I know I'm missing something real simple but I can't seem to get the numbers to print out in rows of just odd or just even numbers using a while loop or loops. Also It keeps printing out "the even numbers are:"/ "the odd numbers are:" for every number.
#include<stdio.h>
#include <iostream>
using namespace std;
int main()
{
//declare variables
int number;
int n;
cout << "Enter value less than 100: ";
cin >> n; //take user input
while (n <= 100) //loop only if n equals 100 or less
{
for(number = n; number <= n; number++) //for loop to increment int value
{
if(number % 2 !=0) //determines if odd
{
cout << "The odd numbers are:" <<number << endl; //prints odd values
}
}
for(number = n;number <= n; number++) // for loop to increment int value
{
if(number % 2 ==0) //determines if even
{
cout <<"The even numbers are:" <<number <<endl; //prints even values
}
}
n++;
}
return 0; //end of program
}
You may want this:
#include <iostream>
using namespace std;
int main()
{
//declare variables
int number;
int n;
cout << "Enter value less than 100: ";
cin >> n; //take user input
// print odd values
cout << "The odd numbers are:";
for (number = n + 1 - (n % 2); number <= 100; number += 2)
{
cout << " " << number;
}
cout << endl;
// print even values
cout << "The even numbers are:";
for (number = n + (n % 2); number <= 100; number += 2)
{
cout << " " << number;
}
cout << endl;
return 0; //end of program
}
Related
#include <iostream>
using namespace std;
int main()
{
int n, G;
float num[500], sum=0.0, average,Grades;
cout << "Enter the numbers of data: ";
cin >> n;
while (n > 500 || n <= 0)
{
cout << "Error! number should in range of (1 to 500)." << endl;
cout << "Enter the number again: ";
cin >> n;
}
for(G = 0; G < n; ++G)
{
cout << G + 1 << ". Enter number: ";
cin >> num[G];
sum += num[G];
}
average = sum / n;
Grades = num[G] >= average;
cout<<endl;
cout << "Grades Average = " << average << endl;
cout << "Grades above or equal the Average : " <<Grades<< endl;
cout << "Number of grades above the Average = "<<(int) Grades;
return 0;
}
i coded this code but the Number of grades above the Average and Grades above or equal the Average don't work it just print 0
i tried to print the Grades >= the avg but it print 0
also num of Grades also print 0
where is the error ?
I think you was trying to do something like this:
...
int grades_on_avg, upper_grades = 0;
for(int i = 0; i < n; ++i)
{
cout << i + 1 << ". Enter number: ";
cin >> num[i];
sum += num[i];
}
average = sum / n;
for(int i = 0; i < n; ++i) // use separate for loop and redefined index
{
if(num[i] == average) // compare to average
grades_on_avg++;
else if(num[i] > average) // if bigger than average
upper_grades++;
}
cout<<endl;
cout << "Grades Average = " << average << endl;
cout << "Grades above or equal the Average =" << (grades_on_avg + upper_grades) << endl;
cout << "Number of grades above the Average = "<< upper_grades ;
You assign boolean value to Grades variable. Also, you refer to element outside of the array: G variable is equal to n after exiting for-loop, but max index you can use is n - 1 (basic programming rule). So, you should change your code into something like this:
...
int avgGrades{0};
int avgAboveGrades{0};
for(int i{0}; i < n; ++i)
{
if(num [i] == average)
{
++avgGrades;
}
else if(num [i] > average)
{
++avgAboveGrades;
}
}
If you prefer more elegant ways of doing so, you can use std::count_if() function but it's more tricky and requires knowledge about lambdas.
Is there some way to write a condition within a while loop that creates output if the user guesses a number that is within 10 units (plus or minus) from a random number generated by the program (integers)?
