I have response body which contains
"<h3 class="panel-title">Welcome
First Last </h3>"
I want to fetch 'First Last' as a output
The regular expression I have tried are
"Welcome(\s*([A-Za-z]+))(\s*([A-Za-z]+))"
"Welcome \s*([A-Za-z]+)\s*([A-Za-z]+)"
But not able to get the result. If I remove the newline and take it as
"<h3 class="panel-title">Welcome First Last </h3>" it is detecting in online regex maker.
I suspect your problem is the carriage return between "Welcome" and the user name. If you use the "single-line mode" flag (?s) in your regex, it will ignore newlines. Try these:
(?s)Welcome(\s*([A-Za-z]+))(\s*([A-Za-z]+))
(?s)Welcome \s*([A-Za-z]+)\s*([A-Za-z]+)
(this works in jMeter and any other java or php based regex, but not in javascript. In the comments on the question you say you're using javascript and also jMeter - if it is a jMeter question, then this will help. if javaScript, try one of the other answers)
Well, usually I don't recommend regex for this kind of work. DOM manipulation plays at its best.
but you can use following regex to yank text:
/(?:<h3.*?>)([^<]+)(?:<\/h3>)/i
See demo at https://regex101.com/r/wA2sZ9/1
This will extract First and Last names including extra spacing. I'm sure you can easily deal with spaces.
In jmeter reg exp extractor you can use:
<h3 class="panel-title">Welcome(.*?)</h3>
Then take value using $1$.
In the data you shown welcome is followed by enter.If actually its part of response then you have to use \n.
<h3 class="panel-title">Welcome\n(.*?)</h3>
Otherwise above one is enough.
First verify this in jmeter using regular expression tester of response body.
Welcome([\s\S]+?)<
Try this, it will definitely work.
Regular expressions are greedy by default, try this
Welcome\s*([A-Za-z]+)\s*([A-Za-z]+)
Groups 1 and 2 contain your data
Check it here
Related
I'm trying to create a custom filter in Google Analytic to remove the query parts of the url which I don't want to see. The url has the following structure
[domain]/?p=899:2000:15018702722302::NO:::
I would like to create a regex which skips the first 12 characters (that is until:/?p=899:2000), and what ever is going to be after that replace it with nothing.
So I made this one: https://regex101.com/r/Xgbfqz/1 (which could be simplified to .{0,12}) , but I actually would like to skip those and only let the regex match whatever is going to be after that, so that I'll be able to tell in Google Analytics to replace it with "".
The part in the url that is always the same is
?p=[3numbers]:[0-4numbers]
Thank you
Your regular expression:
\/\?p=\d{3}\:\d{0,4}(.*)
Tested in Golang RegEx 2 and RegEx101
It search for /p=###:[optional:####] and capture the rest of the right side string.
(extra) JavaScript:
paragraf='[domain]/?p=899:2000:15018702722302::NO:::'
var regex= /\/\?p=\d{3}\:\d{0,4}(.*)/;
var match = regex.exec(paragraf);
alert('The rest of the right side of the string: ' + match[1]);
Easily use "[domain]/?p=899:2000:15018702722302::NO:::".substr(12)
You can try this:
/\?p\=\d{3}:\d{0,4}
Which matches just this: ?p=[3numbers]:[0-4numbers]
Not sure about replacing though.
https://regex101.com/r/Xgbfqz/1
I use a jmeter for REST testing.
I have made a HTTP Request, and this is the response data:
{"id":11,"name":"value","password":null,"status":"ACTIVE","lastIp":"0.0.0.0","lastLogin":null,"addedDate":1429090984000}
I need just the ID (which is 11) in
{"id":11,....
I use the REGEX below :
([0-9].+?)
It works perfectly but it will be a problem if my ID more than 2 digits. I need to change the REGEX to :
([0-9][0-9].+?)
Is there any dynamic REGEX for my problem. Thank you for your attention.
Regards,
Stefio
If you want any integer between {"id": and , use the following Regular Expression:
{"id":(\d+),
However the smarter way of dealing with JSON data could be JSON Path Extractor (available via JMeter Plugins), going forward this option can be much easier to use against complex JSON.
See Using the XPath Extractor in JMeter guide (scroll down to "Parsing JSON") to learn more on syntax and use cases.
I suggest using the following regular expression:
"id":([^,]*),
This will first find "id": and then look for anything that is not a comma until it finds a comma. Note the character grouping is only around the value of the ID.
This will work for ANY length ID.
Edit:
The same concept works for almost any JSON data, for example where the value is quoted:
"key":"([^"]*)"
That regular expression will extract the value from given key, as long as value is quoted and does not contain quotes. It first finds "key": and then matches anything that is not a quote until the next quote.
You can use the quantifier like this:
([0-9]{2,}.+?)
It will catch 2 or more digits, and then any symbol, 1 or more times. If you want to allow no other characters after the digits, use * instead of +:
([0-9]{2,}.*?)
Regex demo
I've searched around quite a bit now, but I can't get any suggestions to work in my situation. I've seen success with negative lookahead or lookaround, but I really don't understand it.
I wish to use RegExp to find URLs in blocks of text but ignore them when quoted. While not perfect yet I have the following to find URLs:
(https?\://)?(\w+\.)+\w{2,}(:[0-9])?\/?((/?\w+)+)?(\.\w+)?
I want it to match the following:
www.test.com:50/stuff
http://player.vimeo.com/video/63317960
odd.name.amazone.com/pizza
But not match:
"www.test.com:50/stuff
http://plAyerz.vimeo.com/video/63317960"
"odd.name.amazone.com/pizza"
Edit:
To clarify, I could be passing a full paragraph of text through the expression. Sample paragraph of what I'd like below:
I would like the following link to be found www.example.com. However this link should be ignored "www.example.com". It would be nice, but not required, to have "www.example.com and www.example.com" ignored as well.
