 100) : ";
cin >> qN;
cout << "\nEnter Number of Attributes (<= 100) : ";
cin >> aN;
cout << "\nEnter Attribute Usage Values" << endl;
for (int n = 0; n < qN; n++)
{
cout << "\n\n***************** COLUMN " << n + 1 <<" *******************\n\n";
for (int i = 0; i < aN; i++)
{
bool bad_input = true;
while (bad_input)
{
bad_input = false; // Assume that input will be correct this time.
cout << "Use(Q" << n + 1 << " , " << "A" << i + 1 << ") = ";
cin >> attVal[n][i];
cout << endl;
if (attVal[n][i] > 1 || attVal[n][i] < 0)
{
cout << "\n\nTHE VALUE MUST BE 1 or 0 . Please Re-Enter The Values\n\n";
bad_input = true;
}
}
}
}
cout << "\n\nYOUR ATTRIBUTE USAGE MATRIX IS\n\n";
showAttributeUsage(attVal, qN, aN);
getch();
return 0;
}
void showAttributeUsage(int att[max_queries][max_attributes], int queries, int attributes)
{
for (int i = 0; i < queries; i++)
{
for (int j = 0; j < attributes; j++)
{
cout << att[i][j] << " ";
}
cout << endl;
}
}
For comparison, the same program using std::vector, which is almost identical but with no size limitations:
void showAttributeUsage(vector<vector<int> > att);
int main()
{
cout << "Enter Number of Queries (<= 100) : ";
cin >> qN;
cout << "\nEnter Number of Attributes (<= 100) : ";
cin >> aN;
vector<vector<int> > attVal(qN, vector<int>(aN));
cout << "\nEnter Attribute Usage Values"<<endl;
for (int n = 0; n < qN; n++)
{
cout<<"\n\n***************** COLUMN "<<n+1<<" *******************\n\n";
for (int i = 0; i < aN; i++)
{
bool bad = true;
while (bad)
{
bad = false;
cout << "Use(Q" << n + 1 << " , " << "A" << i + 1 << ") = ";
cin >> attVal[n][i];
cout << endl;
if (attVal[n][i] > 1 || attVal[n][i] < 0)
{
cout << "\n\nTHE VALUE MUST BE 1 or 0 . Please Re-Enter The Values\n\n";
bad = true;
}
}
}
}
cout << "\n\nYOUR ATTRIBUTE USAGE MATRIX IS\n\n";
showAttributeUsage(attVal);
getch();
return 0;
}
void showAttributeUsage(vector<vector<int> > att);
{
for (int i = 0; i < att.size(); i++)
{
for (int j = 0; j < att[i].size(); j++)
{
cout << att[i][j] << " ";
}
cout << endl;
}
}
The Particular Logic worked for me. At last found it. :-)
int** create2dArray(int rows, int cols) {
int** array = new int*[rows];
for (int row=0; row<rows; row++) {
array[row] = new int[cols];
}
return array;
}
void delete2dArray(int **ar, int rows, int cols) {
for (int row=0; row<rows; row++) {
delete [] ar[row];
}
delete [] ar;
}
void loadDefault(int **ar, int rows, int cols) {
int a = 0;
for (int row=0; row<rows; row++) {
for (int col=0; col<cols; col++) {
ar[row][col] = a++;
}
}
}
void print(int **ar, int rows, int cols) {
for (int row=0; row<rows; row++) {
for (int col=0; col<cols; col++) {
cout << " | " << ar[row][col];
}
cout << " | " << endl;
}
}
int main () {
int rows = 0;
int cols = 0;
cout<<"ENTER NUMBER OF ROWS:\t";cin>>rows;
cout<<"\nENTER NUMBER OF COLUMNS:\t";cin>>cols;
cout<<"\n\n";
int** a = create2dArray(rows, cols);
loadDefault(a, rows, cols);
print(a, rows, cols);
delete2dArray(a, rows, cols);
getch();
return 0;
}
if its c++ then you can use a templete that would work with any number of dimensions
template<typename T>
void func(T& v)
{
// code here
}
int main()
{
int arr[][7] = {
{1,2,3,4,5,6,7},
{1,2,3,4,5,6,7}
};
func(arr);
char triplestring[][2][5] = {
{
"str1",
"str2"
},
{
"str3",
"str4"
}
};
func(triplestring);
return 0;
}