#include <iostream>
#include <ctime>
using namespace std;
int main()
{
srand ( time(NULL) );
bool valid;
int randNum;
int sum = 0;
int userNum;
for (int x = 1; x < 11; x++)
{
randNum = rand() % (71) + 7;
cout << "Random number " << x << ": " << randNum << endl;
sum = sum + randNum;
}
cout << "\nThe total of all the random numbers is " << sum << "\n\n";
cout << "Guess a number between 70 and 770: ";
do
{
cin >> userNum;
while(userNum >= 70 && userNum <= 770)
{
while(userNum == sum)
{
cout << "You win";
break;
}
while(/* the number given by the user is within 10 units from the random number generated by the program*/)
{
cout << "You almost won";
break;
}
break;
}
while(userNum < 70 || userNum > 770)
{
cout << "Try again.";
valid = false;
break;
}
}
while (!valid);
return 0;
}
You will have to #include <stdlib.h> then for the condition in your while loop you write abs(userNum - randNum) <= 10. This will give the magnitude of the difference between the userNum and randNum, which you want to be less than or equal to 10.
I'm writing a code that requires pentagonal numbers to be limited to ten per line, however I can't get it to work. My code is:
#include <iostream>
using namespace std;
int getPentagonalNumber(int n)
{
/*equation to calculate pentagonal numbers*/
return (n * (3 * n - 1) / 2);
}
int main()
{
/*Ask the user to put in the number of results*/
int userInput;
cout << "How many pentagonal numbers would you like to be displayed: ";
cin >> userInput;
cout << endl;
cout << "results are: " << endl;
/*Loop to generate the numbers for the equation*/
for (int n = 1; n <= userInput; n++)
{
cout << getPentagonalNumber(n) << " ";
}
return 0;
}
Does this do what you want:
#include <iostream>
using namespace std;
int getPentagonalNumber(int n)
{
/*equation to calculate pentagonal numbers*/
return (n * (3 * n - 1) / 2);
}
int main()
{
/*Ask the user to put in the number of results*/
int userInput;
cout << "How many pentagonal numbers would you like to be displayed: ";
cin >> userInput;
cout << endl;
cout << "results are: " << endl;
/*Loop to generate the numbers for the equation*/
for (int n = 1; n <= userInput; n++)
{
cout << getPentagonalNumber(n) << " ";
if (n % 10 == 0)
cout << endl;
}
return 0;
}
?
I added a new line output every time n is divisible by 10.
Looking for some advice here on what I'm getting wrong. Everything in my main should be fine and left unchanged. My problem is in my reverse function. It's printing the reversed number right before the cout statement of "The number is" instead down below where it should be. I spent awhile trying to fix but can't come up with a solution.
#include <iostream>
#include <iomanip>
#include <cstdlib>
#include <ctime>
using namespace std;
const int NUM_VALS = 10; //the maximum number of values to use
int reverse(int num);
bool isPrime(int num);
int main()
{
int number, //Holds the random number that is manipulated and tested
loopCnt; //Controls the loop
//set the seed value for the random number generator
//Note: a value of 1 will generate the same sequence of "random" numbers every
// time the program is executed
srand(1);
//Generate 10 random numbers to be manipulated and tested
for( loopCnt = 1; loopCnt <= NUM_VALS; loopCnt++ )
{
//Get a random number
number = rand();
//Display the sum of adding up the digits in the random number, the reversed
//random number, and whether or not the number is palindromic or a prime number
cout << "The number is " << number << endl
<< "----------------------------------------" << endl
// << "Adding the digits result" << setw(16) << sumDigits( number ) << endl
<< "Reversing the digits result" << setw(13) << reverse(number) << endl
// << "Is the number a palindrome?" << setw(13) << (isPalindrome(number)? "Yes" : "No") << endl
// << "Is the number prime?" << setw(20) << (isPrime(number)? "Yes" : "No") << endl
<< endl << endl;
}
return 0;
}
int reverse(int num)
{
int quo, rem;
quo = num;
while (quo != 0)
{
rem = quo % 10;
cout << rem;
quo /= 10;
}
}
bool isPrime(int num)
{
int i;
if (num % 2 == 0)
return false;
for (i = 3; i*i <= num; i+=2)
{
if (num % i == 0)
return false;
}
return true;
}
You need to have your reverse function return the number as reversed, because the return value is used in main.
You can build the reversed number by multiplying a "reversed" value by 10, then adding in the remainder:
int reverse(int num)
{
int reversed = 0;
int quo, rem;
quo = num;
while (quo != 0)
{
rem = quo % 10;
reversed = reversed * 10 + rem;
quo /= 10;
}
return reversed;
}
You can also use this method to reverse a number by taking string input and then reverse it and convert it to int.