A sample of a different one I have working below. language is php:
$articleEntry = "Hey guys! Check out this cool video on Vimeo: player.vimeo.com/video/63317960";
$pattern = array('/\n+/', '/(https?\:\/\/)?(player\.vimeo\.com\/video\/[0-9]+)/');
$replace = array('<br/><br/>',
'<iframe src="http://$2?color=40cc20" width="500" height="281" frameborder="0" webkitAllowFullScreen mozallowfullscreen allowFullScreen></iframe>');
$articleEntry = preg_replace($pattern,$replace,$articleEntry);
The result of the above will replace any new lines "\n" with a double break "" and will embed the Vimeo video by replacing the Vimeo address with an iframe and link.
I've found a solution!
(?=(([^"]+"){2})*[^"]*$)((https?:\/\/)?(\w+\.)+\w{2,}(:[0-9]+)?((\/\w+)+(\.\w+)?)?\/?)
The first part from (? to *$) what makes it work for me. I found this as an answer in java Regex - split but ignore text inside quotes? by https://stackoverflow.com/users/548225/anubhava
While I had read that question before, I had overlooked his answer because it wasn't the one that "solved" the question. I just changed the single quote to double quote and it works out for me.
add ^ and $ to your regex
^(https?\://)?(\w+\.)+\w{2,}(:[0-9])?\/?((/?\w+)+)?(\.\w+)?$
please notice you might need to escape the slashes after http (meaning https?\:\/\/)
update
if you want it to be case sensitive, you shouldn't use \w but [a-z]. the \w contains all letters and numbers, so you should be careful while using it.
I am trying to extract javascript code from HTML content that I receive via CFHTTP request.
I have this simple regex that catches everyting as long as there is no linebreak in the code between the tags.
var result=REMatch("<script[^>]*>(.*?)</script>",html);
This will catch:
<script>testtesttest</script<
but not
<script>
testtest
</script>
I have tried to use (?m) for multiline, but it doesn't work like that.
I am using the reference to figure it out but I am just not getting it with regex.
Heads up, normally there would be javascript between the script tags, not simple text so also characters like {}();:-_ etc.
Can anyone help me out?
Cheers
[[UPDATE]]
Thanks guys, I will try the solutions. I favor regex because but I will look into the HTML Parser too.
(?m) multiline mode is for making ^ and $ match on line breaks (not just start/end of string as is default), but what you're trying to do here is make . include newlines - for that you want (?s) (dot-all mode).
However, I probably wouldn't do this with regex - a HTML parser is a more robust solution. Here's how to do it with jSoup:
var result = jsoup.parse(html).select('script').text();
More details on using jSoup in CF are available here, or alternatively you can use the TagSoup parser, which ships with CF10 (so you don't need to worry about jars/etc).
If you really want regex, then you can use this:
var result = rematch('<script[^>]*>(?:[^<]+|<(?!/script>))+',html);
Unlike using (?s).*? this avoids matching empty blocks (but it will still fail in certain edge cases - if accuracy is required use a HTML parser).
To extract just the text from the first script block, you can strip the script tag with this:
result = ListRest( result[1] , '>' );
You can use dot matches all mode or replace . with [\s\S] to get the same effect.
<script[^>]*>[\s\S]*?</script> would match everything including newlines.
I'm trying to use a custom regex clean transformation (information found here ) to extract a post code from a mixed address column (Address3) and move it to a new column (Post Code)
Example of incoming data:
Address3: "London W12 9LZ"
Incoming data could be any combination of place names with a post code at the start, middle or end (or not at all).
Desired outcome:
Address3: "London"
Post Code: "W12 9LZ"
Essentially, in plain english, "move (not copy) any post code found from address3 into Post Code".
My regex skills aren't brilliant but I've managed to get as far as extracting the post code and getting it into its own column using the following regex, matching from Address3 and replacing into Post Code:
Match Expression:
(?<stringOUT>([A-PR-UWYZa-pr-uwyz]([0-9]{1,2}|([A-HK-Ya-hk-y][0-9]|[A-HK-Ya-hk-y][0-9] ([0-9]|[ABEHMNPRV-Yabehmnprv-y]))|[0-9][A-HJKS-UWa-hjks-uw])\ {0,1}[0-9][ABD-HJLNP-UW-Zabd-hjlnp-uw-z]{2}|([Gg][Ii][Rr]\ 0[Aa][Aa])|([Ss][Aa][Nn]\ {0,1}[Tt][Aa]1)|([Bb][Ff][Pp][Oo]\ {0,1}([Cc]\/[Oo]\ )?[0-9]{1,4})|(([Aa][Ss][Cc][Nn]|[Bb][Bb][Nn][Dd]|[BFSbfs][Ii][Qq][Qq]|[Pp][Cc][Rr][Nn]|[Ss][Tt][Hh][Ll]|[Tt][Dd][Cc][Uu]|[Tt][Kk][Cc][Aa])\ {0,1}1[Zz][Zz])))
Replace Expression:
${stringOUT}
So this leaves me with:
Address3: "London W12 9LZ"
Post Code: "W12 9LZ"
My next thought is to keep the above match/replace, then add another to match anything that doesn't match the above regex. I think it might be a negative lookahead but I can't seem to make it work.
I'm using SSIS 2008 R2 and I think the regex clean transformation uses .net regex implementation.
Thanks.
Just solved this. As usual, it was simpler logic than I thought it should be. Instead of trying to match the non-post code strings and replace them with themselves, I have added another line matching the postcode again and replacing it with "".
So in total, I have:
Match the post code using the above regex and move it to the Post Code column
Match the post code using the above regex and replace it with "" in the Address3 column