#include <iostream>
#include<string>
using namespace std;
int reverse_num(string a)
{
string s;
for(int i=a.length()-1;i>=0;i--)
{
s+=a[i];
}
int n;
n=stoi(s);
return n;
}
int main()
{
string a;
cin>> a;
cout<<reverse_num(a);
return 0;
}
I have problem running my loops.
I have to run a program where user enter 4 digit number, and it will show how many zero appear. This program will run depends on how many times user want it to run. so at the beginning I prompt user to enter the number of times the program will run, then the actual program will run in For loop. but so far, I can only run it once. Can someone help me? Thank you. Here is my code
#include <iostream>
using namespace std;
int main()
{
int numberTimes;
cout << "How many times do you want to run this check?\n";
cin >> numberTimes;
for (int counter = 0; counter < numberTimes; counter++);
{
int positiveInteger;
//prompt user to enter a positive integer
cout << "Please enter a positive integer value.\n";
cin >> positiveInteger;
//conditional statement
while((positiveInteger <=0) || (positiveInteger > 9999))
{
cout << "Invalid Value!!! Please try again.\n";
cout << "Please enter a positive integer value.\n";
cin >> positiveInteger;
}
cout << "Processing the value " << positiveInteger << ".\n";
int zeroCount = 0;
int firstNumber = positiveInteger%10; //separate the first number
if (firstNumber == 0) //determine if the first digit is zero
{
zeroCount = zeroCount + 1;
}
int digitOne = positiveInteger/10; //omitted first digit number
int secondNumber = digitOne%10; //separate the second number
if (secondNumber == 0) //determine if the second digit is zero
{
zeroCount = zeroCount + 1;
}
int digitTwo = digitOne/10; //omitted the second number
int thirdNumber = digitTwo%10; //separate the third number
if (thirdNumber == 0) //determine if the third digit is zero
{
zeroCount = zeroCount + 1;
}
int digitThree = digitTwo/10; //omitted the third number
int fourthNumber = digitThree%10; //separate the fourth number
if (fourthNumber == 0) //determine if the fourth digit is zero
{
zeroCount = zeroCount + 1;
}
cout << "Your first digit number is " << firstNumber << ".\n";
cout << "Your second digit number is " << secondNumber << ".\n";
cout << "Your third digit number is " << thirdNumber << ".\n";
cout << "Your fourth digit number is " << fourthNumber << ".\n";
cout << "Number of zero appear in your integer is " << zeroCount << ".\n";
if (zeroCount % 2 == 0) //determine if the number is even or odd
{
cout << "Your number zero appear even times.\n";
} else
{
cout << "Your number zero appear odd times.\n";
}
}
cout << "You have run this program " << numberTimes << ".\n";
cout << "Thank you and good bye.";
return 0;
}
The problem is using ; at the end of for line.
for (int counter = 0; counter < numberTimes; counter++);
In such a case that you used, it iterate the loop but do nothing.
In the other word,it is equal to the below program now :
for (int counter = 0; counter < numberTimes; counter++)
{
}
You can also use this program : (Add complementary lines)
#include <iostream>
using namespace std;
int main()
{
int positiveInteger;
int numberTimes;
int digit;
cout << "How many times do you want to run this check?\n";
cin >> numberTimes;
while(numberTimes)
{
int zeroRepitation=0;
cout << "Please enter a positive integer value.\n";
cin >> positiveInteger;
if ((positiveInteger <=0) || (positiveInteger > 9999))
{
cout << "Invalid Value!!! Try again!\n";
continue;
}
for (int i=1;i<5;i++)
{
digit = positiveInteger % 10;
if (digit=0)
{
++zeroRepitation;
}
positiveInteger = positiveInteger / 10;
}
cout<<"Number of zeros in this number= "<<zeroRepitation;
--numberTimes;
}
You put a semicolon at the end of the for statement. This:
for (int counter = 0; counter < numberTimes; counter++);
should be this:
for (int counter = 0; counter < numberTimes; counter++)